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Find the recoil velocity of gun of mass 2kg from which a bullet of 20 g is fired with a velocity of 200m/s |
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Answer» Given m1= 2 kg, V1 =? , m2= 20 x 10∧-3 kg, v2=200m/s According to the LAW of linear momentum, m1 x v1=m2 x v2 2 x v1 = 20 x 10∧-3 x 200 v1= 2 x 10∧-2 x 2 x 10∧2 / 2 v1= 2m/s Explanation: |
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