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`(C_(0)+C_(1))(C_(1)+C_(2))(C_(2)+C_(3))....(C_(n-1)+C_(n))=` |
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Answer» स्पष्ट है कि `C_(0) + C_(1) = 1 + n` `C_(1)+C_(2)=n+(n(n-1))/(2)=n(n+1))/(2)=C_(1)(n+1)/(2)` `C_(2)+C_(3)=(n(n-1))/(2.1)+(n(n-1)(n-2))/(3.2.1)` `=(n(n-1))/(2).(n+1)/(3)=C_(2)(n+1)/(3)` इत्यादि । अत: अभीष्ट गुणनफल `= (1+n).C_(1)(1+n)/(2).C_(2)(1+n)/(3).......n` गुणखंडो तक `=(1+n)^(n) (C_(1)C_(2)......C_(n))/(1.2.3.....n)` `=(1+n)^(n) (C_(1)C_(2).....C_(n))/(n!)` |
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