This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Statement given bellow are incorrect. Write the correct statement :- (1) Force per unit area of a substance is called dentisty. (2)The mass of a solid is determined by a spring balance very accurately. |
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Answer» per unit AREA of a SUBSTANCE is called density2.the force of a SOLID is DETERMINED by a spring BALANCE very easily |
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| 2. |
The radius of curvature of a spherical mirror is 20 cm. What is its focal length ? |
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Answer» 10cmExplanation:Given-Radius of CURVATURE, R = 20 CMRADIUS of curvature of a spherical mirror= > 2 x focal length(f)=> R = 2F=> f = R/2=> f = 20/2=> f = 10 cm.Hence, the focal length of the given spherical mirror is 10 cm |
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| 3. |
Light bulbs are connected to 6V battery as shown in Figure below. Calculate the flowing : (i) The total current supplied by the battery (ii) (ii) The current through each bulb(iii) The resistance of each bulb |
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| 4. |
.Two tyres of a tractor are very wide and huge . why? |
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Answer» ➡Because of this, heavy VEHICLES (like tractor) can MOVE even on SOFT roads and fields without sinking. ... Since, weight of tractors are preety heavy that is why we uses broad TIRE so as to divide its weight equally and hence, it prevents sinking of tractor in soil. |
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| 5. |
A proton, a neutron, an electron and an a-particle have same energy. Then their de Broglie wavelengths compare as [NCERT Exemplar] (a)λp = λn > λe > λα (b) λα < λp = λn < λe (‘C) λe < λp = λn > λα (d) λe = λp = λn = λα |
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Answer» option A is the RIGHT ANSWER...........for better ANSWERS please follow me and mark as brainliest |
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| 6. |
If K.E. of free electron is doubled, its de Broglie wavelength will change by factor (a) \frac{1}{\sqrt{8}} (b) √2 (c) \frac{1}{2} (d) 2 |
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Answer» its DE - Broglie wavelength CHANGES by the FACTOR. Solution : λ=1√2mE⇒λ∝1√2. |
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| 7. |
Ss 12 Physics MCQ Chapter Wise Question 9. A proton and an α-particle are accelerated by the same potential difference. The ratio of their de broglie wavelengths (λp, λα) is (a) 1 (b) 2 (c) √8 (d) \frac{1}{\sqrt{8}} |
| Answer» OPTION A is the RIGHT ANSWER | |
| 8. |
The energy of photon of wavelength 450 nm is (a) 2.5 × 10-17 J (b) 1.25 × 10-17 J (c) 4.4 × 10-19 J (d) 2.5 × 10-19 J |
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Answer» 2.76 EV................ |
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| 10. |
Which of the following figure represents the variation of particle momentum and associated de Broglie wavelength? |
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| 11. |
Toelectric Effect Multiple Choice Questions and Answers Pdf8. The slope of the stopping potential versus ‘ frequency graph for photoelectric effect is equal to (a) h (b) he (c) h/e (d) e |
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Answer» option C is the right ANSWER...Explanation:for better answers please follow me....please MARK as brainliest |
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| 12. |
Sics MCQs for Class 11 With Answers Pdf Question 5. The stopping potential V0 for photoelectric emission from a metal surface is plotted along y-axis and frequency v of incident light along x-axis. A straight line is obtained as shown. Planck’s constant is given by (a) slope of the line (b) product of the slope of the line and charge on electron (c) intercept along y-axis divided by charge on the electron (d) product of the intercept along x-axis and mass of the electron |
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Answer» option b is the right ANSWER..for BETTER ANSWERS please FOLLOW me..please mark as brainliest |
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| 13. |
For a given kinetic energy which of the following has smallest de Broglie wavelength? (a) Electron (b) Proton (c) Deutron (d) a-particle |
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Answer» α particle has the highest MASS among the given ENTITIES, it has the SMALLEST de-Broglie WAVELEGTH. |
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| 14. |
Ss 12 Physics MCQ Chapter Wise Question 10. Work function of three metals A, B and C are 4.5 eV, 4.3 eV and 3.5 eV respectively. If a light of wavelength 4000 Å is incident on the metals then (a) photoelectrons are emitted from A. (b) photoelectrons are emitted from B. (c) photoelectrons are emitted from C. (d) photoelectrons are emitted from all the metals. |
| Answer» OPTION A is the RIGHT ANSWER.. | |
| 15. |
The kinetic energy of an electron is 5 eV. Calculate the de broglie wavelength associated with it. (h = 6.6 × 10-34 Js, me = 9.1 × 10-31 kg) (a) 5.47 Å (b) 10.9 Å (c) 2.7 Å (d) None of these |
| Answer» N :Given :-▪ KINETIC energy of electron = 5eV▪ Mass of electron = 9.1×10kg▪ PLANK constant (H) = 6.6×10JsTo Find :-▪ De-broglie wavelength associated with electron.FORMULA :-▪ Formula of De-broglie wavelength associated with moving particle is given byCalculation :- | |
| 16. |
Maximum kinetic energy (Ek) of a photoelectron varies with frequency (v) of the incident radiation as |
| Answer» KINETIC ENERGY = HALF MV SQUARE. | |
| 17. |
We have to make a separate copy for notes or not? class 9th |
| Answer» AVE to MAKE NOTES in same COPY | |
| 18. |
One side of a thin metal plate is illuminated by the sun. When the air temperature is T., the temperature of the illuminated side is T, and that of the opposite side is T. What will be the temperatures of each sides be, ifanother plate of double thickness is used ? (temperature difference with surrounding is small)2T +TT2-T (3T-T2)- TzT +T-T2 - T. (3T, -T2) - TZ(T1 - TO)2/T; -T.)2T? +TT2-T, (T7 -3T2) - Tz2[T- TO)(D2, 2T +Ty T, -To(3T; - Ty)-T2/T2 - TO) |
| Answer» EXPLANATIO : can you SHOW me the method of SOLVING this problem?I NEED it so much | |
| 19. |
Definition of static electricity |
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Answer» stationary electric charge, TYPICALLY produced by FRICTION, which CAUSES sparks or CRACKLING or the attraction of dust or hair. |
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| 20. |
Plz solve this physics problem |
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Answer» D ................... |
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| 21. |
In the region of space how many are the points at which electric field is zero? |
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Answer» tion:✧༺♥༻✧✧༺♥༻✧If electric FIELD in some region of space is ZERO, it does not imply that there is no charge in that region. From gauss law in its divergence form, If E=0⇒ charge density ρ is 0.It implies there are EQUAL NUMBER of opposite CHARGES present. So, nothing concrete can be said about charges present in that region. |
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| 22. |
fill in the blanks :-(1) The distance covered by a body in unit time is called ____________________. |
| Answer» TANCE TRAVELLED by a body in unit time is called the SPEED of the body.MARK AS BRAINLIEST PLEASE | |
| 23. |
Theta is a angle between vertical line and the perpendicular line is what |
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Answer» Hey GUYS I am so CONFUSED sorry please marks as brainlist EXPLANATION: |
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| 24. |
2.It is difficult to cut a piece of cloth by a pair of scissors with its blunt blades . Give reason |
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Answer» Blunt blades have LARGER area compared to the sharp-edged blades. Thus, the applied FORCE PRODUCES a lower pressure in CASE of blunt blades, which makes it difficult to cut the cloth.Explanation: |
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| 25. |
Q. A biconcave lens of power P vertically splits into two identical plano concave parts. The power of each part will be (a) 2P (b) P/2 (c) P(d) P/√2 |
| Answer» F lens = PPower of each part On mutual terms ,Power is inversely propotional to the focal length.Also, Power = Now, Focal length and THICKNESS have a relation.And the relation turns out be FOCAL LENGTH is INVERSELY propotional to THICKNESS i.e. f = Now, When the lens splits up into two equal parts - The focal length is actually DOUBLED (2F)And as mentioned above , the power will become half of what it was earlier.SO THE ANSWER TURNS OUT BE - Option (b) | |
| 26. |
What is meant by power write its units |
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Answer» .....here is ur ANSWER....power = work/ time..work is measured in JOULES and t in SECONDS ..it's unit is WATT |
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| 27. |
What is the relation between 11kwh and 1j |
| Answer» 1KWH = 1KW X 1h = 1000 W x 3600 s=1000 js-1 x 3600 s = 3.6 x 106J | |
| 28. |
What is unit.Write its characteristics. |
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Answer» The chosen standard of measurement of a QUANTITY which has essentially the same nature as that of the quantity is called the unit of quantity. Characteristics- 1 It should be of suitable size. 2 It should be easily accessible. 3 It should be accurately definedPLEASE MARK ME AS BRAINLIEST |
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| 29. |
On Dual Nature of Matter And Radiation Question 3. Radiations of frequency v are incident on a photosensitive metal. The maximum K.E. of the photoelectrons is E. When the frequency of the incident radiation is doubled, what is the maximum kinetic energy of the photoelectrons? (a) 2E (b) 4E (c) E + hv (d) E – hv |
| Answer» OPTION A is the RIGHT ANSWER........ | |
| 30. |
Does the value of polarising angle depend on the colour of light? |
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| 31. |
How are interference and diffraction consistent with the principle of conservation of energy? |
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Answer» hey mateThis implies that in interference and diffraction pattern, the intensity of LIGHT is simply being redistributed i.e. ENERGY is only TRANSFERRED from dark to bright FRINGE and no energy is created or destroyed in the process. |
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| 32. |
Why does the intensity of the secondary maximum become less as compared to the central maximum? |
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Answer» It is because, the intensity of the central maximum is DUE to WAVELETS from all PARTS of the slit, the first SECONDARY maximum is due to wavelets from one THIRD part of the slit only, the second secondary maximum is due to the wavelets from the fifth part only and soon |
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| 33. |
The focal length of a spherical mirror has a smaller magnitude than that of its radius of curvature it is true or false please tell me |
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Answer» True. As C= 2F the focal length will ALWAYS be SMALLER then the centre of CURVATURE |
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| 34. |
L Nature of Matter And Radiation Class 12 MCQ Question 2. Threshold wavelength for a metal having work function W0 is X. What is the threshold wavelength for the metal having work function 2W0? (a) 4λ (b) 2λ (c) λ/2 (d) λ/4 |
| Answer» OPTION B is the RIGHT ANSWER.................................. | |
| 35. |
A source of sound of frequency 600hz is placed inside water |
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Answer» frequency of SOUND waves DEPENDS on source of sound . not on the MEDIUM of propagation . so the frequency of sound waves remain the same in air as well as water 600Hz.and I hope it will help youPLEASE MARK ME AS BRILLIANT |
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| 36. |
If the angle between the axis of polariser and the analyser is 45°, write the ratio of the intensities of original light and the transmitted light after passing through the analyser. |
| Answer» RATIO is 2 : 1Explanation:Let I' and I be the TRANSMITTED light and ORIGINAL lightAccording to Malu's lawI' = I cos²∅given: ∅ = 45°I' = I (cos 45° )²I' = I ( 1 / 2 )I / I' = 2I : I' = 2 : 1Hence you got the ratio ! | |
| 37. |
What is the condition that only interference is observed in double slit experiment, diffraction is not? |
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Answer» This not do to diffraction of the LIGHT. In the single slit experiment, the slit is large ENOUGH that diffraction does not occur. Instead EVERY point along the width of the slit acts like it's own point light source, which all interfere with one ANOTHER. |
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| 38. |
One of the two slits in Young’s double slit experiment is so painted that it transmits half the intensity of the other. What is the effect on interference fringes? [HOTS] |
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Answer» where the GASTRIC gland is present our BODY NAME the SECRETION of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary glandwhere the gastric gland is present our body name the secretion of salivary gland |
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| 39. |
L Nature of Radiation and Matter MCQ Questions with Answers Pdf Question 1. Light of frequency 1.9 times the threshold frequency is incident on a photosensitive material. If the frequency is halved and intensity is doubled, the photocurrent becomes (a) quadrupled (b) doubled (c) halved (d) zero |
| Answer» OPTION B is the RIGHT ANSWER......................,. | |
| 40. |
An unpolarised light of intensity 1 is passed through a polaroid. What is the intensity of the light transmitted by the polaroid? |
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| 41. |
How does the angular separation of interference fringes change, in Young’s experiment, if the distance between the slits is increased? |
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Answer» isisisisisisiakakwmsnsbdhhdajfrajauristsgokgsistdljdyagkajfelyahdwgkskgshagslldhsyljfashlLuskgsgkskgskgskgskydkhskgskgskyshmdkhsskhskgskgskgskgskgskgskgskgskydkgskgskgskgsyldlyslyslydylskysmhskydkydlydlysmhsmgskgskyskydlyhelydlyyyshlskysylsymskgskydykslyslydlyelydlyekydgksgkshkdgkzgksgkdgmsmgslhisisisisisiakakwmsnsbdhhdajfrajauristsgokgsistdljdyagkajfelyahdwgkskgshagslldhsyljfashlLuskgsgkskgskgskgskydkhskgskgskyshmdkhdk |
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| 42. |
What is the effect on the interference fringes in a Young’s double slit experiment, if the width of the source slit is increased? [NCERT Example] |
| Answer» TION:intensity of light emitted by the slits INCREASES as WIDTH of the slit is INCREASED. Thus, more brighter fringes are formed at screen on INCREASING width of the slits. | |
| 43. |
A ball is dropped from a tower of height 125 m. If g = 10 ms-2, find the time taken by it to reach the ground? please give steps as well |
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Answer» ____________________GIVEN:HEIGHT- 125m g - 10m/s^2initial VELOCITY -0time- ?using second equation of motion-h=ut+ 1/2gt^2125= 0*t+1/2*10*t^2125= 0+1/2*10*t^2125= 5*t^2125/5=t^2t^2= 25t=5 SEC _______________________________ |
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| 44. |
A moving train is brought to rest within 15sec by applying breaks. Find 1)the initial velocity of the train, if the retardation due to break is 3m/s² 2)the distance travelled by train during the time of retardation? |
| Answer» HOPE the ANSWER will HELP you ☺❤ | |
| 45. |
Fill in the blanks :-(1) In SI system unit of density _____________. |
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Answer» e your ANSWER is :KILOGRAM PER cube meters please Mark BRAIN LIST answer please please please please |
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| 46. |
1. Two bodies A and B massws are at rest. A is acted upon with 1kg-wt force and B with 1N. Will the acceleration generated in them be equal? (SHOW WITH STEPS) 2. Equal forces act on two masses 'm' and '2m' . If the acceleration acqired by 'm' be' f', what is the acceleration acqured by 2m? (SHOW WITH STEPS) |
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Answer» leration of A =>f=m×af= 1kg CONVERT to NEWTON 0.10.1=aB) accleration of b=1=ahence their accleration are not equal please MAKE it BRAINLIST answer please |
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| 47. |
T=k Pa Db Ec ,a,b and c are power of P ,D and E.Where P- pressure, D-density,E- energy .The value of a,b and c are |
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Answer» cljfkgdkgdykektsjtwtketkskydykelydkydkysykskysktskysktskgskgsjtsmgskyskyskysmgskydluflydphflhxlydoydoyslhslystkstishlsljfkgdkgdykektsjtwtketkskydykelydkydkysykskysktskysktskgskgsjtsmgskyskyskysmgskydluflydphflhxlydoydoyslhslystkstishlsylslydyldhldulddyulrlyduldlydgkdoyslyeyo uldkysylsylsourourpuruprpu hskyskysoyeyoeyoelydoye6eo6ely soydykekysylsylsyelyslydozigzsligzitlasiltljaflaitlrauautllaitsitsliflsjflaititsllaitlairtilswltiltsoydykekysylsylsyelyslydozigzsligzitlasiltljaflaitlrauautllaitsitsliflsjflaititsllaitlairtilswltiltsiltsisilylistlaitsjltlwitltwiiltwltwilsitpeitlaitlaitlaitlfailaitlstilsiy |
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| 48. |
which type of copy is used for making assignments for physics , I mean to say a normal sized copy or a register . class 9th |
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Answer» You can copy individual Mastering assignments so that they are available in more than one course, or WITHIN the same course so you can assign them again (with optional edits). About DATES: For any assignment, students SEE the assignment and its due date in the Assignments list BASED on the assignment's Available From and Available Until dates. Whenever you use a copied assignment, be sure to set these dates appropriately. For specialized student WORK: The following are always copied if you copy a course. The following notes describe how they are copied individually: Adaptive Follow-Up assignments are copied automatically if you copy the Parent assignment. Dynamic Study Modules can be copied as assignments into another course that supports them, but a module that has been assigned cannot be assigned again within the same course. Learning Catalytics modules can be copied into a different Learning Catalytics course, and a module that has been delivered can be delivered again in the same course. This setup is done entirely in Learning Catalytics. collapsedTo copy assignments from your other courses, or pre-built from the publisher collapsedTo copy an assignment within the current course collapsedTo copy another instructor's assignments collapsedIf you copy pre-built assignments or another instructor's assignments collapsedIf you copy an assignment from an older textbook edition collapsedTo copy an assignment TO other courses collapsedCategory settings do not travel from one course to another collapsedAdditional notes about copying assignmentsExplanation: |
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| 49. |
Calculate the resistivity of a metallic wire of length 1 m and diameter of 0.5mm and resistance is 10 ohm |
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Answer» -▪ Length of wire = 1m▪ Diameter of wire = 0.5mm▪ Resistance of wire = 10ΩTo FIND :-▪ Resistivity of wire.Concept :-▪ Resistivity is materialistic property of MATERIAL, it doesn't DEPEND upon length or AREA of conductor.▪ Formula of resistance in terms of resistivity, length and area is given byCalculation :- |
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