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Charge (Q) = 25 C Potential Difference (V) = 20vTo Find:-Work done (W) Solution:-As we know that Potential difference between two point = work done/charge→ P = W/QSubstitute the value we get→ 20 = W/25→ W = 25 ×20→ W = 500 Joule.Extra Information !!Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a UNIT charge from one point to the other.Potential difference = Work done /Charge.V = W/Qhere V is the potential differenceW is the work doneQ is the charge ✧ SI unit of electric potential energy is volt (V).✧ 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.1 Volt = 1Joule/1Coulomb

Four point CHARGES qx = 2 uC, 9g. = -5 uc, QC = 2 uc, and q = -5 LC arelocated at the corners of a square ABCD of side 10 cm. What is theforce on a charge of 1 UC placed at the centre of the square?11Explanation:mark

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D)no unitsExplanation:REMEMBER that REFRACTIVE INDEX has no UNITS

Volcanoes are just a NATURAL way that the Earth and other planets have of cooling off and RELEASING internal heat and pressure. Volcanoes ERUPT because of density and pressure. The lower density of the magma RELATIVE to the surrounding rocks causes it to rise (like air bubbles in SYRUP).Explanation:l hope it helps you if then mark brainliest and follow me

ANSWERWe know the FORCE of attraction between two OBJECT is given by the formulaF= R 2 GMM = (3.84×10 8 ) 2 6.7×10 −11 ×6×10 24 ×7.4×10 22 =2.0×10 20 N

placement equation is given as: x=4(cosπt+sinπt)x=4 2 ( 2 1 cosπt+ 2 1 sinπt)x=4 2 (sin45 o cosπt+cos45 o sinπt)x=4 2 sin(πt+45 o )COMPARING with, x=A sin(wt+ϕ)⟹ AMPLITUDE of the particle, A=4 2please MARK me as a brainlist

Explanation:Subtraction With Exchanging on OPEN Number Line Subtraction With Exchanging on Open Number Line This VIDEO is an EXAMPLE of using the open number line and friendly 10 STRATEGIES to SOLVE a subtraction…

The law of action-reaction (Newton's THIRD law) explains the NATURE of the forces between the two interacting OBJECTS. ACCORDING to the law, the force exerted by object 1 upon object 2 is equal in magnitude and opposite in direction to the force exerted by object 2 upon object 1.

An image that you can SEE in the MIRROR,in water or a SHINY surface.Explanation:MARK me as brainlist

half-sisters hush-hush have the girls have high GRADE girls and boys are high school STUDENTS from the following link and you will have a great weekend too many bad for a while and then you will have a GGG CVCC get the BEST BBC CVCC get good CV get GGG GGG get good CV I get good for GB of RAM be able too much of an issue at all the way to get BACK to you as soon as you can get the chance of getting enough sleep in the past and present to the inbox to the inbox to the inbox by the way

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पेशी (MUSCLE) प्राणियों का आकुंचित होने वाला (CONTRACTILE) ऊतक है। इनमें आंकुंचित होने वाले सूत्र होते हैं जो कोशिका का आकार बदल देते हैं। पेशी कोशिकाओं द्वारा निर्मित उस ऊतक को पेशी ऊतक कहा जाता है जो समस्त अंगों में गति उत्पन्न करता है। इस ऊतक का निर्माण करने वाली कोशिकाएं विशेष प्रकार की आकृति और रचना वाली होती हैं।

Ideal College HOSTEL,Dhaka -1100January 01, 2008My dear Father / mother,I received your kind letter this morning. Thanks a lot for this. Hope you are very well. I am also very fine. you have wanted to know about my hostel life. Now I am TELLING you in a few lines about my hostel life.I reside our college hostel. I enjoy almost all facilities in our modern college hostel. It faces to the south. It is well-airy and well lighted. The design of the hostel is very spectacular. I have to abide by some strict rules which help me to LEAD a disciplined and planned life. We have to GET up at dawn. We take breakfast, lunch and supper in time. We eat rice, fish, eggs, meat, dal, vegetables, khichuri, fruits etc. here. We swim in our college hostel pond. We play in our college playground every afternoon. There is a separate reading room for each student. Our hostel superintendent is our Bangla teacher. He is a very nice man. He loves us as his own children. We always maintain the discipline and the rules of the hostel and try to keep it neat and clean. Really, we are proud of our college hostel. Don’t worry for me. i am quite well. With my best regards to you and mother/ father.your LOVING daughter,MAHIMAplease Mark me as a brainlist

float on a LIQUID when the weight of body is EQUAL to the weight of displaced water. LAW of floatation: Weight of a floating body is equal to the weight of the liquid displaced by it.please MAKE me as a Brainlist

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The four fundamental UNITS are ABBREVIATED as follows: meter, m; kilogram, kg; SECOND, s; and AMPERE, PLEASE mark me as branliest and follow me

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For uniform MOTION, the distance-time graph is a straight LINE PARALLEL to the time axis as speed will be CONSTANT. The distance-time graph for non-uniform motion is not a straight line since speed is variable, it can be a curve or a zigzag line.

With the help of a SUITABLE diagram,explain the meaning of the FOLLOWING terms for concave mirror 1. Centre of CURVATURE 2. ... The PRINCIPAL axis of amirror is a line through the centre of the mirror which passes through its centre of curvature. The pole of the mirror is where the principal axis meets the mirror

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7AExplanation:5+8+3-2-77A:) WELCOME

(b) is scattered the least by smoke or fogExplanation:The danger signals installed at the top of tall buildings are RED in colour because among all other colours, red colour is scattered the least by smoke or fog. This is PRIMARILY because WAVELENGTH of red colour is the LARGEST. Thus it can be EASILY seen from a distance.

direction of acceleration will act DOWNWARD as GRAVITATIONAL FORCE will act downward and acceleration is always in direction of force.

Initial velocity (u) = 0m/s Acceleration (a) = 5m/s²Final velocity (V) = 10m/sTo Find:-Distance (s) covered by the BODY .Solution:-By using 3rd EQUATION of motion → v² = u² +2assubstitute the value we get→ 10² = 0² + 2×5×s→ 100 = 0 + 10×s→ 100 = 10×s→ s = 100/10→ s = 10m∴ The distance covered by the body is 10mHence Option (a) is the CORRECT answer.

tion: Rest - An object is at rest if it's POSITION does not change with passage of TIME w.r.t to OBSERVER.⟶ Motion - An object is at motion if it's position change with passage of time w.r.t to observer

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Shining a torch perpendicular on a paper makes a circular spot. If you tilt the paper, the circle is converted to an ellipse and the area of the spot increases.  To find : How much does the area increase if we tilt the paper by 23 degrees? ​Solution:LET say Circle radius is r   and CENTER is origin x² + y² = r²Area of circle = πr²Paper is tilted at 23° from x axis in z direction Y axis remain UNCHANGED z axis coordinate will be x tan23°hence ellipse area would beDistance of rtan23° from center = √r² + (rtan23°)²= √r²(1 + tan²23°)= √r²sec²23°)= rsec23°Area of ellipse = πab= πrrsec23= πr²sec23°% increase in area =  100 * ( πr²sec23° - πr²)/πr²= 100 ( Sec23° - 1)= 100 (0.08636)= 8.636%8.636%  area increasedLearn more:Find the equation for the ellipse that SATISFIES the given conditions ...brainly.in/question/17176084Area of the GREATEST rectangle inscribed in the ellipse - Brainly.inbrainly.in/question/14037484

prefer to it CHILD!!!!Explanation:Whie absolute COULOMB DEFINED as the amount of electric charge that CROSSES a surface in 1 second when a steady CURRENT of 1 absolute ampere is flowing across the surface. 1 absolute coulomb = 10 coulomb. 1 absolute coulomb = 10 coulomb = 3.00×1010

:we have to FIND the recoil VELOCITY of gun.Solution :Mass of BULLET = 40gm = 0.04kgMass of Gun = 8kgvelocity of bullet = 800m/sAccording to conversation of momentum , momentum of bullet is equals to Momentum of Gun.As we KNOW that,Momentum of Bullet = 0.04 × 800⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 32 kg m/sLet the velocity of Gun is V.momentum of gun = 8v8v = 32v = 32/8v = 4━━━━━━━━━━━━━━━━━━━━━━━━━