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When the speed of a ball is doubled its kinetic energy(a) Remains same (b) gets doubled(c) Becomes half (d) becomes 4 times |
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Answer» Explanation ⇒ Let the Original VELOCITY, mass and the kinetic ENERGY of the BODY be v, m and K₁ respectively. ∴ K = 1/2 × mv² -----eq(i) Now, If the velocity becomes 2 times of the original, then new velocity = 2v ∴ New Kinetic Energy = 1/2 × m(2v)² ⇒ K₂ = 1/2 × mv² × 4 ⇒ K₂ = K₁ × 4 [From eq(i)] ⇒ K₂ = 4K₁ Hence, the kinetic energy becomes 4 times of the original. Hope it helps. |
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