A proton has kinetic energy `E = 100 keV` which is equal to that of a photon . The wavelength of photon is `lambda_(2)`and that of proton is `lambda_(1)` .The ratio of `lambda_(2) // lambda_(1) ` is proportional toA. `E^2`B. `E^((-1)/(2))`C. `E^-1`D. `E^((1)/(2))`

A proton has kinetic energy `E = 100 keV` which is equal to that of a

1.	A proton has kinetic energy `E = 100 keV` which is equal to that of a photon . The wavelength of photon is `lambda_(2)`and that of proton is `lambda_(1)` .The ratio of `lambda_(2) // lambda_(1) ` is proportional toA. `E^2`B. `E^((-1)/(2))`C. `E^-1`D. `E^((1)/(2))`
Answer» Correct Answer - B For photon: `E=hv` or `E=(hv)/(lamda)` `implieslamda_2=(hc)/(E)` For proton: `E=(1)/(2)m_pv_p^2` `E=(1)/(2)(m_p^2v_p^2)/(m)impliesP=sqrt(2mE)` `P=(h)/(lamda_1)` `implieslamda_1=(h)/(p)=(h)/(sqrt(2mE))` `(h_2)/(lamda_1)=(hc)/(Exx(h)/(sqrt(2mE)))propE^((-1)/(2))`

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