* 11. A body starting from rest moving with an acceleration of 5 m/s2 acquires avelocity of 10 m/s. the distance travelled by the body isa. 10mb. 20mc. 50md. 100m

* 11. A body starting from rest moving with an acceleration of 5 m/s

1.	* 11. A body starting from rest moving with an acceleration of 5 m/s2 acquires avelocity of 10 m/s. the distance travelled by the body isa. 10mb. 20mc. 50md. 100m
Answer» Initial velocity (u) = 0m/s Acceleration (a) = 5m/s²Final velocity (V) = 10m/sTo Find:-Distance (s) covered by the BODY .Solution:-By using 3rd EQUATION of motion → v² = u² +2assubstitute the value we get→ 10² = 0² + 2×5×s→ 100 = 0 + 10×s→ 100 = 10×s→ s = 100/10→ s = 10m∴ The distance covered by the body is 10mHence Option (a) is the CORRECT answer.

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* 11. A body starting from rest moving with an acceleration of 5 m/s2 acquires avelocity of 10 m/s. the distance travelled by the body isa. 10mb. 20mc. 50md. 100m​

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* 11. A body starting from rest moving with an acceleration of 5 m/s2 acquires avelocity of 10 m/s. the distance travelled by the body isa. 10mb. 20mc. 50md. 100m