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The welfare of individuals, sustainable development of countries, and the life-supporting capacity of the global ecosystem depends on energy resources.
Energy supplies, particularly OIL, are strategically important for industrial development and military weaponry. They help to increase national power. A nation endowed with sufficient energy resources can make its will prevail over the others.
The importance of energy security became evident after the first and second oil shock in October 1973 and 1979 respectively. The oil crisis showed the dependence of the industrialized world on the strategic raw materials from the Third World countries. It was recognized that oil is a powerful factor in global politics and governments should pay more attention to it.
People realized that conflict should be replaced by cooperation in order to ensure energy security. The International Energy Agency or IEA was created which played an important role in building negotiation platforms and making rules to limit the autonomy of governments and oil companies.
Oil is a natural resource which is limited in quantity and is non-renewable in the economic sense. Alternatives to oil are being developed but they are not a viable replacement for oil. This creates economic interdependence between the nations.
The ability to obtain enough energy supplies at a reasonable cost is an important aspect of energy security.
In the future, energy resources may be in greater demand due to population and economic growth. This may lead to more conflicts.
The IEA which consists of 29 OECD member countries plays an important role in international energy cooperation. But its capacity to secure global cooperation is limited because the major developing countries are not its members. So there is a need for more collaboration and open markets in energy policy. Multilateral cooperation is extremely necessary for the stability of energy markets and a PEACEFUL evolution of the international system.
Collaborated EFFORTS to conserve energy in order to meet its increasing demand can go a long way in ensuring international peace and security.

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The WORD "period" means SOMETHING very specific, and is not the same thing as an oscillation in either meaning. A "period" is not the act of swinging, but the time for a complete cycle of the oscillation (from maximum to maximum). Usually denoted with units of seconds (or seconds PER cycle if you like)....
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ANSWER ⇒ Option (d). 4 TIMES.

Explanation ⇒

Let the Original VELOCITY, mass and the kinetic ENERGY of the BODY be v, m and K₁ respectively.

∴ K = 1/2 × mv² -----eq(i)

Now,

If the velocity becomes 2 times of the original, then new velocity = 2v

∴ New Kinetic Energy = 1/2 × m(2v)²

⇒ K₂ = 1/2 × mv² × 4

⇒ K₂ = K₁ × 4 [From eq(i)]

⇒ K₂ = 4K₁

Hence, the kinetic energy becomes 4 times of the original.

Hope it helps.

This is the ANSWER. L HOPE it will HELP you.

The DENSITY of the OBJECT will be 2.5 g/cm³

The GRAVITATIONAL force=Gm.m/r^2=G.6400/4=1600G

The bending ABILITY of a medium is known as the REFRACTIVE index.

There are two TYPES of spherical mirrors
convex and concave
all the VIRTUAL images formed by either PLANE or spherical mirrors are laterally inverted

KINETIC energy of an object is defined as the energy that it possesses due to its motion.

It is also described as the work required to accelerate a body of a given unit of mass from rest to its stated velocity.

Derivation:

Let us consider an object of mass " m " UPON which Force "F" is acting and let the object from rest move from point A to point B to COVER a displacement "S".

We know,

Work done = Force x displacement

W= FxS ____(1)

An equation of motion--- V^2 -U^2 =2aS

S= V^2 -U^2/2a ______(2)

Newtons SECOND law of motion--- F= ma

We derive from equation 1 and 2,

W= m*a* (V^2- U^2)/2a

u=0 as object is at rest

W=m*V^2/2

WORK Done is the kinetic energy of the body.

K.E = (1/2 )mv^2

This is because he EXERTS PRESSURE on his LEGS for a LONG TIME

Let after time t the bus will over the car.

let s be the distance travelled by the bus to overtake the car.

For bus : As a = 5 m/s^2 ; u = 0 m/s

so, s = u t + 1/2 a t^2

or, s = 0 + 1/2 ×5 × t^2

so, s = 5/2 t^2

Also, the distance travelled by the car in the same time t with v = 50 m/s

d = v t = 50 × t

As both s and d is the same distance

so, s = d

or, 5/2 t^2 = 50 t

or, t^2 - 20 t = 0

or, t ( t - 20 ) = 0

so, t = 20 s ; { 0 s NEGLECTED }

As v = u + a t

so, velocity of bus after 20 s

v = 0 + 5 × 20 = 100 m/s

the bus will be TRAVELLING then at a speed of

100 m/s.

I have tried my level best of there's any MISTAKE PLZZ UPDATE me

Let two FORCES be A & B, and the RESULTANT be P.

A + B = 16

P2 = B2 – A2 = (B – A)(B + A)  = 16(B – A)

(B - A) = P2/16 = 4

B – A = 16

B + A = 4

2B = 12

B = 6N

A = 10N

The FORCE is CALLED : CONTACT force

(a) Distance travelled = 10km
= 10 × 1000 m
= 10 × 1000 × 100cm
= 1000000cm

TIME taken = 5 minutes
= 5 × 60
= 300S

speed = {distance travelled}/{time taken}
speed = {1000000}/{300}
= 3333cm/s

(b) Distance travelled = 10km
= 10 × 1000m
= 10000M

Time taken = 5 minutes
= 5× 60
= 300 s

speed = {distance travelled}/{time taken}

speed = {10000}/{300} = 33 m/s

While GETTING down from a moving vehicle a person should always run in the same DIRECTION as thar of the vehicle because initially the person has the momentum same as that of the moving vehicle when he is boarding the BUS.

DUE to this momentum the person will tend to move forward in the direction of the motion due to the inertia of motion.

If the person tries to get down without doing that he will unknowingly change the inertia suddenly but his momentum will not let him do so and he MIGHT fall.

As changing momentum causes force in the direction of motion and so he will experience a force which will make him fall.

So, it is always adviced to do so while getting down a moving bus.

Rest is a STATE in physics that refers to an object being STATIONARY relative to a PARTICULAR FRAME of reference or another object; when the position of abody with respect to its surroundings does not CHANGE with time it is said to be "at rest".

Answer ⇒ No.

Explanation ⇒

We know that the Potential energy is dependent upon the chosen configuration. One is FREE to choose the zero Potential energy configuration SINCE, the origin is choose arbitrarily.

Hence, the Potential energy is DEPENDING upon the chosen configuration.

In the GIVEN case, It may be Possible that both the Person have chosen different configuration.

Hence, No one of them is wrong.

Hope it helps.

If the forces are acting in the opposite directions of the BODY then the RESULTANT force is 4 dyne - 3 dyne = 1 dyne
If the forces are acting in the same DIRECTION on the body then the resultant force is 4 dyne + 3
dyne = 7 dyne 
so your answer is option D. BTW 1 and 7 dyne.

When you roll a ball on the ground, the electrons in the atoms on the surface of the ground PUSH against the electrons in the atoms on the surface of your ball that is TOUCHING the ground. A rolling ball STOPS because the surface on which it ROLLS RESISTS its motion. A rolling ball stops because of friction.

4m/sis The VELOCITY of the SECOND BODY

total work on the object = force * DISTANCE = mgh

change in kinetic energy = work DONE = 0.5mv(final)^2 - 0.5mv(INITIAL)^2 = mgh.

Assuming initial velocity is zero:

0.5mv(final)^2 = mgh --> v(final) = sqrt(2gh).

The wire's volume stays the same, so the new cross-sectional AREA is 1/3 the ORIGINAL. Resistance is directly proportional to wire LENGTH and INVERSELY proportional to the cross-sectional area. Thus, by tripling the length and reducing the cross-sectional area to 1/3 the original, the resistance is now 9 times the original, or 27 OHMS.

Answer:

d1 * d2 / [ d1 + d2 ].

Explanation:

We will get the horizontal component to be  as X = U cosФ*t = u t/√2 since the value of the Ф is = π/4 and, the distance  y = u sinФ  t - 1/2 g  t^2 will be equal to =  u/√2 - 1/2 g t^2

Again we know that the y = x  - g x^2 / u^2  since the value of the tanФ = 1  and cosФ =1/√2.

If we take x = d1,  y = H to be the height of the pole.

h = d1 - g d1^2 / u^2 ....(1)

Now from the question, when  x = d1 + d2 and the value of y = 0.

Hence,  0 = (d1+d2) - g (d1 + d2)^2/u^2.  

u^2 = g (d1 + d2)  ...(2)

Now if we substitute the EQUATION (2) in (1) we will get:

h = d1 - d1^2/(d1+d2) = d1 * d2  / (d1 + d2).

So on solving we will get the value as  d1 * d2 / [ d1 + d2 ].

17x35= 1S2 2S2 2P6 3S2 3p5
Y= 1s2 2s2 2P2

Frequency=speed of light/wavelength.
=3*10^8/6*10-7=10^15/2=5*10^14s^-1

1÷f=1÷u+1÷V where v is the OBJECT,

N chemistry , the pH scale measures how acidic or ALKALINE something is. Generally speaking, the pH value of water does not directly affect human health , although it can have an indirect effect by corroding PLUMBING, which leaches metals into the water . Only when water is contaminated with another substance can the pH reach an especially high or low level , but even then , the pH value ALONE doesn' t determine whether water is safe to drink .
Theinitials"pH" standfor"potentialof hydrogen"; theH is capitalizedbecauseit's thechemicalsymbolfor hydrogen. In scientificterms, thepHscalemeasuresthe relativeconcentrationsof hydrogenionsandhydroxyl ionsin a substance. Whenhydrogenionsoutnumber hydroxylions, thesubstanceis acidic; whenhydroxyl ionshavetheedge, thesubstanceis alkaline.
ThepHscalerunsfrom0 to 14. A pHof 7 is "neutral," meaningthetwotypesof ionsarein balance, sothe substanceis neitheracidicnoralkaline. Valuesbelow7 areacidic, with0 beingthemostacidic. Valuesabove7 arealkaline, with14beingthemostalkaline. Battery acidhasa pHof about0. Liquiddraincleanerhasa pH of about14. Distilled, filteredwaterhasa pHof about7. Eachunitwithinthescalerepresentsa tenfoldincrease in acidityor alkalinity.
Waterfoundin naturewillgenerallyhavea pHbetween 6.5 and8.5, dependingon geologicalandatmospheric conditions. Accordingto theUniversityof MassachusettsandtheWaterSystemsCouncil, thepH of drinkingwaterisnota healthissue. Water's pHvalue cangetneitherhighenoughnorlowenoughto posea hazard. HOWEVER, if thewateris contaminated, thepH maybesignificantlyhigherorlower. BUTIT's thenature of thecontaminantnot thepHvaluethatdetermines whetherthewateris unsafeto drink. Lemonjuice, for example, is extremelyacidic, witha pHof about2, while milkof magnesiais quitealkaline, witha pHbetween10 and11-- yetbotharesafeto consume.
TheEnvironmentalProtectionAgencyclassifiesa pH valueabove8.5 or below6.5 as a "secondary contaminant" in drinkingwater. However, theeffectsof highor lowpH, theEPAstates, aremainly"aesthetic" -- thatis, relatedto tasteandodor. Waterwitha lowpH canhavea metallic, bitterorsourtaste; waterwitha highpHcanhavea baking-sodataste. In addition, pH outsidetheEPA-recommendedrangecandamage plumbing. Acidicwatercancorrodepipes; alkalinewater canformscalydeposits. LIVESTRONG.COM • FOOD AND DRINK • BEVERAGES • WATER
What pH in Water Is Too High for Human Consumptions

Because THIN GLASS can EASILY ABSORB HEAT

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RANGE R = 2u/g

and

Max.


Height, H =u^2/2g

Divide the Range and Height we get,

R/H = 4/u

u = 4H/R m/s is the speed of projection.





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Ajay
B.Tech,IIT(BHU)VARANASI

A

angle between a and B is 90

The ANSWER is 50 SECONDS.

What is thiissssssssssss?

Speed of boy in first 20 min = 18 km/

As d = v × t

so, distance travelled by the boy in first 20 min

= 20/60h × 18 km/h = 6 km

let the speed for next 40 min be v km/h

so, distance travelled will be 40/60h × v kmph

= 2v/3 km

So, total distance = 6 + 2v/3 km

total time = 20 + 40 min = 60 min = 1 h

As average speed = total distance/total time

so, 24 = (6 + 2v/3)/1 = (18 + 2v)/3

or, 24×3 = 18 + 2v

or, 2v = 72 - 18 = 54

so, v = 54/2 = 27 km/h

So, he should RUN at a speed of 27 km/h for 40 minutes so that his average speed be 24 km/h.

A convex mirror forms an erect diminished virtual image for all the positions of the object placed in front of it.

A convex mirror is used as rear VIEW mirrors in AUTOMOBILES, as reflectors in STREET light bulbs and in parking lots.

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In the figure shown SEGMENT of a straight wire carrying current I is lying along Y-axis. There is a point ‘ P ’ where magnetic field due to this wire is to be calculated.



For the sake of convenience we CHOOSE the FOOT of perpendicular from P to the current carrying wire as origin.

Idl→ is a current element at a distance l from O. Let point P lie in x-y PLANE and r→ is the position vector of point ‘ P ‘ with respect to Idl→ . From figure r→= Ri^ − lj^ . Here i^ and j^ have usual meanings.

Magnetic field at point P due to the current element Idl-> is



Here dB→ is directed along negative Z-axis. The directions of at point P for all elements are same.



This is the general expression for the magnetic field due to straight current.

Now we discuss the different cases.

Case I:

If the wire extends to infinity on either side of ‘ O ‘ then

θ1 = θ2 = π/2 and hence



Case II:

If length of the wire is finite say ‘ L ‘ and P lies on right bisector of wire, then θ1 = θ2 = θ



In this way we can find magnetic field at any point due to straight current.