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IN ORDER to PREVENT SHORT CIRCUIT

tion:object's height, h_0h 0 = 4cmobject distance , u = -15cmfocal length of convex LENS , f = +5cmusing lens maker formula,1/v - 1/u = 1/for, 1/v - 1/-15 = 1/5or, 1/v = 1/5 - 1/15 = 2/15or, v = 15/2 = +7.5 cmas IMAGE distance is positive, image is real and it is located at 7.5cm behind the lens ( right side).magnification, m = v/u = height of image /height of object.or, (+7.5)/(-15cm) = height of image/(4cm)or, height of image = -2CM < height of objecthence, image is real and diminished.see diagram , which shows image position, NATURE and size.

Uses of concave mirrorsConcave mirrors are used in reflecting TELESCOPES. They are also used to PROVIDE a magnified image of the FACE for applying make-up or shaving.Explanation:plzzzzz mark me brainliest and LIKE

If TWO INDIVIDUAL forces are of EQUAL magnitude and opposite direction, then the forces are said to be balanced. An object is said to be ACTED upon by an UNBALANCED force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

S.I UNIT of MOMENTUM is KG m/s

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Answer is A.As the VALUE of sin 180 degrees is 0, the FORCE exerted on a current-carrying wire PLACED in a magnetic field is ZERO when the angle between the wire and the DIRECTION of magnetic field is 180 degrees.

Resistivity, commonly symbolized by the Greek letter RHO, ρ, is quantitatively equal to the resistance R of a SPECIMEN such as a wire, multiplied by its cross-sectional area A, and DIVIDED by its length L; ρ = RA/l. The unit of resistance is the ohm.Explanation:and plz follow me

tion:A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can DEFORM spacetime to form a black hole.please Mark me as a BRAINLIST ANSWER CLICK on mark as brainlist answer

24 km/hExplanation:Let distance between A and B is DThen, time TAKEN by motorcyclist with uniform speed 30 km/h ,T₁ = distance/speed = D/30 hrsAgain, they return with uniform speed 20 km , so time taken by motorcyclist , T₂ = D/20 hrsNow, AVERAGE speed of motorcyclist = total distance/total time taken= (D + D )/(D/30 + D/20) km/h= 2 × 30 × 20/(30 + 20) km/h= 24 km/hHope it will help you .......... Please MARK me as brainliest...........

d VELOCITY or speedExplanation:basically ENERGY DEPENDS these FACTORS and aslo vibrationally.

tion:P 1 V 1 = T 2 P 2 V 2 Here, P 1 =750−12=738mm,V 1 =28CM 3 ,T 1 =14+273=287K,P 2 =760mm,T 2 =273KThen, V 2 = 287×760738×28×273 =25.9cm 3Hope it helpsplzzz mark as BRAINLIEST ✌️ ✌️✌️✌️

ANSWERV∝P a ρ b From the relation, using dimensional ANALYSIS,Dimension of LHS= Dimension of RHS∴LT −1 =[ML −1 T −2 ] a [ML −3 ] b ⇒LT −1 =M a+b L −a−3b T −2a Comparing LHS and RHS,a+b=0−a−3b=1−2a=−1On solving the equations, a= 21 & b= 21 ∴V∝P 21 ρ − 21 ⇒V∝ ρp PLS FOLLOW me i will follow back

-25 is your ANSWEREXPLANATION:Please thanks me and mark me as brainlist.Please it is my humble request.

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refers to how tightly the string is stretched. Tightening the string gives it a higher FREQUENCY while loosening it LOWERS the frequency. When string PLAYERS tighten or LOOSEN their strings, they are altering the pitches to make them in tune. The density of a string will also AFFECT its frequency.

(meter/second)

ven:-since MASS ∝V a d b G c ⇒M=kV a d b g c Equating dimensions.[M ′ ]=K[L 1 T −1 ] a [ML −3 ] b [L 1 T −2 ] c ⇒ on comparing:-b=1,a−3b+c=0⇒a+c=3......(1)and −a−2c=0......(2)on SOLVING:-c=−3 and a=6∴M=k g 3 V 6 d ∴ Mass ∝ sixth Power of Velocity Hope it helpsplzzz mark as brainliest ✌️ ✌️✌️✌️

tion: HI bro it's easy........ As we know, THE AREA UNDER V-T GRAPH GIVES THE MAGNITUDE OF DISPLACEMENT/ DISTANCE. Let's mark the first triangle in the graph as 1st. base = 4-0 = 4 units height = 2-0 = 2 units So, Area of 1st triangle = 1/2bh = 1/2×8 = 4units Similarly, Area of 2nd triangle in DOWNWARD graph will be equal to 1 unit. Now, we will find area of that square, i.e. side x side = 1 unit. Now simply add all areas...... 4+1+1 = 6units.THEREFORE YOUR ANSWER IS, DISPLACEMENT = 6 meters hope it helped you. pls mark it brainliest

:Given -Mass = 5 kgSpeed = 2 m/sTo Find -Kinetic energy ?Solution -Kinetic Energy = ½mv²Now, Calculating Kinetic energy :⇒ ½*5*(2)²⇒ 5*2⇒ 10 JHence, Kinetic energy of the BODY is 10 J.Some ADDITIONAL Information -Energy possessed by a body DUE to change in position of SHAPE is called potential energy.Energy possessed by a body due to change in MOTION is called Kinetic energy.PE = mghKE = ½mv²

it can be EXPRESSES as 360000cm

Gauss's law STATES that the net FLUX of an electric field in a CLOSED surface is directly PROPORTIONAL to the enclosed electric charge. ... Yet another statement of Gauss's law states that the net flux of a given electric field through a given surface, divided by the enclosed charge should be equal to a constant.pls mark as the BRAINLIST

Given :  q=10 C             t=5 s ∴ Electric CURRENT       I= t q=  5 10 ​   =2 AEXPLANATION:

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the TWO TYPES of convex LENS arebiconvex lensconcavo convex lensExplanation:hope it HELPS youplzz mark me as ur BRAINLIAST

ke=1\2mv2Explanation:ke1\ke2=m1\m2m1\m2=2;3

it depends on the force = MASS × acceleration PLS FOLLOW me and I will follow you back

itudeD) GraphHope this ANSWER HELP you

teHere is your ans:-Explanation:(i) Position of image is 12 cm in FRONT of mirror. (II) SIZE of image is -1 cm.SolutionHere we have :-● Height of object (h_0) = 5 cm.● Distance of object (u) = -60 cm.● Focal length (f) = -10 cm.We will use mirror FORMULA :-● 1/f = 1/v + 1/u⇒ 1/-10 = 1/v + 1/(-60)⇒ 1/-10 = 1/v - 1/60⇒ 1/v = 1/60 - 1/10⇒ 1/v = (1 - 6)/60⇒ 1/v = -5/60⇒ 1/v = -1/12⇒ -v = 12⇒ v = -12 cmSo, position of image is 12 cm in front of mirror.Now we will use magnification formula :-● m = h_i/h_o = -v/u⇒ h_i/5 = -(-12)/-60⇒ h_i/5 = 12/-60⇒ h_i/5 = 1/-5⇒ -5h_i = 5⇒ h_i = 5/-5⇒ h_i = -1 cmSo, size of image is -1 cm.I hope this will help you❤️❤️

a PERSON sitting in the moving car watching outsideExplanation:the MOTION is called RELATIVE motion because REST and motion are related to each other

0= (12)^2–2gh( h is the HEIGHT the stone will RISE before start of FALL.) t = 12/10sec ( time to rise above 30.4m.). Total height to fall 30.4+7.2,=37.6 m.Explanation:here's the answer please FOLLOW me

Explanation:PLS FIND the ATTACHMENT where is T 5 IN THE QUESTION??

’ is a vector quantity that can be described as a push or pull on an OBJECT.......Laws of motion are :- These laws are as follows:• Newton’s FIRST Law of Motion also known as Law of Inertia states that every object persists to stay in uniform motion in a straight line or in the state of rest unless an external force acts upon it.• Newton’s Second Law of Motion states that force is equal to the change in momentum PER change in time. For a constant mass, force equals mass times acceleration, i.e. F = m*a. Learn about the Acceleration in detail here.• Newton’s THIRD Law of Motion states that for every action there is an equal and opposite reaction.

bit of juggling of the question first i did the first part then i did the third part and then the second part. In the first part the effective resistance between A and B will be 11R/4 as the current will not go in C and D BRANCH it will directly go from A to B firstly all three central resistances are in series and their sum will be 3R then 3R will be in parallel with R then their sum will be 3R/4 and then all three i.e. R , 3R/4 , R will be in series and their sum will be 11R/4. Same is for the effective resistance between A and C . In the third part between A and D there are 4 resistances in which 2 of them are series and other 2 are also in series and their sum will be 2R and both these 2Rs are in parallel and their sum is R and all three resistances i.e. R,R,R are in series and their sum is 3R .The SOLUTION is in the attachment.

our answerSee the ATTACHED FILE.

geometrical optics, a focus, ALSO CALLED an image point, is the point where light rays originating from a point on the object converge. ALTHOUGH the focus is conceptually a point, physically the focus has a spatial extent, called the blur circle... Pls follow me and have a nice day.. ❤️