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An electron is accelerated through a potential difference of `200` volts. If `e//m` for the electron be `1.6 xx 10^(11)` coulomb/kg, the velocity acquired by the electron will beA. `8xx10^(6)ms^(-1)`B. `8xx10^(5)ms^(-1)`C. `5.9xx10^(6) ms^(-1)`D. `5.9xx10^(5) ms^(-1)` |
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Answer» Correct Answer - A `(1)/(2)mv^(2)=eV` or `v+sqrt((2eV)/(m))=sqrt(2xx1.6xx10^(11)xx200)ms^(-1)=8xx10^(6)ms^(-1)` |
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