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(a) 15 s19. In the above question what are the distances traveleach of them till they meet?(a) 30 m and 70 m(b) 40 m and 60 m(c) 50 m by each(d) 45 m and SS m |
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Answer» Answer: This is also the speed at which they are MOVING TOWARDS each other or the speed at ... Thus, the distance covered in 3 min = (10 x 3 x 60) = 1,800 m . ... We KNOW that S X T = D, But now his speed is 3/ 4 ... |
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