Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is columb law ?give it three characteristics

Answer»

Answer:

CHARGE is a basic property of MATTER. ... According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one ANOTHER, while a POSITIVE charge ATTRACTS a negative charge.

Hope it helps

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2.

Plz help me in this physics question​

Answer»

Explanation:

IDK. CAN U GIVE QUE. IN MORE DETAIL.

3.

An object travel 30m in 4 seconds and then another​

Answer»

Answer:

Ask full question and TELL what you WANT in that question.

4.

Friction is a neccessary evil. Why?

Answer»

Friction is a necessary evil because it has both advantages and disadvantages.

Here are some of them...

Friction is necessity

(1) It is DUE to friction between the ground and the feet that we are able to walk.

(2) The brakes of a vehicle cannot work without friction.

(3) Various parts of a machine are able to rotate because of friction between belt and pulley.

(4) The tyres of vehicles are made rough to increase friction.

(5) Nails and screws join various wooden parts due to friction.

(6) In the absence of friction it will not be possible to write on paper with a pen or pencil.

Friction is an evil:

(1) Wear and tear of machinery is due to friction.

(2) A large amount of power is wasted in overcoming friction and the efficiency of the machines DECREASE considerably.

(3) Excessive friction between ROTATING parts of a machine producers enough heat and causes damage to the machinery.

Hope this helps you

Brainly Stars.

5.

Why does the sun appears round at sunrise and sunset but flatten at noon?​

Answer»

Answer

At sunrise and sunset, the sun is near the horizon. The rays of light from the upper part and lower part of the periphery of the sun BEND UNEQUALLY on TRAVELLING through earth's atmosphere. That is why the sun appears oval or flattened at the time of sunrise and sunset.At NOON, the sun is overhead. The rays of light from the sun enter earth's atmosphere normally. Therefore, they suffer no refraction or bending on passing through earth's atmosphere. Hence the sun appears CIRCULAR at noon.

6.

Derive the relation between for the variation of density of a solid with temperature​

Answer»

Answer:

When a given MASS of a solid or LIQUID is heated its volume increases. ACCORDINGLY the density of a solid or a liquid decreases on HEATING. With INCREASE in temperature, volume increases,so density decreases and vise_versa.

7.

The physical quantity which has dimensional formula as that of energy/mass×length

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ANSWER:

The physical quantity which has DIMENSIONAL formula as that of Energy/mass x LENGTH is. Force. POWER.

8.

Two body of masses 1g and 16g are moving with equal K.E .Find the ratio of the magnitudes of their linear momentum

Answer»

P=1/\sqrt{2mKE}

P∝1/√m

P1/P2=\sqrt{m2/m1}

P1/P2=4/1

9.

A mixture of hydrogen and oxygen (45 ml) is sparked to form liquid water. The component nom excessreacts completely and 15 ml is left over. (All measurements are made at the same temperature and pressure).The composition by volume in the original mixture of H2:0, is(A) 4:5(B) 7:2either 4:5 or7:2 (D) 2:1​

Answer»

D 2:1 is the ANSWER to QUESTION

10.

A boy of mass 30kg is running with a velocity 3 m/s on the ground just tangential to the merry go round which is at rest.it had radius 2m,mass 120kgants radius of gyration is 1m.if the boy suddenly jumps into the merry go round , the angular velocity aqquired by the system is

Answer»

Given:

A boy of mass 30kg is running with a velocity 3 m/s on the ground just tangential to the merry go round which is at rest.it had radius 2m,mass 120kgants radius of gyration is 1m.

To FIND:

Angular velocity acquired by the SYSTEM when boy JUMPS on the merry-go round.

Calculation:

In this type of questions , we need to apply the concept of conservation of angular momentum since no is External Torque is involved.

Let mass of boy be m and mass of merry-go-round be M ; K denotes radius of gyration.

\rm{ \therefore \: L = constant}

\rm{  =  >  \:( I1)( \omega1)= (I1 + I2) \omega}

\rm{  =  >  \:(m {r}^{2} )( \dfrac{v1}{r} )= (I1 + I2) \omega}

\rm{  =  >  \:(m {r}^{2} )( \dfrac{v1}{r} )= ( M{r}^{2}  + M {k}^{2} ) \omega}

\rm{  =  >  \:(mr) (v1)= (M {r}^{2}  + M {k}^{2} ) \omega}

Putting available VALUES in SI unit:

\rm{  =  >  \:30 \times 2 \times 3= M ({r}^{2}  +  {k}^{2} ) \omega}

\rm{  =  >  \:180= M ({r}^{2}  +  {k}^{2} ) \omega}

\rm{  =  >  \:180= M  \{{(2)}^{2}  +  {(1)}^{2}  \}\omega}

\rm{  =  >  \:180= M  \{5 \}\omega}

\rm{  =  >  \:180= 120 \times5\omega}

\rm{  =  >  \:3= 2 \times5\omega}

\rm{  =  >  \:3= 10\omega}

\rm{  =  >  \:\omega = 0.3 \: rad {s}^{ - 1} }

So, final answer is:

\boxed{\bf{\omega = 0.3 \: rad {s}^{ - 1} }}

11.

V vector(t)=dr vector÷d(t)R=(3.0t i vector+2.0 t square j vector+5.0k vector), find V

Answer»

ANSWER:

hj468434543567yfxvkjgx xsdujk

12.

A wire of resistance 2 ohms per meter is bent to form a circle of radius 1m

Answer»

ANSWER:

[email PROTECTED]₩&'hwel#£*#*kzjsyfirioe

13.

A car attains a velocity of 54km/h within 5seconds from an initial velocity of 18km/h. Find its acceleration and displacement

Answer»

54km/hr= 15m/s

18km/hr= 5m/s

A=15-5/5

A=5m/s²

V²=U²+2as

225-25/10

S=200/10

S=20m

14.

a particle is projected with velocity u making an angle 30° with the horizontal, vertical velocity of the particle at the highest point is

Answer»

vy=0 at HIGHEST POINT or at MAX HEIGHT

15.

What are the three devision of stone age ​

Answer»

ANSWER:

The three DIVISION of STONE age are ANCIENT period ,medieval period and modern period.

16.

(a) 15 s19. In the above question what are the distances traveleach of them till they meet?(a) 30 m and 70 m(b) 40 m and 60 m(c) 50 m by each(d) 45 m and SS m​

Answer»

Answer:

This is also the speed at which they are MOVING TOWARDS each other or the speed at ... Thus, the distance covered in 3 min = (10 x 3 x 60) = 1,800 m . ... We KNOW that S X T = D, But now his speed is 3/ 4 ...

17.

What is real focus and virtual focus ?​

Answer»

Answer:

The focus where the parallel LIGHT rays coming from a FAR object, parallel to each other and to principle axis converge actually is called real focus and when it DIVERGE but appears to converge if rays are extended back is called virtual focus.

18.

(4) 5, 12 sec.sec.10.(1) 6 sec(2) 2 sec(3) 4 secA particle of mass 0.01 kg is projected withvelocity v = 2î from point (x = 0, y = 20). After2 second, its position co-ordinates will be(1) 4,0(2) 4, -20(3) 0,4(4) 4, 20.A body is thrown vertically upward from theground. It reaches a maximum height of 100 min 5 sec. It will reach the ground from the1211.​

Answer»

ANSWER:

no answer because I doesn't UNDERSTAND this TYPE of QUESTIONS SORRY

19.

How to calculate magnitude of the displacement​

Answer»

Answer: SPEED * TIME

Explanation:

SPEED = DISTANCE/ TIME (DISPLACEMENT = SHORTEST DISTANCE)

NOW,

DISPLACEMENT = SPEED * TIME.

HOPE IT HELPS.

PLZ MARK IT AS BRAINLIEST... THANKS

20.

Derivation of small g​

Answer»

if you like ANSWER then please MARK as BRAINLIST THANKYOU it's my REQUEST.

21.

Plss answer fast.. if displacement of a body is given as x=√1+t^2. find acceleration of body.​

Answer»

Acceleration and displacement are related as a = x²

we KNOW, acceleration , a =

so, x² =

⇒x²dx = vdv

⇒∫x²dx = ∫vdv

at X = 0 , body is in rest ∴ initial velocity , v₀ = 0

Let velocity at x = 2 is v

Now,

⇒ [x³/3]²₀ =

⇒8/3 = v²/2

⇒16/3 = v²

So, v = ±4/√3 m/s

Hence, MAGNITUDE of velocity = 4/√3 m/s

22.

A car travels the first third half a distance with v1speed the second third with v2speed and the last third with v3speed what is its mean speed over the entire distance

Answer»

ANSWER:

n/Vavg= 1/v1+1/v2+1/v3

Explanation:

If a PARTICLE COVERS n-equal distances with VELOCITY v1,v2......hn.

Then Vavg,

n/Vavg= 1/v1+1/v2+........+n/vn

23.

If we triple the distance between two objects, then the force of gravitation will become........???​

Answer»

Answer:

It will become 1/9th of the of the previous

Explanation:

Force is INVERSELY PROPORTIONAL to the square of distance between TWO objects if we increase the distance by 3 times then the force will decrease by 1/9

24.

Star A is farther than star B. Which starwill have a large parallax angle?​

Answer»

ANSWER:

TWO are same prallax ANGLE

25.

What is universal gravity constant??__☆☆ Explain it ☆☆__​

Answer»

Answer:

The gravitational constant, denoted by the LETTER G, is an empirical physical constant involved in the CALCULATION of gravitational effects in Sir Isaac Newton's LAW of UNIVERSAL GRAVITATION and in Albert Einstein's general theory of relativity.

#Hope it helps ✨

26.

Cheak whether the physical quantity is correct or not v = u+at

Answer»

Answer:

yes, its correct

Explanation:

It is the FIRST EQUATION of MOTION:

a=v-u/t

at=v-u

at+u=v

thus, v=u+at

27.

Question 1: An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.

Answer»

Answer:

EXPLANATION:

F=ma

m=mass of object

a=acceleration produced by the object

Given,

FINAL velocity (v) =10m/s

Initial velocity (u)=0m/s (as the car START s from REST)

Time(t)=5s

Acceleration =v-u/t

10-0/5=2m/s²

Force=50×2=100N

FORCE=100N

28.

What are the correct units of energy

Answer»

THE CORRECT UNIT OF ENERGY IS JOULE

29.

Please tell 15 question fast will mark as brainliest if answer is correct with formulas ​

Answer»

Explanation:

1. On the surface of earth

acceleration due to Gravity (g) = g

weight = mg

= 10*10 ( g = 10 m/s²)

= 100N

2. On the surface of moon

acceleration DUE to gravity (g) = g/6

WEIGHT = mg

= 10*10/6 ( g = 10/6 m/s²)

= 100/6 N

3. At the centre of earth :-

acceleration vary with depth as

g' =g(1-d/r)

where g' = acceleration due to gravity at depth

d = depth

r = radius of earth

At centre d = r

g' = 0

thus weight = mg

= 10*0

= 0

thus person feels weightlessness

30.

A body of mass 2kg is moving with a velocity of 20m/s .find momentum?

Answer»

Answer:40 KG m/s

Explanation:

Formula for FINDING MOMENTUM is P(momentum)= m(mass)*V(Velocity)

31.

A man mass 62 kg is standing on stationary boat if mass 238 kg the nan carry so here mass 0.5 throws it horizontally with u = 12 m s find the velocity with which boat move

Answer»

INITIALLY, man, boat and SPHERE all are in rest. so, initial linear momentum of SYSTEM = 0

now, the man throws a sphere of mass 0.5kg with speed 12m/s in horizontal direction.

so, linear momentum of sphere = mv = 0.5kg × 12m/s = 6 Kgm/s

Because, no external force is acting on system so, linear momentum will be conserved.

i.e., initial linear momentum = final linear momentum

⇒0 = 6 + linear momentum of man + linear momentum of boat.

if we assume man doesn't move with respect to boat.

then, velocity of boat = velocity of man = v' (let)

now, 0 = 6 + 62 × v' + 238 × v'

⇒0 = -6 + 300v'

⇒v' = -6/300 = -0.02 m/s

hence, velocity of boat is -2 × 10^-5 m/s

32.

A car covers the first half of the distancebetween the two places at 40 km/h andanother half at 60 km/h. The average speed ofthe car is:(a) 40 km/h(b) 48 km/h(c) 50 km/h(d) 60 km/h​

Answer»

let x/2 distance COVER in TIME t1 & another x/2 distance cover in time t2

t1 = (x/2)/40

t2 = (x/2)/60

t1+t2 = x/48

average speed = x/(t1+t2) 

                     = x/(x/48)

                     = 48Km/hr

(2) as the above

t1 = x/40

t2 = x/60

t1+t2 = x/24

average speed = 2x/(x/24)

                      =48Km/hr 

(3) S1 = 6*2 

           = 12Km.

s2 = 4*3

      = 12Km.

total distance = s1+s2 = 24km.

average speed = 24/5

                      = 4.8Km/hr

33.

Answer please.. ASAP​

Answer»

ANSWER:

hope it will HELP uh.....

if it helps.... mark as BRAINLIEST too

34.

The position of an object changes from r = (2i+j) m to r1=(4i+3j) m in 2 s. Find its average velocity

Answer»

Answer:

3.62 m/s

Explanation:

R1 = √4+1 = √5

r2 = √16+9 = 5

Average VELOCITY =[ (√5) + 5 ]/2

= 7.24/2

= 3.62 m/s

35.

A car moves with velocity 10 m/s towards East in5 s, its velocity changes to 10 m/s towards North.Then the change in velocity of car is​

Answer»

ANSWER:

The change in velocity of the car is 10√2 m/s

Explanation:

According to the problem the velocity of the car while MOVING towards EAST was 10 m/s

The velocity of the car while moving towards North is 10 m/s

The direction as well as velocity changes after 5 s

Now the change in velocity will be: √(INITIAL velocity)^2 + (final velocity)^2

                                                          = √ (10)^2 + (10)^2

                                                         = √ 100 + 100 =  10√2 m/s

36.

Difference Between audiable and inaudiable range​

Answer»

Answer:

Audible sounds are sounds of frequency which are audible to human ear. However, on the other hand, INAUDIBLE sounds are those sounds who have frequency not audible for human ear. The frequency of audible sounds is usually 20-20,000 HERTZ, while that of inaudible is above 20kHz(kiloHertz).

Explanation:

thanks for asking

HOPE it helps

37.

Answer this question plz... ASAP. With proper derivation. ​

Answer»

ANSWER:

I HOPE it will HELP UH....

38.

A particle is moving along a circle such that itsposition vector with respect to origin isr = 2r° (sinwti^ + coswtj^), where r° and w areconstant. The motion is with(1) Constant speed 12) Constant velocity43) Constant acceleration 14) Constant momentum​

Answer»

ANSWER : option (1) constant speed

explanation : A PARTICLE moves along a circle such that its position vector with respect to origin is r=2r_0(sin\omega t\hat{i}+cos\omega t\hat{<klux>J</klux>})

where r and ω are constants.

differentiating with respect to time,

dr/dt = 2r_0[d(sinωt)/dt i + d(cosωt)/dt j ]

= 2r_0(-ωcosωt i + ωsinωt j)

= 2r_0\omega(-cosωt i + sinωt j)

so, velocity of particle is v = dr/dt = 2r_0\omega(-cosωt i + sinωt j)

now, speed of particle = |v|

= 2r_0\omega\sqrt{sin^2(\omega t)+cos^2(\omega t)}

= 2r_0\omega (constant )

hence, it is CLEAR that speed of particle is constant.

hence, option (1) is correct choice

39.

Howtocalculateerrorindivision​

Answer»

ANSWER:

The formula is QUOTIENT ×Divisor +Remainder

Explanation:

At first MULTIPLY the quotient with the divisor and then add with the remainder. HOPE it helps you

40.

Plzz answer this question with explanation dudes​

Answer»

ANSWER:

EXPLANATION:

HOPE it will HELP you

41.

We observe that the wheels of buses and trucks are heavier than the wheels of car why

Answer»

ANSWER:

Because BUSES and trucks are heavier in weight so they need big heavy WHEELS with broader and the weight of cars and scooters are LESS so they need small and light weighted wheels.And if the wheels are small then the pressure will more on ROAD.

42.

नातलघु उत्तरीय प्रश्न1. समतल दर्पण पर पड़नेवाली एक ही प्रकाश किरण की कितनीपरावर्तित किरणें हो सकती हैं?2. समतल दर्पण पर लंबवत पड़नेवाली किरण किस प्रकारपरावर्तित होती है?1. समतल दर्पण पर अभिलंब आपतन (normal incidence) के| लिए परावर्तन कोण का मान कितना होता है?प्रकाश के परावर्तन के कितने नियम हैं?समतल दर्पण में वस्तु-दूरी (object distance) औप्रतिबिंब-दूरी (image distance) में क्या संबंध है?​

Answer»

ANSWER:

TYPE in ENGLISH.... MATE

43.

What is the difference between typhoon and tornado

Answer»

EXPLANATION:

typhooon is the HEAVY WATER flowing movements in the oceans

tornado is heavy winds which starts from the surface of the ground ,by which all particles go into the heavy air.

44.

How to find frequency with a example

Answer»

ANSWER:

for a FREQUENCY DIGRAM

Explanation:

1.2.3.4.5.6.7,-1.-2.-3.-4.-5.-6.-7

45.

Matter how many type ​

Answer»

matter.Eg;sand,water,oxygen,WOOD,rock.are all different kinds of matter because all of them occupy SPACE and have mass.MATTER is classified into three TYPES;solidsliquidsgases

follow me and mark as brainliest please!

46.

What is atomic structure​

Answer»

Answer:

\huge\underline\red{\ttHey\:Mate} The structure of an ATOM, theoretically consisting of a positively charged nucleus surrounded and neutralized by negatively charged ELECTRONS revolving in orbits at VARYING distances from the nucleus, the constitution of the nucleus and the arrangement of the electrons DIFFERING with various chemical ELEMENTS.

47.

What is geothermal energy ?​

Answer»

EXPLANATION:

Geothermal ENERGY is thermal energy generated and stored in the EARTH.

hope it helps

48.

Challenge for brainliest.solve this class 9 question.those who do first will mark as brainliest​

Answer»

ANSWER:

the above is the answer

49.

A man completed 1/2 round of radius at what distance and displacement​

Answer»

EXPLANATION:

DISTANCE PI*r

displacement is 2R

50.

Calculate the force on the object if it moves with uniform velocity​

Answer»

HERE IS YOUR ANSWER:-

It is given that velocity is uniform

hence , there is no change in velocity with respect to time.

therefore , as acceleration is equal to rate of change of velocity with respect to time , it is 0.

Now,

Force = ma

Force = m × 0

Force = 0 N.

Hope it helps you//...

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