1.

A praticle of mass M at rest decays into two particle of masses `m_1` and `m_2`, having non-zero velocities. The ratio of the de Broglie wavelength of the particles `(lamda_1)/(lamda_2)` isA. `(m_1)/(m_2)`B. `(m_2)/(m_1)`C. 1D. `(sqrtm_2)/(sqrtm_1)`

Answer» Correct Answer - C
Applying consevation of linear momentum:
Initial momentum `=` Final momentum
`0=m_1v_1-m_2v_2impliesm_1v_1=m_2v_2`
Now, `(lamda_1)/(lamda_2)=((h)/(m_1v_1))/((h)/(m_2v_2))=1`


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