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A circular coil of 300 turns and average area `5xx10^(-3)m^(2)` carries a current of 15 A. Calculater the magnitude of magnetic moment associated with coil. |
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Answer» Given : no. of turns, N = 300, area, `A=5xx10^(-3)m^(-2)`, Current, `I=15A` The magnetic moment of the coil, M=NIA `=300xx15xx5xx10^(-3)` `M=22*5"Am"^2`. |
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