Saved Bookmarks
| 1. |
A praticle of mass M at rest decays into two particle of masses `m_1` and `m_2`, having non-zero velocities. The ratio of the de Broglie wavelength of the particles `(lamda_1)/(lamda_2)` isA. `(m_1)/(m_2)`B. `(m_2)/(m_1)`C. 1D. `(sqrtm_2)/(sqrtm_1)` |
|
Answer» Correct Answer - C Applying consevation of linear momentum: Initial momentum `=` Final momentum `0=m_1v_1-m_2v_2impliesm_1v_1=m_2v_2` Now, `(lamda_1)/(lamda_2)=((h)/(m_1v_1))/((h)/(m_2v_2))=1` |
|