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Projectile motion is a form of motionexperienced by an OBJECT or particle (a projectile) that is thrown near the EARTH's surface and moves along a curved path under the ACTION of gravity only (in particular, the effects of AIR resistance are assumed to be NEGLIGIBLE).

When we PUSH our DOOR then due to TORQUE door moves
here force is not zero

Acceleration of train , a = 20cm/s² = 0.2 m/s²
DECELERATION , d = - 100cm/s² =- 1 m/s²

Let the train start with acceleration for xkm or, 1000X m distances and deceleration for (2700 - 1000x) m [ I just change (2.7 - x) km into metre.]

so, equation of distance travelled by train in 1ST CASE :- when we assume train start from rest then, intial velocity, u = 0
use formula, v² = u² + 2aS
v² = 0 + 2 × 0.2 × 1000x = 400x ----(1)

equation of distance travelled by train in 2nd case :- intial velocity in this case = final velocity of 1st case = v.finally train will be rest .
so, final velocity in this case = 0
deceleration = d and distance is S' = (2700-1000x) m
so, 0 = v² + 2(-1) × (2700-1000x)
v² = 5400 - 2000x -----(2)

solve equations (1) and (2),
5400 - 2000x = 400x
=> 5400 = 2400x
=> x = 54/24 = 9/4 km

so, v² = 400 × 9/4 = 900
v = 30 m/s
now, use formula v = u + at
30 = 0 + 0.2t
t = 150 sec

again, time TAKEN in 2nd case
0 = 30 + (-1)t => t = 30 sec

hence, total time taken = 180 sec

Yes,Of course we can find the solution of energy problems using renewable energy SOURCES by many ways.They are all around us in unlimited quantity
RENEWABLE RESOURCES-Resoruces which are FOUND in nature everywhere and get exhausted but get rejenuvate by a lot of means and are eco-friendly are called renewable resoruces.
FOR EXAMPLE- Sun,wind,wateretc.

Types of Renewable energy.
(NOTE-I am not mentioning only 5,they may be more)

1.SOLAR ENERGY- Energy which we get from the rays of sun is called solar energy.
2.WIND ENERGY- Enery which we are generating from wind by using windmills is called wind energy.
3.HYDRAL ENERGY- Energy which we generate from water by building dams is called Hydral energy.
4.TIDAL ENERGY- Energy which we get from the force of tides is called tidal energy.
5.BIO ENERGY- Energy which we generate by decomposition animal DUNG and NATURAL waste is called bio energy.

So,these all energy sources we are getting from nature and are TOTALLY safe to consume.
Unlike those non-renewable resources,they do not produce any type of pollution and dont got exhaust.
We all should discourage the use of petroleum,kerosene etc. and should use CNG,Bio gas and energy produces from renewable resources and keep our Earth safe,healthy,clean and fine.

HOPE THIS WILL HELPFULL TO YOU.



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YOUR WELCOME.

It is CENTRIPETAL FORCE.

RESULTING DISPLACEMENT =

√6^2+8^2+10^2

= 10√2 m.

Vehicle DESIGNED for speed as in racing car have a very low center of gravity because its HEIGHT is KEPT SMALL

HEY
HERE IS YOUR ANSWER
====================================
WE KNOW THAT
FORCE OF FRICTION=COEFFICIENT*NORMAL REACTION
ALSO,
NORMAL REACTION=mg
normal reaction=10*9.8=98
now
19.6=coefficient of friction*98
COEFFICIENT OF FRICTION=0.2
====================================
HOPE IT WILL HELP
PLEASE MARK IT AS BRAINLIEST

Let intial velocity is u = 0 , acceleration is a.
time taken to COVER distance S.
use formula, S = UT + 1/2 at²
S = 1/2 at² ----(1)
and FINAL velocity , v = u + at = 0 + at
e.g., v = at -----(2)

now, sign of acceleration changes . but for some distance body MOVE same direction untill it becomes rest.
so, final velocity in this case , v = 0
INITIAL velocity , u = at [ because final velocity of 1st case is considered initial velocity of 2nd case.]
use formula, v = u + at
0 = at + (-a)t' => t' = t
so, S' = ut' + 1/2(-a)t'²
S'= at² -1/2at² = 1/2at² ------(3)

now, body moves opposite direction and comes to intial point.
so, initial velocity in this case, u = 0
and acceleration = a
use formula, S" = ut" + 1/2at"²
S + S' = 1/2at² + 1/2at² = 0 1/2at"²
at² = 1/2at"² => t" = √2t

so, total time = t + t' + t"
= t + t + √2t = (2 + √2)t

At the end of the 5TH SEC its velocity is 1.5 m/s
let intial velocity is u and acceleration is a
e.g., 1.5 = u + 5a ----(1)
at the end of 6th body stops.
e.g., 0 = u + 6a -----(2)

from equations (1) and (2),
1.5 = -6a + 5a => a = -1.5 m/s²
now, put a in equation (1),
1.5 = u + 5 × (-1.5)
u = 1.5 + 7.5 = 9 m/s

distance travelled by the body before it stop
v² = u² + 2aS
0 = 9² + 2(-1.5)S
S = 81/3 =27 m
now, velocity at 'O' is v
use formula, v² = u² + 2aS
v² = 0² + 2(1.5) × 27
v² = 2 × 1.5 × 27 = 81
v = 9m/s
hence, velocity of body to return at 'O' is -9m/s

Here MASS of ALPHA PARTICLE = 4× mass of PROTON

R=rl/a so if l=l/2&a=2a thenR=16/4=4ohms

V=u+at

since u=0

v=at

and t=v/a

in such CASE a=\frac{\ALPHA+\BETA}{\alpha*\beta} [/TEX]

so v=(alpha=beta)*t/alpha*beta

When the processor is working on many tasks at the same time ,it will start to heat.if the temperature GOES up to 50C the processor will automatically shut down and restart.dont over TASK your MOBILE and turn off HOTSPOT

NET force on one SIDE will be 2Fcos30

2 * 10^-6 * 10^-6 * 9 * 10^9/(10 * 10^-2)^2 X √3/2

1.8 * √3/2

0.9*√3

1.53

Stars twinkle seems to be twinkling because of refractive index .there are MANY spheres in our atmosphere which have DIFFERENT different density and when star light comes in these SPHERE it BENDS to wards the normal so that we think that stars are twinkling

This is a problem in physics RELATING to projectile motion. While not exactly what the problem is, we can use a formula for calculating the angle θ to hit coordinate (x,y) as a good start.

Please refer to the attached image for the full formula as it is quite long and complex to write in text.

This formula computes the angle θ of launch to hit a target at range x  and altitude y when FIRED from (0,0) and with initial speed v.

Also, the g in the formula refers to the gravitational acceleration constant = 9.8m/s^2.

The coordinate (0,0) simply refers to the start position.

Plug in the values for each of the variables:

x = 24 (the DISTANCE from start of launch to the obstacle in meters)

y = 14 (the height of the obstacle in meters)

v = 24 (the initial speed of the projectile in m/s)

g = 9.8 (gravity constant)

The computation can be quite long.

Note how the formula contains "±" or plus-minus symbol. This  means that there are two POSSIBLE answers. Depending on which one you use, you will get two different angles.

If there aren't any computation errors, you will get the angles 44.6 degrees and 75.7 degrees (rounded to the nearest tenths).

This means that you can launch the projectile at those angles to HIT the top of the obstacle. This is what I meant when I said the formula is not quite the final solution. In order for the projectile to pass OVER the obstacle, we need to know it's size and shape. For example, if it's a ball with a radius of 1m, then we just simply adjust our values such that y = 14m + 1m or y = 15m. Redo the computation using the adjusted value for y and you will get the new angles. When launched at those angles, our imaginary ball's skin will ever so slightly touch the top obstacle and pass over it.

This computation DOES NOT yet take into ACCOUNT air resistance and friction. However, since the problem did not provide information on those, it's safe to ignore them just for learning's sake.

it is newton's LAW stating that MOMENTUM of system is CONSTANT unless no EXTERNAL force is ACTING on that particular system

To Prove ⇒

Proof ⇒

LET US consider that the object is MOVING with the initial velocity U and have the uniform acceleration of a. Then the displacement in the nth second will be given by,

∵

∴

⇒

⇒

Hence PROVED.

Hope it helps.

Ø=1°54'=114'=(114×60)"=114×60×4.85×10^-6 rad = 3.32×10^-2 rad
Basis, b=AB=1.276×10^7 m
So, the distance of the MOON from the EARTH,
S= b/ø =(1.276×10^7)÷(3.32×10-2)= 3.84×10^8 (ans)

80/2 km/hr + 40/2 km/hr = 120/2 km/hr ≈ 60 km/hr

یھھھھھھھھھھھھھھاکاھسکسھسیسجناجاجاجاجۃکاججاجسھسھجسبدھد

What we have to FIND in this QUESTION ... PLS COMPLETE your question

It will COVER 20 KM as
4/2 is CURRENT acceleration
4*5/2*5
=20/10

This is UR ANSWER.....

For a p TYPE CONDUCTOR germanium should be doped with ELECTRON defiecient group i e boron

@skb

ANSWER is 90km/h.

i HOPED its HELPED

Distance=velocity*time=50*1200=60000m=60km

The UNIT of ENERGY is EITHER WH or KWH.

The sprinter will cover 3 and a half rounds...
total DISTANCE covered = PERIMETER × rounds
= 628 × 3.5
= 2198 m
displacement = diameter = 200m
pls mark brainliest....
cheers !!

R = n^2 R
2^2 . 20
4 . 20
=80
new resistance = 80 OHM