1.

Calculate the energy equivalent of 1 a.m.u. in `MeV`

Answer» form `E=mc^2`,
when `m=1 a.m.u. =1.66xx10^(-27)kg`
`E=(1.66xx10^(-27))(3xx10^8)^2 "jouls"`
`=(1.66xx9xx10^(-11))/(1.6xx10^(-13)) MeV=933.75MeV`


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