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A particale in S.H.M. has a perod of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position. |
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Answer» Given : A = 10 cm, T = 2 sec. ltbngt Acceleration, `a=omega^2((2pi)/T)^2x,` `=(2xx22/7xx1/2)"^2,x` Practicle is 4 cm from its positive exterme position. `x=A-4` `=10-4=6cm ` `a=(2xx22/7xx1/2)^2*6` `a=(22xx22)/(49)xx6=2904)/49` `a=59.29`m//s^2` |
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