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6. An object 5 cm high is placed at a distance 60 cm in front of a concave mirror of focal length 10 cm. Find (i) the position and (ii) size, of the image. Ans. (i) 12 cm in front of the mirror, (ii) 1 cm |
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Answer» teHere is your ans:-Explanation:(i) Position of image is 12 cm in FRONT of mirror. (II) SIZE of image is -1 cm.SolutionHere we have :-● Height of object (h_0) = 5 cm.● Distance of object (u) = -60 cm.● Focal length (f) = -10 cm.We will use mirror FORMULA :-● 1/f = 1/v + 1/u⇒ 1/-10 = 1/v + 1/(-60)⇒ 1/-10 = 1/v - 1/60⇒ 1/v = 1/60 - 1/10⇒ 1/v = (1 - 6)/60⇒ 1/v = -5/60⇒ 1/v = -1/12⇒ -v = 12⇒ v = -12 cmSo, position of image is 12 cm in front of mirror.Now we will use magnification formula :-● m = h_i/h_o = -v/u⇒ h_i/5 = -(-12)/-60⇒ h_i/5 = 12/-60⇒ h_i/5 = 1/-5⇒ -5h_i = 5⇒ h_i = 5/-5⇒ h_i = -1 cmSo, size of image is -1 cm.I hope this will help you❤️❤️ |
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