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A nucleus `._n^ m X` emits one `alpha-`particle and two `beta-`particles. The resulting nucleus isA. `._(n-4)^(m-6)Z`B. `._(n)^(m-6)Z`C. `._(n)^(m-4)X`D. `._(n-2)^(m-4)Z` |
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Answer» Correct Answer - C When an alpha particle `(._(2)He^(4))` is emitted, the mass number and atomic number of dougther nucleus decreases by four and two respectively. When a `beta` particle `(._(-1)e^(0))` is emitted, the mass number of product remains unchanged, but the atomic number increases by one. Therefore, `._(n)X^(m)` overset (alpha)to `._(n-2)X^(m-4) overset (2beta)to._(n)X^(m-4)` |
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