If K.E. of free electron is doubled, its de Broglie wavelength will change by factor (a) \frac{1}{\sqrt{8}} (b) √2 (c) \frac{1}{2} (d) 2

If K.E. of free electron is doubled, its de Broglie wavelength will ch

1.	If K.E. of free electron is doubled, its de Broglie wavelength will change by factor (a) \frac{1}{\sqrt{8}} (b) √2 (c) \frac{1}{2} (d) 2
Answer» its DE - Broglie wavelength CHANGES by the FACTOR. Solution : λ=1√2mE⇒λ∝1√2.

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If K.E. of free electron is doubled, its de Broglie wavelength will change by factor (a) \frac{1}{\sqrt{8}} (b) √2 (c) \frac{1}{2} (d) 2

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