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A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom transits form the upper level to the lower level. |
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Answer» Here, `E=2.3 eV =2.3xx 1.6xx10^(-19)J.` As `E=hv= :. v=E/h=(2.3xx1.6xx10^(-19))/(6.6xx10^(-34))=5.6xx10^(14)Hz` |
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