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A proton when accelerated through a potential difference of V volt has a wavelength `lamda` associated with it. An alpha-particle in order to have the same `lamda` must be accelerated through a potential difference ofA. V voltB. 4V voldC. 2 V voltD. `((V)/(8))` volt |
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Answer» Correct Answer - D `lamda_P=lamda_alpha` or `(h)/(sqrt(2m_pQ_pV))=(h)/(sqrt(2m_alphaQ_alphaV_alpha))` `m__pQ_pV_p=m_alphaQ_alphaV_alpha` `V_alpha=((m_p)/(m_alpha))((Q_p)/(Q_alpha))V=((1)/(4))((1)/(2))V=(V)/(8)` |
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