Saved Bookmarks
| 1. |
You drop a stone from rest into a well that is `7.35 m` deep. How long does it take before you the splash ? |
|
Answer» Time for the stone to drop, `t_1 = sqrt((2h)/(g)) = sqrt((2(7.35))/(9.8)) s = 1.22 s` Time for sound to travel a distance h, i.e., `t_2 = (h)/(v) = (7.35 m)/(344 m//s) = 0.0214 s` (as speed of sound in water `= 344 m//s` ) Total time, `t = t_1 + t_2 = 1.22 s + 0.0214 s = 1.24 s`. |
|