1.

Calculate and compare the energy released by (a) fusion of 1.0kg of hydrogen deep within the sun, and (b) the fission of 1.0kg of `U^(235)` in a fission reactor.

Answer» In sun, four hydrogen nuclie fuse to form a helium nucleus with the release of 26MeV energy.
`:.` Energy released by fusion of 1kg of hydrogen `=(6xx10^(23)xx10^3)/4xx26MeV`
`E_1=39xx10^(26)MeV`
As energy released in fission of one atom of `._(92)U^(235)=200MeV`,
`:.` Energy released by fusion of 1kg of `._(92)U^(235)=(6xx10^(23)xx10^3)/235xx200 MeV`
`E_2=5.1xx10^(26)MeV`
`(E_1)/(E_2)=(39xx10^(26))/(5.1xx10^(26))=7.65`, i.e. energy released in fusion is 7.65 times the energy released in fission.


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