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A system absorbs 640 J heat and does work of 260 J, the change in internal energy of the system will be :A. `+380J`B. `-380J`C. `+900J`D. `-900J` |
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Answer» Correct Answer - B The system has been given internal energy of 640 J and the work system does on surroundings is 260 J. Therefore, by first law of thermodynamics the internal energy of system increases by `-q=DeltaU-W=(-640+260)=-360J` |
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