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A radioactive sample contains 2.2 mg of pure `._6C^(11)` , which has a half life period of 1224s. Calculate (i) number of atoms present initially. (ii) the activity when `5 mu g` of the sample will be left. |
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Answer» Correct Answer - `1.2xx10^(20); 1.55xx10^(14)` disintegration/sec Here, number atoms present in 11 gram of sampel `=6.023xx10^(23)` `:.` No. of atoms present in 2.2 mg of sample initially `N_(0)=(6.023xx10^(23)xx2.2xx10^(-3))/11=1.2xx10^(20)` No. of atoms present in `5 mug` `N=(6.023xx10^(23)xx5xx10^(-6))/11=2.74xx10^(17)` Activity of the sample `A=lambdaN=0.693/TN=(0.693xx2.74xx10^(17))/1224` `A=1.55xx10^(14)` disintegration/sec. |
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