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Calculate and compare the energy released by (a) fusion of 1.0kg of hydrogen deep within the sun, and (b) the fission of 1.0kg of `U^(235)` in a fission reactor. |
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Answer» In sun, four hydrogen nuclie fuse to form a helium nucleus with the release of 26MeV energy. `:.` Energy released by fusion of 1kg of hydrogen `=(6xx10^(23)xx10^3)/4xx26MeV` `E_1=39xx10^(26)MeV` As energy released in fission of one atom of `._(92)U^(235)=200MeV`, `:.` Energy released by fusion of 1kg of `._(92)U^(235)=(6xx10^(23)xx10^3)/235xx200 MeV` `E_2=5.1xx10^(26)MeV` `(E_1)/(E_2)=(39xx10^(26))/(5.1xx10^(26))=7.65`, i.e. energy released in fusion is 7.65 times the energy released in fission. |
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