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`(1-x)^(-4)` में विस्तार में (r+1)वाँ पद हैA. `(x^(r))/(r!)`B. `((r+1)(r+2)(r+3))/(6) x^(r)`C. `((r+2)(r+3))/(2)x^(r)`D. इनमें से कोई नहीं |
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Answer» Correct Answer - B `T_(r+1)` `=([(-4)(-4-1)(-4-2)...(-4-r+3)(-4-r+2).(-4-r+1)])/(r!)(-x)^(r)` `=(4.5.6.7...r(r+1)(r+2)(r+3))/(r!).x^(r)` `=(4.5.6.7...r(r+1)(r+2)(r+3))/(1.2.3...(r-1)r).x^(r)` `=((r+1)(r+2)(r+3))/(1.2.3).x^(r)` `=((r+1)(r+2)(r+3))/(6).x^(r)` |
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