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A radioactive element decays to `1//32th` of its initial activity in 25 decay. Calculate its half life. |
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Answer» Here, `A/(A_0)=1/32, t= 25 days` `T=?` As `A/(A_0)=N/(N_0)=(1/2)^n=1/32 :. n=5` As `T=t/n :. T=25/5=5 days` |
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