A material particle with a rest mass `m_o` is moving with a velocity of light c. Then, the wavelength of the de Broglie wave associated with it isA. `((h)/(m_oc))`B. zeroC. `infty`D. `((m_oc)/(h))`

A material particle with a rest mass `m_o` is moving with a velocity o

1.	A material particle with a rest mass `m_o` is moving with a velocity of light c. Then, the wavelength of the de Broglie wave associated with it isA. `((h)/(m_oc))`B. zeroC. `infty`D. `((m_oc)/(h))`
Answer» Correct Answer - B We know that mass m in motion and the rest mass `m_0` is related through the equation `m=(m_0)/(sqrt(1-(v^2)/(c^2)))` As `v=c`,`m=(m_0)/(sqrt(1-1)=(m_0)/(0)=infty` Therefore, de Broglie wavelength is `lamda=(h)/(mv)=(h)/((infty)(c ))=0`

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A material particle with a rest mass `m_o` is moving with a velocity of light c. Then, the wavelength of the de Broglie wave associated with it isA. `((h)/(m_oc))`B. zeroC. `infty`D. `((m_oc)/(h))`

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