1.

Find the recoil velocity of gun of mass 2kg from which a bullet of 20 g is fired with a velocity of 200m/s

Answer»

ANSWER:

Given m1= 2 kg, V1 =? , m2= 20 x 10∧-3 kg, v2=200m/s

        According to the LAW of linear momentum,

                 m1 x v1=m2 x v2

                  2 x v1 = 20 x 10∧-3 x 200

                   v1= 2 x 10∧-2 x 2 x 10∧2 / 2

                        v1= 2m/s

Explanation:



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