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Arrange the following reducing agents in the order of increasing strength under standard state condition. Justify the answer. `{:("Element",Al(s),Cu(s),Cl(aq),Ni(s)),(E^(@),-1.66V,0.34V,1.36V,-0.26V):}` |
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Answer» Given `Delta=-110kJ` `DeltaS=40JK^(-1)` ltbr? `=0.04kjK^(-1)` Temperature, `T=4000K` `DeltaG=?` Since `DeltaH` is -ve, the reaction is exothermic `DeltaG=DeltaH-TDeltaS` `=-110-400xx0*04` `=-110-16` `=-126kJ` Since, `DeltaG` is negative, the reaction is spontaneous and exothermic. (b) Given `DeltaH=40kJ`, `Delta=-120JK^(-1)` `=-0*12kJK^(-1)` Temperature, `T=250K` `DeltaG=?` Since `DeltaH` is + ve reaction is endothermic `DeltaG=DeltaH-T.DeltaS` `=40-250xx(0*12)` `=40+30` `=70kJ`. Sice `DeltaGgt0`, the reaction is non-spontaneous. `DeltaG=70kJ`, The reaction is endothermic and non-spontaneous. |
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