A car starts from rest and travels with uniform acceleration 'α' for

1.	A car starts from rest and travels with uniform acceleration 'α' for some time and then with uniform retardation 'β' and comes to rest. The time of motion is 't' . Find the maximum velocity attained by it.(αβt/(α+β))
Answer» V=u+at since u=0 v=at and t=v/a in such CASE a=\frac{\ALPHA+\BETA}{\alpha\beta} [/TEX] so v=(alpha=beta)t/alpha*beta

A car starts from rest and travels with uniform acceleration 'α' for some time and then with uniform retardation 'β' and comes to rest. The time of motion is 't' . Find the maximum velocity attained by it.(αβt/(α+β))

Answer»

V=u+at

since u=0

v=at

and t=v/a

in such CASE a=\frac{\ALPHA+\BETA}{\alpha*\beta} [/TEX]

so v=(alpha=beta)*t/alpha*beta

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A car starts from rest and travels with uniform acceleration 'α' for some time and then with uniform retardation 'β' and comes to rest. The time of motion is 't' . Find the maximum velocity attained by it.(αβt/(α+β))

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