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A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value, then the maximum KE of emitted photoelectrons will become.A. `((1)/(16))`th of original valueB. unchangedC. twice the original valueD. four times the original value |
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Answer» Correct Answer - B Maximum KE depends on the frequency of incident radiation, not on intensity. |
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