This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
(a) A person listens to a source of sound of frequency `350 Hz` standing at a distance of `500 m`. What is the time interval between successive rarefactions from the source ? (b) What is meant by the term lithotripsy ? |
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Answer» (a) Time interval between two successive rarefactions `= T = (1)/(v) = (1)/(350) s`. The distance of `500 m` has no significance. (b) Lithotripsy is the technique of breaking gallstones or kidney stones using ultrasounds. (In greek, lithotripsy means stone breaking). |
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| 602. |
A stationary source produces a note of frequency 350 Hz. An observer in a car moving towards the source measures the frequency of sound as 370 Hz. Find the speed of the car. What will be the frequency of sound as measured by the observer in the car if the car moves away from the source at the same speed?(Assume speed of sound = 340 m/s) |
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Answer» Given: n0 = 350 Hz, v = 340 m/s, nA = 370 Hz To find: Speed (vL), Frequency (nA) Formulae: i. When the car moves towards the stationary source then, nA = n0 \((\frac{v+v_s}{v})\) ii. When the car moves away from the stationary source then, nA = n0 \((\frac{v-v_L}{v})\) Calculation: From formula (i), 370 = 350 \((\frac{340+v_L}{340})\) ∴ 359.43 =340 + vL ∴ vL = 19.43 m/s From formula (ii), ∴ nA = 350 \((\frac{340-20}{340})\) = \(\frac{35}{34}\) × 320 ∴ nA = 329.41 Hz |
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| 603. |
From the above diagrams ‘A’ and ‘C’, which one has more amplitude? A) A B) C C) Both A and C D) Neither ‘A’ nor ‘C’ |
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Answer» Correct option is B) C |
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| 604. |
From the above diagrams, which one has more wavelength? A) A B) B C) C D)D |
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Answer» Correct option is D) D |
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| 605. |
The speed of sound in air on a summer day is `350 m//s`. What is the air temperature ? |
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Answer» Speed of sound in air at `0^@ C = 331 m//s` Speed of sound in air at `t^@ C = 350 m//s` Change in speed of sound with `t^@ C` change in temperature `= 350 m//s - 331 m//s = 19 m//s`. Since speed of sound increases by `0.6 m//s` for `1^@ C` increse in temperature, temperature `(t^@ C)` of air `= ((19 m//s)/(0.60 m//s)) .^@C = 31.7^@ C`. This is an approximate method of relating speed of sound with temperature. The exact relation between speed of sound (v) and T (temperature in degrees kelvin) is `v prop sqrt(T)` You will learn this in Class (XI). |
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| 606. |
Guitar is an instrument of ……… type. A) drum instrument B) fringed instrument C) stringed instrument D) none of these |
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Answer» Correct option is C) stringed instrument |
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| 607. |
………… is the important organ in the human body to produce sound. A) Ear B) Larynx C) Nose D) Muscles |
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Answer» Correct option is B) Larynx |
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| 608. |
What is sound? How does sound produces? |
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Answer» Sound is a form of energy. A vibrating body produces sound. |
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| 609. |
Honeybee produce peculiar sound through their mouth or some other organ used for that purpose? |
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Answer» A honeybee can’t make a sound using vocal cords. The buzzing sound that you b*ear from any flying insect is caused by vibration of their wings when flying. |
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| 610. |
Frequency is expressed in ……….. (a) hertz (b) meter (c) Kilogram (d) second |
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Answer» Frequency is expressed in hertz |
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| 611. |
The time taken for one complete vibration is called its …… (a) loudness (b) pitch (C) time period (d) frequency |
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Answer» (c) time period |
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| 612. |
………….. instruments produce a specific sound when they are struck, scrapped or clashed together. (a) Reed (b) Stringed (c) Percussion (d) None |
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Answer» (c) Percussion |
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| 613. |
Vibrations in a body produce …….. (a) pressure (b) sound (c) density (d) current |
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Answer» Vibrations in a body produce sound |
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| 614. |
Which of the following are the characteristics of vibrations? (i) Frequency (ii) Time period(iii) Pitch (a) (i) and (ii) (b) (ii) and (iii) (c) (iii) and (iv) (d) (i) and (iv)(iv) Loudness |
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Answer» (c) (iii) and (iv) |
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| 615. |
What are vibrations? |
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Answer» Vibration means a kind of rapid to and fro motion of an object. |
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| 616. |
Choose the correct option:(a) Both assertion and reason are true and reason is the correct explanation of assertion. (b) Both assertion and reason are true but reason is not the correct explanation of assertion. (c) Assertion is true but reason is false. (d) Assertion is false but reason is true. (e) Both Assertion and reason are false.Assertion: Two persons on the surface of moon cannot talk to each other.Reason: There is no atmosphere on moon. |
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Answer» (a) Both assertion and reason are true and reason is the correct explanation of assertion. |
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| 617. |
Write true of false for the following statements: The wavelength of 5 MHz ultrasound in a medium where the velocity is 1540 ms-1 is 0.3 mm. |
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Answer» False Explanation: wavelength of ultrasound = 5 MHz velocity of ultrasound = 1540 ms-1 Then, for sound wave Velocity (u) = Wavelength (λ) \(\times\) frequency(f) ⇒ frequency(f) = \(\frac{velocity}{wavelength}\) = \(\frac{1540}{5 \times 10^6}\) = 3.08 \(\times\) 10-4m =0.03 mm |
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| 618. |
Say whether the following statements given below are true or false.If false, rewrite it by making necessary changes.a. Sound cannot travel through vacuum. b. When frequency of sound increases, pitch decreases. |
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Answer» a. correct b. false, when frequency decreases pitch decreases |
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| 619. |
‘Bats can catch prey even in the dark’. Do you agree with this statement? Explain your inference. |
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Answer» Agree. Bats can produce and hear ultrasonic waves. The sound they produced reflects by hitting on objects. The bats can analyze the returning sounds. |
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| 620. |
How do human beings contribute to noise pollution? |
Answer»
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| 621. |
A girl hears an echo of her own voice from a distant tall building after 2s. What is the distance of the girl from the building? |
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Answer» t = 2s, ν = 332 m/s, s = ? Required distance s = \(\frac{vt}{2}\) = \(\frac{332\times 2}{2}\) = 332m |
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| 622. |
Write true of false for the following statements: The minimum distance between a source and the reflector of sound should be 34 m. |
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Answer» False Explanation: The total distance covered by the sound from the point of generation and reflecting surface and back should be at least (344 m/s) x0.1 s = 34.4 m. Thus, the minimum distance between point of generation and reflecting surface should be half of it i.e. 17.2 m. |
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| 623. |
Define the term frequency |
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Answer» The number of vibrations produced by a vibrating body in one second is called frequency |
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| 624. |
What do you understand by the term echo? |
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Answer» The repetition of the sound, which is reflected from a high building or any such object is called an echo. |
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| 625. |
Write true of false for the following statements: Sound waves travel faster in air than in water. |
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Answer» False Explanation: The speed of sound decreases as we go from solid to the gaseous state. Thus, sound travels faster in water than in air. |
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| 626. |
The extension in a string obeying Hooke’s law is x. The speed of transverse waves in the stretched string is v. If the extension in the string is increased to 1.5x, the speed of transverse waves in it will be (a) 1.22v (b) 0.61v (c) 1.5v (d) 0.75v |
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Answer» Correct Answer is: (a) 1.22v Tension ∝ extension, and speed ∝ √tension. |
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| 627. |
A cylindrical resonance tube, open at both ends, has a fundamental frequency F in air. Half of the length of the tube is dipped vertically in water. The fundamental frequency of the air column now is (a) 4F (b) 2F(c) F (d) F/2 |
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Answer» Correct Answer is: (c) F |
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| 628. |
Write any two slogans to reduce sound pollution. |
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Answer» Slogans to reduce sound pollution: 1. The more you make noise. The faster you lose your voice. 2. Noise an evil. You help doing it, it gives you a reward making you a deaf. |
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| 629. |
Write true of false for the following statements: Sound travels faster at a higher temperature than at a lower temperature. |
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Answer» True Explanation: The speed of sound depends on the properties of a medium. It travels faster at a higher temperature than at a lower temperature. |
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| 630. |
What can be done along the roads to reduce noise pollution caused by traffic from reaching the residents of the area? |
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Answer» The following measures which can be taken to reduce noise pollution caused by traffic from reaching the residents of the area: 1. The residential area must be declared as no use of horns. 2. The colonies must be established at a distance than the roads. |
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| 631. |
List four ways of reducing noise pollution. |
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Answer» Ways of reducing noise pollution : 1. Factories should be located far away from residential areas. 2. Heavy vehicles should not be allowed in residential areas. 3. At homes T.V. radio, power music system, should played at a low volume. 4. Machines should be designed in such a way, so that they produce minimum noise. |
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| 632. |
State the condition for the occurrence of resonance. |
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Answer» Condition for resonance: Resonance occurs when the frequency of the applied force is exactly equal to the natural frequency of the vibrating body. |
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| 633. |
Write your suggestions about reducing sound pollution. |
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Answer» 1. Attach silencers to bikes and other machines to reduce sounds. 2. Manufacture machines that work with less noise. 3. During the use of TV and tape recorder tune down volume of sound. 4. Plant trees to reduce sound pollution. 5. Community laws must. Silence zones near school/colleges, hospitals, etc. 6. Noise producing industries, airports, bus and transport terminals and railway stations to sighted far from living places. |
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| 634. |
What travels faster : a radio signal or sound in air ? |
| Answer» A radio signals travels with the speed of light which is `3 xx 10^8 m//s`. On the other hand, sound travels in air with a speed of about `340 m//s`. Roughly speaking, a radio signal travels `(3 xx 10^8 m//s)//(340 m//s) ~~ 10^6`, i.e., a million times faster than sound in air. | |
| 635. |
Complete the following sentence:Resonance is a special case of …………….. vibrations, when frequency of the driving force is ……… natural frequency of the body. |
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Answer» Resonance is a special case of forced vibrations, when frequency of the driving force is equal to the natural frequency of the body. |
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| 636. |
List four harmful effects of sound pollution. |
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Answer» Harmful effects of sound pollution : 1. Noise produces headaches, irritatibility and nervous tension. 2. A long exposure to noise pollution may result in the loss of hearing to deafness. 3. Noise in the surroundings interferes with the conversation with another. 4. It causes anger, tension and interferer with the sleep pattern of individuals |
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| 637. |
Complete the table.No of vibrationstimeFrequency10….. a ….2153…… b …..……. c …..54 |
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Answer» Completed table:
a. 5 b. 5 c. 20 |
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| 638. |
Deaf people can be made to dance to music. Explain how ? |
| Answer» If there is nothing wrong with the interval ear, deaf prople can listen to music. This can be made possible by placing on end of a rod on a piano (or any other musical instrument) in such a way that it does not obstruct playing upon it. The other end of the rod can be gripped in the teeth. The music would reach the auditory nerve via rod and bones of the head. | |
| 639. |
How does sound pollution effects bio – diversity? Explain. |
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Answer» Slogans to reduce sound pollution: 1. The more you make noise. The faster you lose your voice. 2. Noise an evil. You help doing it, it gives you a reward making you a deaf. Effects of sound pollution on biodiversity: 1. The first harmful effect is loss of hearing. 2. It also leads to several health related problems, e.g: Sleeplessness, hypertension, increase in blood pressure, etc. 3. It effects the mental health of people. 4. In animals, noise can increase the risk of death by altering predator or prey detection and avoidance, interfere with reproduction and navigation and contribute to permanent hearing loss. 5. Noise pollution causes poor quality of crops. 6. Under water animals such as whales and dolphins too experience discomfort due to noise pollution caused by submarines, shipping companies and sonars. Cuttle fish and octopus suffer serious damage from noise pollution. |
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| 640. |
What are the problem faced by deaf people? |
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Answer» The people having damage to hereby birth effect many difficulties for communication, for ability to speak, vulnerability to danger, etc. |
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| 641. |
What are the demerits of sound pollution? |
Answer»
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| 642. |
Write the ways to reduce sound pollution. |
Answer»
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| 643. |
Can we hear the sound from Galton whistle having a frequency of 30000Hz? Why? |
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Answer» No. We cannot hear the sound having a frequency greater than 20000Hz |
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| 644. |
Write any two uses of ultrasonic sound. |
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Answer» 1. It is extensively used in medical applications like sonogram. 2. It is also employed in dishwashers. |
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| 645. |
Write two uses of ultrasonic sound. |
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Answer» Use in SONAR To find out the disease and treatment in medical field |
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| 646. |
A key of mechanical piano is first struck gently and then struck again but much harder this time. In the second case:A. second will be lounder but pitch will not be differentB. sound will be lounder and the pitch will also be higherC. sound will be lounder but pitch will be lowerD. both loundness and pitch will remain unaffected |
| Answer» Correct Answer - A | |
| 647. |
A key of mechanical piano is first struck gently and then struck again but much harder this time. In the second case: A. sound will be louder but pitch will not be different B. sound will be louder and the pitch will also be higher C. sound will be louder but pitch will be lower D. both loudness and pitch will remain unaffected |
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Answer» A. sound will be louder but pitch will not be different In the second case sound will be louder but pitch will not be different. |
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| 648. |
What is sound barrier ? |
| Answer» The barrier of sound waves in front of an object approaching the speed of sound is called sound barrier. | |
| 649. |
What propagates along with the waves ? |
| Answer» Waves transport energy and not matter from one region to the other. | |
| 650. |
You drop a stone from rest into a well that is `7.35 m` deep. How long does it take before you the splash ? |
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Answer» Time for the stone to drop, `t_1 = sqrt((2h)/(g)) = sqrt((2(7.35))/(9.8)) s = 1.22 s` Time for sound to travel a distance h, i.e., `t_2 = (h)/(v) = (7.35 m)/(344 m//s) = 0.0214 s` (as speed of sound in water `= 344 m//s` ) Total time, `t = t_1 + t_2 = 1.22 s + 0.0214 s = 1.24 s`. |
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