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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
How to people come to an understanding the earth is spherical |
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Answer» Because it is Golaakaar..... |
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| 2. |
Vii) The Integral of VxⓇdx is . |
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| 3. |
Draw a diagram of torch and explain how concave mirror is used as torch light reflector.... |
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| 4. |
The work to be done moving a body fro mass m from height 2R to 3R above the earth surface |
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Answer» Answer: 1/6mgR Explanation:
hence we GET 1/6mgR to my POINT of view if it helps you then give me BRAINLIST plz ok |
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| 5. |
Dall the aboveThree charges q, q, andan equilateral trianis in equilibriumsurface charge densitytime period of small andpassing through itsplane. Moment ofg, and -29 are fixed on the vertices ofteral triangular plate of edge length a. Thisilibrium between two very large plates have density o, and 02, respectively. Find theof small angular oscillation about an axisrough its centroid and perpendicular to theMoment of inertia of the system about this axis isb. 27ElV2qalo, -ol2 Igalo, -021I 281c. 20 )V 3galo, -021d. 2n 28,1Vqalo, -0₂1 |
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| 6. |
Iii) During B decayis Converted intoa) Neutron protonb) Proton, Neutronc) Neutron, Positrond) None of these |
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Answer» During B decay is CONVERTED into. a) Neutron PROTON is yours answer. |
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| 7. |
The displacement of a damped harmonic oscillator is given byx(t) = e⁻⁰·¹ ᵗ cos(10πt + Φ). Here t is in seconds.The time taken for its amplitude of vibration to drop to half of its initial value is close to:(A) 13 s (B) 27 S(C) 4 s (D) 7 s |
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Answer» b Explanation: PLEASE FOLLOW ME |
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| 8. |
A ray of light AO in vacuum is incident on a glass slab at angle 60° and refracted at angle 30° along OB as shown in the figure. The optical path length of light ray from A to B is :(A) 2a + (2b/√3)(B) 2a + (2b/3)(C) (2√3/a) + 2b(D) 2a + 2b |
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| 9. |
N-moles of an ideal gas with constant volume heat capacity Cᵥ undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is(A) nR/(Cᵥ - nR)(B) nR/(Cᵥ + nR)(C) 4nR/(Cᵥ + nR)(D) 4nR/(Cᵥ - nR) |
Answer» The ratio of the work DONE in the process, to the heat supplied = Given: n-MOLES of an ideal gas with constant volume heat capacity Cᵥ undergo an isobaric expansion by certain volume. Find: The ratio of the work done in the process, to the heat supplied. Formula used: In isobaric process W = nRdT Q= n Where W= work done. Q= Heat supplied. dT = change in temperature. R = Universal gas constant. Explanation:
To learn more.... 1) A DIATOMIC ideal gas is heated at constant volume until its pressure is doubled. It is again heated at constant pressure until its volume is doubled. The MOLAR heat capacity for the whole process is kR. Find the value of k. 2)70 calories are required to raise the temperature of 2 moles of an ideal gas at constant pressure from 30°C to 35°C.The amount of heat required (in calories) to raise the temperature of the same gas through the same range (30°C to 35°C) at constant volume is?
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| 10. |
For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127ºC. At 2 atm pressure and at 227ºC, the rms speed of the molecules will be:(A) 80 m/s (B) 80√5 m/s(C) 100 m/s (D) 100√5 m/s |
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Answer» GIVEN : The rms speed of the gas at 1 atm and 400 K ( 127 °C ) = 200 m/s To find : The rms speed of the gas at 2 atm and 500 K ( 227 °C ) . Solution : let rms speed at 500 K is v . rms speed , v Now , at 1 atm and 400 K , 200 = √( 3 * R * 400 / M ) .....(i) at 2 atm and 500 K , v = √( 3 * R * 500 / M ) ......(ii) DIVIDING (ii) by (i) , v / 200 = √ ( 500 / 400 ) => v = ( 200 * √5 ) / 2 => v = 100√5 m/s The rms speed of the gas at 2 atm and 500 K ( 227 °C ) is 100√5 m/s . |
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| 11. |
A current of 5 A passes through a copper conductor (resistivity = 1.7 × 10⁻⁸ Ωm) of radius of cross-section 5 mm. Find the mobility of the charges if their drift velocity is 1.1 × 10⁻³ m/s.(A) 1.8 m²/Vs (B) 1.0 m²/Vs(C) 1.3 m²/Vs (D) 1.5 m²/Vs |
Answer» ANSWER:CORRECT Option is : (B) 1.0 m²/Vs Explanation : |
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| 12. |
A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V. The modulation index and difference between the two side band frequencies are:(A) 4 ; 2 × 10⁸ Hz (B) 4 ; 1 × 10⁸ Hz(C) 0.25 ; 1 × 10⁸ Hz (D) 0.25 ; 2 × 10⁸ Hz |
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Answer» •According to the question, amessage signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V. • So,Fm = 100MHZ = 10^8 MHz (Vm)o = 100V , ( Ve)o =400 V So the modulation index = (Vm)o /( Ve)o = 100/400 = 1/4 = 0.25 UBF or Upper Band Frequency = FE + Fm LBF or Lower Band Frequency= Fe – Fm so,the difference between the two SIDE band frequencies are [UBF — LBF] = 2Fm = 2× 10 ^8 Hz So, the ANSWER is (D) 0.25 ; 2 × 10⁸ Hz
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| 13. |
If a street light of mass m is suspended from the end of rod of length L in different figures |
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Answer» Answer: Explanation: The complete question STATEMENT is ; If a street light of mass M is suspended from the end of uniform rod of length L in the different possible patterns as SHOWN in figure, then which among the three patterns is more sturdy? See attached figure which was also missing. For steady STATE, it is important that we consider EQUILIBRIUM of street light In terms of equillibrium, it can be written as mg×x=T×y T=mgx / y Greater the value of y, LESSER will be T, hence pattern A is more stable |
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| 14. |
Uvalu UIA.James bond is standing on a bridge above the road and his pursuers are getting too close. He spots a flat bedtruck loaded with mattresses approaching at 30 m/s which he measures by knowing that the telephones polesthe truckis passing are 20m apart in this country. The bed of truck is 20 m below the bridge and bond quicklycalculates how many poles away the truck should be when he jumps down the bridge onto the truck makinghis get away. Assume that nearest pole is just below the bridge. How many poles is it? |
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Answer» Answer: 3 poles Explanation: assumption:the truck is point mass having more dimensions! when bond jumps from the bridge: (taking the downward direction as POSITIVE) s=+20 m u=0 a=+10 m/s² thus,s=ut+1/2at² 20=0+1/2*10*t² t=±2 s (but t≠-2) thus,t=2 s in this 2 s,the truck must be at a distance of 30*2 m or,the truck must be at 60 m we KNOW the telephone poles at at SEPARATION of 20 m each. so,the truck must be 60/20=3 poles away when bond JUMPED! |
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| 15. |
How do you derive relation a relation between mechanical equivalent of heat and rotational energy and MS∆T for this question |
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| 16. |
A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of 2.2 kW. If the current in the secondary coils is 10 A, then the input voltage and current in the primary coil are:(A) 440 V and 5 A (B) 440 and 20 A(C) 220 V and 20 A (D) 220 V and 10 A |
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Answer» hope this will HELP you. |
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| 17. |
What is moment of inertia of half circle? |
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Answer» To review, the moment of inertia is the measurement of an object's RESISTANCE to being rotated. The shape we worked with was a SEMICIRCLE with an AXIS perpendicular to its surface through its radius. ... gives US the moment of inertia of our semicircle about an axis perpendicular to its surface through its radius.... i HOPE it helps you ✌☺ |
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| 18. |
The electric field of a plane electromagnetic wave is given by⃗E = E₀î cos(kz) cos(ωt) The corresponding magnetic field ⃗Bis then given by:(A) ⃗B = (E₀/C)jˆ sin(kz) cos(ωt) (B) ⃗B = (E₀/C)kˆ sin(kz) cos(ωt) (C) ⃗B = (E₀/C)jˆ cos(kz) sin(ωt) (D) ⃗B = (E₀/C)jˆ sin(kz) sin(ωt) |
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| 19. |
A uniformly charged ring of radius 3a and total charge q is placed in xy-plane centered at origin. A point charge q is moving towards the ring along the z-axis and has speed v at z = 4a. The minimum value of v such that it crosses the origin is:(A) √(2/m)(1/5 . q²/4π∈₀a)¹/²(B) √(2/m)(1/15 . q²/4π∈₀a)¹/²(C) √(2/m)(4/15 . q²/4π∈₀a)¹/²(D) √(2/m)(2/15 . q²/4π∈₀a)¹/² |
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Answer» Answer: C) √(2/m)(4/15 . q²/4π∈₀a)¹/² will be the right answer |
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| 20. |
A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is (1/16)thof the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is:(A) 2T√(1/10) (B) 2T√(1/14) (C) 4T√(1/15) (D) 4T√(1/14) |
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Answer» Answer: ▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The DENSITY of the liquid is (1/16)th of the material of the bob. If the bob is INSIDE liquid all the time, its period of oscillation in this liquid is: (A) 2T√(1/10) (B) 2T√(1/14) (C) 4T√(1/15) (D) 4T√(1/14)✔ ▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬..________________________.. |
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| 21. |
In a meter bridge experiment, the circuit diagram and the corresponding observation table are shown in figure.Sl. No. R (Ω) l (cm)1. 1000 602. 100 133. 10 1.54. 1 1.0Which of the readings is inconsistent?(A) 4 (B) 3(C) 2 (D) 1 |
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Answer» Answer: 2 OPTION is INCONSISTENT |
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| 22. |
An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance Is 100 Ω and the output load resistance is 10 kΩ. the common emitter current gain β is:(A) 6 × 10²(B) 10²(C) 60 (D) 10⁴ |
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| 23. |
Explain domestic vapor compression refrigerator |
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Answer» Answer: vapour COMPRESSION REFRIGERATOR in which the refrigerant undergoes phase changes, is one of the many refrigeration cycles and is the most widely used METHOD for air-conditioning of buildings and automobiles.its also used in domestic and commercial REFRIGERATORS large -scale ware houses for chilled or frozen storage of foods if it helped u click on THANKS❤️ |
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| 24. |
Why does the sun appear reddish in the morning (as well as evening) |
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Answer» The Sun appears RED during sunrise and sunset because the rays from the Sun has to travel a LONGER distance COMPARED to the noon. Sun rays contain seven colors out of which red color has the highest wavelength. |
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| 25. |
State keepers law of equal area? |
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| 26. |
from the equation Y is equals to R sin 2 pi by Lambda VT minus x establish the relation between particle velocity and wave velocity |
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| 27. |
In the given circuit, an ideal voltmeter connected across the 10 Ω resistance reads 2 V. The internal resistance r, of each cell is:(A) 1 Ω (B) 0.5 Ω(C) 1.5 Ω (D) 0 Ω |
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Answer» answer INTERNAL RESISTANCE for each is C IS ANSWER |
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| 28. |
Two wires A and B are carrying currents I₁ and I₂ as shown in the figure. The separation between them is d. A third wire C carrying a current I is to be kept parallel to them at a distance x from A such that the net force acting on it is zero. The possible values of x are:(A) x = I₁/(I₁ – I₂)d and x = I₂/(I₁+I₂)d(B) x = ± I₂d/(I₁ – I₂)(C) x = I₂/(I₁ + I₂)d and x = I₂/(I₁– I₂)d(D) x = I₁/(I₁ + I₂)d and x = I₂/(I₁– I₂)d |
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Answer» A is RIGHT answer |
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| 29. |
A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbitals in a plane due to magnetic field perpendicular to the plane. Let rₚ, rₑ and ʳHe be their respective radii, then,(A) rₑ > rₚ = ʳHe (B) rₑ > rₚ > ʳHe (C) rₑ < rₚ < ʳHe (D) rₑ < rₚ = ʳHe |
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| 30. |
The value of acceleration due to gravity at Earth’s surface is 9.8 ms⁻². The altitude above its surface at which the acceleration due to gravity decreases to 4.9 ms⁻², is close to: (Radius of earth = 6.4 × 10⁶ m)(A) 6.4 × 10⁶ m (B) 9.0 × 10⁶ m(C) 2.6 × 10⁶ m (D) 1.6 × 10⁶ m |
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| 31. |
Figure shows charge (q) versus voltage (V) graph for series and parallel combination of to given capacitors. The capacitances are:(A) 40 μF and 10 μF(B) 50 μF and 30 μF(C) 60 μF and 40 μF(D) 20 μF and 30 μF |
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| 32. |
Metal get transmitted on reaction with atmosphere air? |
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Answer» Answer: Reaction with air, water and hydrogen The corrosion of SOLID sodium by oxygen ALSO is accelerated by the PRESENCE of small amount of impurities in the sodium.In ordinary air,sodium metal reacts to form a sodium hydroxide film, which can rapidly ABSORB carbon DIOXIDE from the air,forming sodium bicarbonate... |
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| 33. |
Differentiate on both sides |
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Answer» dv=a+2bt+atdt+bt^2dt Explanation: dv/dt=dt(a+2bt)+(at+bt^2)d^2t÷d^2t |
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| 34. |
An a.e. source is rated at 220 V - 50 H. The time taken for voltage to change from itspenk value to zero is(A) 50 sec(B) 0.02 sec(C) 5 sec(D) 5 x 10-³ sec |
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Answer» answer-answer-(A) |
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| 35. |
How to change 2 cm to mm |
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Answer» Answer: (2*10)mm = 20 mm Explanation: |
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| 36. |
The dimensions of light year are:ATB) LT 1C)LDTH |
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Answer» [M^0 L^1 T^0] .............. |
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| 37. |
What are the vectors? give 2 examples of vectors? |
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Answer»
A vectoer is a PHENOMENON in which both direction and magnitude are present. ACCELERATION is also a vector quantity. FORCE is also a vector quantity. |
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| 38. |
What methods could you suggest to prevent misuses of fuelwrong answers will be reported |
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Answer» Ways to Save Fuel Avoid Long Idling. ... Clean Out the Trunk and Eliminate UNNECESSARY Weight. ... Keep Tires INFLATED to the Correct Pressure. ... Don't Buy Premium Fuel. ... Encourage Drivers to Observe Posted Speed LIMITS. ... SHOP Around for Best Fuel Prices. ... Make Drivers Energy Conscious. ... Use Air Conditioning Sparingly. Explanation: |
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| 39. |
What will be the power stored in an inductor connected with AC source ?(A) 1/2Li>2(B) Li2(C) O(D) None of these |
Answer» B) LI2 is the RIGHT answer |
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| 40. |
The ratio of surface tensions of mercury and water is given to be 7.5 while the ratio of their densities is 13.6. Their contact angles, with glass, are close to 135° and 0°, respectively. It is observed that mercury gets depressed by an amount h in a capillary tube of radius r₁, while water rises by the same amount h in a capillary tube of radius r₂. The ratio, (r₁/r₂), is then close to:(A) 3/5 (B) 4/5(C) 2/3 (D) 2/5 |
Answer» HOPE it HELPS you FOLLOW me..... |
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| 41. |
A ball is thrown upward with an initial velocity V₀ from the surface of the earth. The motion of the ball is affected by a drag force equal to mγν²(where m is mass of the ball, v is its Instantneous velocity and γ is a constant). Time taken by the ball to rise to its zenith is:(A) {1/√(γg)} ln{1+ √(γ/g) V₀}(B) {1/√(γg)} tan⁻¹{√(γ/g) V₀}(C) {1/√(γg)} sin⁻¹{√(γ/g) V₀}(D) {1/√(γg)} tan⁻¹{√(γ/g) V₀} |
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Answer» CANT UNDERSTAND that (A) (B) (C) (D) |
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| 42. |
A rectangular coil (Dimension 5 cm × 2 cm) with 100 100 turns, carrying a current of 3 A in the clock-wise direction, is kept centered at the origin and in the X-Z plane. A magnetic field of 1 T is applied along X-axis. If the coil is tilted through 45º about Z-axis, then the torque on the coil is: (A) 0.42 Nm (B) 0.55 Nm(C) 0.27 Nm (D) 0.38 Nm |
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Answer» (C) 0.27 NM the CORRECT answer.. THANKS for the question...,. |
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| 43. |
Two coaxial discs, having moments of inertia I₁ and I₁/2,area rotating with respectively angular velocities ω₁ and ω₁/2, about their common axes. They are brought in contact with each other and thereafter they rotate with a common angular velocity. If Eᶠ and Eᵢ are the final and initial total energies, then (Eᶠ – Eᵢ) is:(A) (I₁ω₁²)/6(B) (3I₁ω₁²)/8(C) (-I₁ω₁²)/12(D) (-I₁ω₁²)/24 |
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| 44. |
A thin disc of mass M and radius R has mass per unit area σ(r) = kr² where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is:(A) MR²/2(B) MR²/3(C) MR²/6(D) 2MR²/3 |
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Answer» Answer: A thin DISC of mass M and radius R has mass per UNIT area σ(r) = kr² where r is the distance from its CENTRE. Its moment of INERTIA about an axis going through its centre of mass and perpendicular to its PLANE is: Option:; (D) 2MR^2/3 |
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| 45. |
A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat needed to raise the temperature of the gas by 20°C is: [Given that R = 8.31 J mol⁻¹ K⁻¹](A) 350 J (B) 700 J(C) 748 J (D) 374 J |
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Answer» The amount of heat NEEDED to RAISE the temperature of GAS by 20°c is 748J Given 1.capacity of cylinder is 67.2 litre R=8.31 J mol⁻¹ K⁻¹ 2.Q=nCvΔT now n=67.2/22.4 He is MONOATOMIC gas so cv=f/2R=3/2R Q=67.2/22.4*3/2R*20=748J |
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| 46. |
Displacement of a body can be zero even when the distance travelled is not zero explain |
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Answer» Displacement is BASICALLY the shortest distantce between the initial point and the final point....so this can be explained USING an example...consider a pathetic 100M long...u covered this 100m and then u RETURNED to ur initial position.....so ur distance will be 200m...but displacement....as u can see will be 0....why?...bcoz the final position is same as initial position....so the shortest distance between these TWO positions will obviously be 0m...I hope you got the point! |
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| 47. |
Does surface tension act within the inside of a liquid |
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Answer» Answer: According to this theory, COHESIVE forces among LIQUID MOLECULES are responsible for the phenomenon of surface tension. The molecules well inside the liquid are attracted equally in all DIRECTIONS by the other molecules. ... So, a network is formed against the inward pull, in order to move a molecule to the liquid surface. |
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| 48. |
Determine the charge on the capacitor in the following circuit:(A) 200 μC (B) 60 μC(C) 10 μC (D) 2 μC |
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Answer» The charge on the capacitance can be CALCULATED as below: |
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| 49. |
Two particles, of masses M and 2M, moving as shown, with speeds of 10 m/s and 5 m/s, collide elastically at the origin. After the collision, they move along the indicated directions with speeds v₁ and v₂ respectively. The value of v₁ and v₂ are nearly:(A) 3.2 m/s and 12.6 m/s(B) 6.5 m/s and 6.3 m/s(C) 6.5 m/s and 3.2 m/s(D) 3.2 m/s and 6.3 m/s |
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Answer» HEY mate ,yr answer.. m1u1 + m2U2= m1v1 +m2v2 M(10) +2M(5) = M V1 + 2Mv2 10M + 10M = M(v1 + 2V2) 20M / M = v1 + 2v2 20 - 2v2 = v1 v1 = 20 - 2 (3.2 ) ...............( 3.2 is bcoz I used option first ) v1 = 20 _ 6.4 v1 = 13 .6 hence first option is correct to some extent other options are very FAR .... And it is 13.6 INSTEAD of 12.6 |
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| 50. |
Given below in the left column are different modes of communication using the kinds of waves given in the right column.A. Optical Fibre Communication P. UltrasoundB. Radar Q. Infrared LightC. Sonar R. MicrowavesD. Mobile Phones S. Radio WavesFrom the options given below, find the most appropriate match between entries in the left and the right column. (A) A – S, B – Q, C – R, D – P (B) A – Q, B – S, C – P, D – R(C) A – R, B – P, C – S, D – Q (D) A – Q, B – S, C – R, D – P |
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Answer» it is APPROPRIATE 'c' Explanation: c=a-r, b-p, c-s, d-q |
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