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Calculate packing fraction of alpha particle form the following date: `m_(alpha)=4.0028a.m.u., m_(p)=1.00758a.m.u. , and m_(n)=1.00897 a.m.u.`

Answer» Correct Answer - `7.58xx10^(-3)a.m.u.//N`
An alpha particle contains two protons and two neutrons.
Mass excess, `Deltam=2m_(p)+2m_(n)-m_(alpha)`
`=2xx1.00785+2xx1.00897-4.0028`
`=0.0303 a.m.u`
Packing fraction `=(Deltam)/A=0.0303/4`
`=7.58xx10^(-3)a.m.u//N`


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