This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Give two safety measures to be taken during thunderstrom |
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Answer» Answer: ❤️❤️hello DEAR here is your answer mark it BRAINLIST ok and FOLLOW me... :) ☺️☺️❤️❤️ |
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| 2. |
The two bodies of masses 40 kg and 80kg are at a distance of 0.15m the force of gravitation between them is 1N.calculate the constant of gravation. |
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Answer» Answer: 7.03 × 10^-6 Nm²/kg Explanation: From GRAVITATIONAL force formula F = GMm/d² G = Fd² / (Mm) = 1 N × (0.15 m)² / (40 kg × 80 kg) = 7.03 × 10^-6 Nm²/kg² Note: The correct Universal gravitation CONSTANT is 6.67 × 10^(-11) Nm²/kg². |
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| 3. |
if the angle of projection is 60°,the height of the projectile when it was travelled a distance 3R/4 where R is the range |
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Answer» which angle HEIGHT of projectile is maximum? ... What will the angle of projection be if the horizontal range of ... The PARTICLE travels for a TIME t = 2*V*sin A/g and the ... |
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| 4. |
A model of helicopter is made in which a kind of box is introduced inside it for the sitting of passengers. The box is further connnected to a parachute which get opens during any hard situation (such as fire). Is the model accurate or it Do have any demerit ?Quick reply please! |
Answer» HELLO MATES |
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| 5. |
a boy press horizontally a book against the front wall such that book does not slide down . the force of friction between wall and book is |
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Answer» Answer:
Explanation: Force of FRICTION is the force which opposes the MOTION of the object. It always acts in the OPPOSITE direction of the motion. When a book is press horizontally against the front wall, the force of friction is
Where R= Normal force of the book which is reaction of book exerted by the weight of the book. R=mg.............(2) where m=mass of the book, g=acceleration due to gravity using (1) and (2) we get So,force of friction is,
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| 6. |
Examples for free oscillations |
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Answer» Answer: Free oscillations[edit] When an object is in free OSCILLATION, it vibrates at its natural frequency. For example, if you strike a TUNING FORK, it will begin to vibrate for some time after you struck it, or if you HIT a PENDULUM, it will always oscillate at the same frequency no matter how hard you hit it. |
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| 7. |
Give me some examples of unit vector from real life ???? |
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| 8. |
When we freely suspend a bar magnet,the north pole of the magnet turns to North and South pole of the magnet turns to South . But if South pole of one bar magnet is kept near other magnet 's South pole,they repel and if we keep north and south pole then they get attached to each other. WHY? |
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Answer» the south gets ATTRACTED towards north . it is because like pole ATTRACT and UNLIKE pole REPEL |
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| 9. |
What is the dimensonl of k in the expresion of work in Spring |
| Answer» K is a CONSTANT Vance it has no UNIT or DIMENSION | |
| 10. |
Name the kind of frictional friction that comes into play when a book lepton a collection of cylindrical pencils, is moved by pushing |
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| 11. |
.What can be the angle between P vector + Q vector and p vector - q vector |
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Answer» The angle between P VECTOR + Q vector is 0° while the angle between P vector - Q vector is 180°. Since RESULTANT vector=√P^2 vector +Q^2 vector +2PQvector cos 0°. (cos 0°=1 and cos 180°=-1) HOPE THIS HELPS..☺️ |
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| 12. |
What is a motion? and what is its formula for numerical |
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Answer» Answer: As we have already discussed earlier, motion is the state of change in position of an object over time. It is described in terms of DISPLACEMENT, distance, velocity, acceleration, time and speed. Jogging, driving a car, and EVEN simply taking a walk are all everyday examples of motion. The relations between these quantities are known as the equations of motion. In case of uniform acceleration, there are three equations of motion which are also known as the laws of constant acceleration. Hence, these equations are used to derive the COMPONENTS like displacement(s), velocity (initial and final), time(t) and acceleration(a). Therefore they can only be applied when acceleration is constant and motion is a straight line. The three equations are, v = u + at v² = u² + 2as s = ut + ½at² where, s = displacement; u = initial velocity; v = final velocity; a = acceleration; t = time of motion. These equations are REFERRED as SUVAT equations where SUVAT stands for displacement (s), initial velocity (u), final velocity (v), acceleration (a) and time (T) DERIVATION of the Equations of Motion v = u + at Let us begin with the first equation, v=u+at. This equation only talks about the acceleration, time, the initial and the final velocity. Let us assume a body that has a mass “m” and initial velocity “u”. Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that: Acceleration = Change in velocity/Time Taken Therefore, Acceleration = (Final Velocity-Initial Velocity) / Time Taken Hence, a = v-u /t or at = v-u Therefore, we have: v = u + at v² = u² + 2as We have, v = u + at. Hence, we can write t = (v-u)/a Also, we know that, Distance = average velocity × Time Therefore, for constant acceleration we can write: Average velocity = (final velocity + initial velocty)/2 = (v+u)/2 Hence, Distance (s) = [(v+u)/2] × [(v-u)/a] or s = (v² – u²)/2a or 2as = v² – u² or v² = u² + 2as s = ut + ½at² Let the distance be “s”. We know that Distance = Average velocity × Time. Also, Average velocity = (u+v)/2 Therefore, Distance (s) = (u+v)/2 × t Also, from v = u + at, we have: s = (u+u+at)/2 × t = (2u+at)/2 × t s = (2ut+at²)/2 = 2ut/2 + at²/2 or s = ut +½ at² |
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| 14. |
suppose A=B^m C^m where A has dimension LT. B has dimensions L^2 T^-1 and C has dimensions LT^2 then for the value of m & n. |
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| 15. |
The value of 120 joule per second on a system thathas 10 g, 10^2 cm and 10^3 second as base unit is ____(1) 12 x 10^10 units (2) 12 x 10^12 units(3) 12 x 10^14 units (4) 12 x 10^16 units |
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Answer» here we are USING the basic formula for unit conversion through dimensional analysis any physical QUANTITY is equal to the product of its unit with the magnitude if you have a physical quantity X then X = n1u1 = n2u2 where YUVAN YouTube or units of the physical quantity in two different systems and n1and n2 are magnitudes corresponding to two different systems n2 = n1u1/u2 = 120(1kg/10g)(1m/10²cm)²(1s/10³s)-³ =120(10²)(1)²(10-³)-³ =12×10¹² answer is (2) Any doubts ask me through chat |
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| 16. |
Please answer the question as soon as possible |
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Answer» Answer: OPTION a. From units and DIMENSIONS you'll STUDY that arguments of trigonometric FUNCTIONS should be dimensionless |
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| 17. |
A boat which has a speed of 5 km per hour in still water crosses a river of width 1km along the shortest possible path in fifteen minutes. The velocity of the river water in km per hour is |
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Answer» Answer: LET the velocity of the RIVER be x. the velocity of the river will be in the HORIZONTAL direction velocity of boat in still water is 5km/hr. As the width of the river is 1 km and time taken by the boat to cross the river along the shortest path is 15 min therefore the velocity of the boat is= 1*60/15= 4km/hr according to the figure the velocity of the river is along AB . By applying triangle law of vector addition the value of AB COMES to be 3km/hr |
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| 18. |
15. A car start from rest and acquire a velocity of 54 km/h in 2 sec. Finda) the accelerationb) distance travelled by car assume motion of car is uniformc) If the mass of the car is 1000 Kg, What is the force acting on it |
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Answer» Explanation: speed of car = 54 KMPH = 54 X 5/18 = 15m/s (a) V = u+ at 54 = 0+ 2a a= 27 m/s^2 (b) s= UT + 1/2 at^2 = 27x 2 = 54M |
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| 19. |
Strongest fundamental force in nature?? |
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| 20. |
Defination + formula of method of application of science |
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Answer» Explanation: The scientific method. When conducting research, scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a HYPOTHESIS (OFTEN in the form of an if/then statement), the results AIMING to support or contradict a theory. |
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| 21. |
a pushing force of 50 newtons acts on a block at an angle of 30 degree with horizontal. the respicetive horizontal and vertical components of force will be |
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Answer» HORIZONTAL COMPONENT is = 50cos30°= 50sqrt3/2N vertical component is = 50sin30° = 25N |
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| 22. |
When a wheel of radius 50 cmmakes 2 revolutions, the lineardistance travelled by it is:A) 3.14 cmB) 6.28 cmC) 628 cmD) 12.5 cm |
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Answer» Answer: 628cm because in one revolution it will GO 2*π*r =4*(22/7)*50CM |
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| 23. |
The energy associated with one gram of mass is(a) 9x10^-13 J(b) 9x10^-16 J(c) 9x10^13 J(d) 9x10^16 J |
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Answer» option C is the right answer i. e. for ONE gram of MASS it is 9*10^13 joules. hope It help uh |
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| 24. |
A stone on the edge of vertical Cliff is kicked so that its initial velocity is 9 m/s horizontally. If the Cliff is 200m high calculate time taken by stone to reach the ground and how far from the Cliff the stone will hit the ground |
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Answer» t=2root10 r=18root10 Explanation: use time and range formula of OBLIQUE PROJECTILE |
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| 25. |
What is the magnitude of vector A= 2i+3j-k and B=4i-j-6k |
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| 26. |
A toy of mass 0.1kg acquires a speed of 5 m/s find the impulse |
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| 27. |
A person walks 12m towards north and then 4 m towards west and there he climbs a pole of 3 m height . The total distance travelled by the person is |
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Answer» Answer: |
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| 28. |
a projectile is thrown with an initial velocity u and angle 15 to the horizontal has a range R if the same projectile is thrown at an angle of 45 to the horizontal with speed 2u its range will be |
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Answer» R15=2u2/g(cos15×sin15) so R 45degree=R15×2u |
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| 29. |
A car is going towards north with a velocity 20 metre per second full stop after some time it starts to go towards south with velocity 20 metre per second full stop determine changes in the velocity of the car full stop |
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Answer» ZERO because DISPALCEMENT is zero |
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| 31. |
Hiiii plzz answerfollow mee |
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Answer» we think ithey are GOOD because : 1.It helps farmers to buy good SEEDS and other necessary things so they do not have to take loan on high interest 2.Farmers feel good that tere is someone who can help them 3.We can see that the suicide rate of farmers decreased after all the efforts PLEASE MARK AS BRAINIEST |
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| 32. |
The mass of the earth is 6(10)^24 kg and that of the moon is 7.4 (10)^22 kg .If the distance between the earth and the moon is 3.84 (10)5 kg .Calculate the force exerted by the earth on the moon |
Answer» Answer:20.2 × 10¹⁹ N Explanation:Given : Mass of earth = 6 × 10²⁴ kg Mass of moon = 7.4 × 10²² kg Distance between them = 3.84 × 10⁵ km = 3.84 × 10⁸ m We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻² We have to find FORCE : We have : F = G m₁ m₂ / r² F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / ( 3.84 × 10⁸ )² N F = 20.2 × 10¹⁹ N Hence force EXERTED by the earth on the moon is 20.2 × 10¹⁹ N. |
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| 33. |
For a body starting from rest the displacement in 10 sec when it acquires 4m/s in 2 sec is |
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Answer» Answer: Given, initial velocity u = 0m/s Velocity after 2s, v = 4m/s Acceleration a = (v - u)/t = (4-0)/2 = 2m/s^2 Under UNIFORMLY accelerated MOTION, After t = 10s S = UT + (1/2)at^2 S = 0 + (1/2) x 2 x (10^2) = 100m S = 100m |
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| 34. |
For 100%efficiency of a carnot engine the temperature of the source should be |
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Answer» Dear Student, ◆ Answer - For 100% EFFICIENCY of a carnot engine the temperature of the source should be infinite. ● Explaination - Efficiency of Carnot engine is calculated by formula - η = 1 - T2/T1 Here, for η to be 1 i.e. 100 %, EITHER T2 (temperature of the sink) should be zero or T1 (temperature of the source) should be infinite. Therefore, for 100% efficiency of a carnot engine the temperature of the source should be infinite. Hope this helps you... |
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| 35. |
Find the recoil velocity of gun of mass 2kg from which a bullet of 20 g is fired with a velocity of 200m/s |
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Answer» Given m1= 2 kg, V1 =? , m2= 20 x 10∧-3 kg, v2=200m/s According to the LAW of linear momentum, m1 x v1=m2 x v2 2 x v1 = 20 x 10∧-3 x 200 v1= 2 x 10∧-2 x 2 x 10∧2 / 2 v1= 2m/s Explanation: |
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| 36. |
Find the maximum horizontal distance travelle by a ball thrown with a velocity 40 m per s without hitting thr roofd |
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Answer» Answer: 160M. Explanation: R = u²sin2∝/g ∝ = 45° R = u²sin90°/g = u²/g = 40²/10 = 160m. |
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| 37. |
Find the magnetic field intensity at the centre o of a square of the sides equal to 5m and carrying 10a of current |
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| 38. |
Find the flux contained by the material when the flux density is 11.7 tesla and the area is 2 units. |
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Answer» It will be about 23.4 T (unit). Explanation: The FORMULA of magnetic flux is : ϕ = B × A cosθ Where B is the magnetic field and A is the area vector. Let US assume that B is parallel to A. That IMPLIES, ϕ = B × A cos0° Thus, ϕ = B × A ϕ = 11.7 T × 2 unit = 23.4 T (unit). |
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| 40. |
A meter scale of mass 400 gm is lying horizontally onthe floor. If it is to be heldvertically with one end touching the floorwork to be done is |
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Answer» here torque will PLAY a role
Explanation: the torque required will be totally DEPENDENT on the LENGTH of the scale (*note i didn't refer any book based on my conscience i just answered this question) |
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| 41. |
Angular 5 Property 'style' does not exist on type 'Element' |
| Answer» EVERY ELEMENT EXIST on STYLE of the CHEMICAL | |
| 42. |
A rectangular car top carrier of 2.1 ft height front to back and 4.2 ft width |
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| 44. |
Write a short note on bose einstein condenstate |
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Answer» Hey...here your answer______________________ |
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| 46. |
Methods to analyze the energy efficiency of electrical utilities |
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Answer» IMPROVE POWER factor leading pf efficient APPLIANCES |
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| 47. |
Difference between active and passive elements |
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Answer» Hey ...... here your answer______________________ |
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| 48. |
Why small engines having larger RPM and larger engines having smaller RPM/quora |
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Answer» Small engine have small shaft and small arm and BIG engines have big shaft and very very big arm that is why it has LESS RPM |
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| 49. |
Why induction genrator in small wind energysystems |
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| 50. |
What is problem if fingerprint red light is not comes |
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Answer» If FINGERPRINT RED LIGHT is not COMES it is MISMATCHED |
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