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A random variable X has the following probability distribution : (a) Find k (b) Find P (O |
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Answer» (a) `K+3K+5K+7K+9K+11K+13K=1` `therefore" "49K=1` `therefore" "K=(1)/(49)` (b) `P(0 lt x lt 4)=P(1)+P(2)+P(3)` `=(3)/(49)+(10)/(49)+(21)/(49)` `=(34)/(49)` (c) `c.d.f = (2x+1)K,, 0 le x` |
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