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A sample of a radioactive element has a mass of `10 g` at an instant `t=0`. The approxiamte mass of this element in the sample after two mean lives is .A. `1.35g`B. `2.50g`C. `3.70g`D. `6.30g` |
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Answer» Correct Answer - A `t=2tau=2xx1.44T=2.88T` As `N/(N_(0))=m/(m_(0)) =(1/2)^(t//T)=(1/2)^(2.38)` `:. m=m_(0)(1/2)^(2.88)=10(1/2)^(2.88)g` `=10xx0.135g=1.35g` |
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