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Actually you can represent TIME in x or y AXIS.But as a CONVENTION, we are representing it on x axis, as it is more suitable for our visualisation

In my textbook, it says that the maximum NUMBER of electrons that can FIT in any given shell is given by 2n². This would mean 2 electrons could fit in the first shell, 8 could fit in the SECOND shell, 18 in the third shell, and 32 in the fourth shell.However, I was previously taught that the maximum number of electrons in the first ORBITAL is 2, 8 in the second orbital, 8 in the third shell, 18 in the fourth orbital, 18 in the fifth orbital, 32 in the sixth orbital. I am fairly sure that orbitals and shells are the same thing.Which of these two methods is correct and should be used to find the number of electrons in an orbital?I am in high school so please try to simplify your answer and use fairly basic terms.Explanation:each orbital can only hold two electrons.because one spin up and one spin down.

100mthe VALUE of 10 SQUARE m is 100M

Hey mate here's your answerA process carried out in such a manner that the system, UNDERGOING the change, does not exchange heat with the surroundings is CALLED an adiabatic process. The temperature of the system changes during the adiabatic process. e.g. expansion of a GAS in a VACUUM.

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y – Time Graph of an object moving with UNIFORM ACCELERATION. When velocity – time graph is plotted for an object moving with uniform acceleration, the slope of the graph is a STRAIGHT line. The PATTERN of slope of the graph shows that object is moving with uniform acceleration.

a) Production of washing soda: Washing soda is produced from sodium chloride (or common salt) in the following three steps:(i) A cold and concentrated solution of sodium chloride (called BRINE) is reacted with ammonia and carbon dioxide to obtain sodium hydrogen carbonate :Sodium hydrogencarbonate formed is only slightly SOLUBLE in water, so it precipitates out as a solid.(ii) Sodium hydrogencarbonate is separated by filtration, dried and heated. On HEATING, sodium hydrogencarbonate decomposes to form sodium carbonate:The anhydrous sodium carbonate obtained here is called soda ash.(iii) Anhydrous sodium carbonate (soda ash) is dissolved in water and recrystallised to get washing soda crystals containing 10 molecules of water of crystallisation :(b) An aqueous solution of washing soda is alkaline because it turns red litmus to BLUE.(c) Washing soda has detergent properties because it can remove dirt and grease from dirty clothes.(d) (i) It is used as cleansing agent for domestic purposes.(ii) It is used for REMOVING permanent hardness of water.

Explanation: Derivation Of Equation Of Motion It is first important to understand what is motion and its laws to understand the derivations better. Following is the table explaining more concepts related to motion Introduction to Motion Equation Of Motion And Its Application Derivation of Equation of Motion There are mainly three equations of motion which describe the relationship between velocity, time, acceleration and displacement. First, consider a body moving in a straight line with uniform acceleration. Then, LET the initial velocity be u, acceleration be a, time period be t, velocity be v, and the distance travelled be S. The equation of motions derivation can be done in three ways which are: Derivation of equations of motion by Simple Algebraic Method Derivation of Motion by Graphical Method Derivation of Motion by Calculus Method Below, the equations of motion are derived by all the three methods in a simple and easy to understand WAY. Derivation of First Equation of Motion The first equation of motion is: v = u + at Derivation of First Equation of Motion by Algebraic Method It is known that the acceleration (a) of the body is defined as the rate of change of velocity. So, the acceleration can be written as: a = v − ut From this, rearranging the terms, the first equation of motion is obtained, which is: v = u + at Derivation of First Equation of Motion by Graphical Method Consider the diagram of the velocity-time graph of a body below: Derivation Of Equation Of Motion In this, the body is moving with an initial velocity of u at point A. The velocity of the body then changes from A to B in time t at a uniform rate. In the above diagram, BC is the final velocity i.e. v after the body travels from A to B at a uniform acceleration of a. In the graph, OC is the time t. Then, a perpendicular is drawn from B to OC, a PARALLEL line is drawn from A to D, and another perpendicular is drawn from B to OE (represented by dotted lines). Following details are obtained from the graph above: The initial velocity of the body, u = OA The final velocity of the body, v = BC From the graph,BC = BD + DC So, v = BD + DC v = BD + OA (since DC = OA) Finally, v = BD + u (since OA = u) (Equation 1) Now, since the slope of a velocity-time graph is equal to acceleration a, So, a = slope of line AB a = BD/AD Since AD = AC = t, the above equation becomes: BD = at (Equation 2) Now, combining Equation 1 & 2, the following is obtained: v = at + u Derivation of First Equation of Motion by Calculus Method It is known that, Derivation Of Equation Of Motion So, Derivation Of Equation Of Motion Derivation of Second Equation of Motion The second equation of motion is: S = ut + ½ a2 Derivation of Second Equation of Motion by Algebraic Method Consider the same notations for the derivation of the second equation of motion by simple algebraic method. Derivation Of Second Equation Of Motion Derivation of Second Equation of Motion by Graphical Method Taking the same diagram used in first law derivation: Derivation Of Equation Of Motion In this diagram, the distance travelled (S) = Area of figure OABC = Area of rectangle OADC + Area of triangle ABD. Now, the area of the rectangle OADC = OA × OC = ut And, Area of triangle ABD = (1/2) × Area of rectangle AEBD = (1/2) at2 (Since, AD = t and BD = at) Thus, the total distance covered will be: S = ut + (1/2) at2 Derivation of Second Equation of Motion by Calculus Method It is known that v = dS/dt.‘ So, Derivation Of Equation Of Motion Derivation of Third Equation of Motion The third equation of motion is: v2 = u2 + 2aS Derivation of Third Equation of Motion by Algebraic Method Derivation Of Third Equation Of Motion Derivation of Third Equation of Motion by Graphical Method Derivation Of Equation Of Motion The total distance travelled, S = Area of trapezium OABC. So, S=(SumofParallelSides)×Height2 S=(OA+CB)×OC2 Since, OA = u, CB = v, and OC = t The above equation becomes S=(u+v)×t2 Now, since t = (v – u)/ a The above equation can be written as: S=(u+v)×(v–u)2a Third equation of motion is obtained by solving the above equation: v2 = u2+2aS Derivation of Third Equation of Motion by Calculus Method It is known that, Derivation Of Equation Of Motion These were the detailed derivations for equations of motion in the graphical method, algebraic method and calculus method

B) 25Explanation:Let the distance between the source of SOUND and the OBSTACLE be x metres .Thus the distance travelled by sound to reach back to the source d=2xAs the minimum time required to HEAR an ECHO is EQUAL to 0.1secThus d=vt2x=500(0.1)⟹x=25mI hope it was helpful for you... If yes mark it as brainliest...

there is not GIVEN FIRST TERM and differenceExplanation:what is your QUESTION

not. TWO vectors with the same MAGNITUDE (including units) and the same direction, are equal. ... You are free to slide a vector PARALLEL to itself without CHANGING its value, since you're KEEPING the magnitude and direction the same

alled the Lagrange point and may be calculated by equating the gravitational law of the Moon and Earth. The Lagrange point is where the gravitational pull of the Earth equals the gravitational pull of the Moon. It is safe to ignore the gravitational pull of the Sun because the centre of mass of Earth and Moon is traveling at APPROXIMATELY 67,000 miles per hour, thus canceling the pull of the Sun with centripetal force. Any object, which leaves the Earth or Moon, retains this velocity. Assume the Lagrange point is a distance R from centre of the Moon and that the distance between the Earth’s centre and the Moon’s centre is D, therefore, the gravitational laws for the two masses can be equated; G is the gravitational constant and m is the mass STATIONARY in the Lagrange point; Mm is the mass of the Moon and Me is mass of the Earth, hence: G x Mm x m/(R^2) = G x Me x m/[(D - R)^2] … (1) The G, and m cancel and it is known that the Earth is approximately 81 times the mass of the Moon, therefore, Me/Mm = 81 (a dimensionless number) The equation at (1) reduces to: (D - R)^2/(R^2) = 81 Square root both sides and with an approximate value for D of 245,000 miles, then: (D - R)/R = 9 or D - R = 9R or D = 10R, Therefore, the distance (R) of the Lagrange point from centre of the Moon is 24,500 miles. The radius of the Moon is about 1000 miles and so the distance of the Lagrange point from surface of the Moon is about 23,500 miles. Note also that the Lagrange point will be along the straight LINE connecting the centres of the Earth and Moon and, as the Moon orbits the Earth, the Lagrange point will also move CORRESPONDINGLY. As stated above the system of the Earth , Moon, their barycentre or centre of gravity, and the Lagrange point are moving at about 67,000 mph in orbiting the Sun.

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The electric lines of force that represent the field of a POSITIVE electric CHARGE in space CONSIST of a family of straight lines radiating uniformly in all DIRECTIONS from the charge where they originate. A SECOND positive charge placed in the field would travel radially away from the first charge.

his is an INTERESTING QUESTION ! SOLUTION is in this given attachment wait .OPTION "a" is correct option _______________________ Hope it's helpful .

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when it's PARTICLES are distrube It's is very dengerous

CO3-hope you UNDERSTAND my WORDS

6 ohmsExplanation: consider the unknown resistance to be x and then SOLD the entire QUESTION for X you will GET the ANSWER at 6 ohms.

Gibbs Free ENERGY (G) - The energy associated with a chemical reaction that can be USED to do WORK. The free energy of a system is the sum of its enthalpy (H) plus the product of the temperature (Kelvin) and the ENTROPY (S) of the system: Free energy of reaction ( G)

To Derive :Formula for ORBITAL Velocity.Concept:Orbital Velocity is a Velocity used to define the trajectory and Velocity of NATURAL and artificial SATELLITES going around celestial bodies.Examples: Telecommunication SatellitesNavigation satellitesProof:When a satellite is revolving around another celestial body , the Centripetal force is attributed to the gravitational force between the 2 bodies.Let mass of satellite be m , it's Velocity be v , mass of the planet be M , Universal Gravitational constant be G and radius of the planet be rCancelling the equal terms on both sides , we get :This is the orbital Velocity of the satellite.Points to note:Orbital Velocity at a CERTAIN height doesn't depend on the mass of the satelliteIt depends on the mass of planet.

hope it helps UU ☺️☺️Explanation:PLEASE MARK as the BRAINLIEST

No yaar, ENERGY CHANGE will take PLACE when FORCE is applied on a BODY

What-are phases, phasor DIAGRAM, time diagram and impedance diagram?→ A quantity which varies with time and REPRESENTED by the projection of a rotating vector, is called a phasor. » Alternating e.m.f. and current arephasors.→ The diagram representing the PHASORS and phase angle between them, is called phasor diagram.→ The graph is showing the variation of V (Potential difference) or I (Current) with time t in terms of wt (w = omega) KNOWN as time diagram.→ It is geometrical method to determine the effective impedance of an a.c. circuit. The right angled triangle is used to determine effective impedance hypotenuse of the triangle give the value of effective impedance.Hope it helped u.

note on Hertz's experiment for the production of EM waves (electromagnetic WAVE).?→ Hertz's experiment was based on the PRINCIPLE that a vibrating electric charge radiates electromagnetic waves. The experimental arrangement is shown in the figure provided with the answer ( Check the attachment given with this answer ) .→ There are two large metallic PLATES A and B connected to an induction coil. Two metallic SPHERES I and I' are connected to metallic plates. These spheres are separated by a small air GAP. There is production of spark between the spheres. This spark gives rise to oscillations which ends out electromagnetic waves.Hope it helped u.

Explanation:1Kwh = 1000 * 1W * (60 * 60)s          = 1000 * 3600          = 3.6 * 10^6J

r earth to be a sphere of mass M, radius R with centre at O. Let g be the VALUE of acceleration due to gravity at a POINT A on the surface of earth. .....(1)If g' is the acceleration due to gravity at a point B, at a height h above the surface of earth, then the force on the body at B is due to earth whose mass M is concentrated at the centre O of earth. .....(2)Dividing EQ. (2) by Eq. (1), we get.....(3)If h<

The house wiring should be done parallel because, in parallel connection there will be more ADVANTAGES than a series connection.Let a house is wired in series and it contains a fan, tube light, TV, refrigerator. All the devices are CONNECTED in series. Now, due to some disturbance the fan speed working or it burned. Then since the connection was a series, due to one appliance failure causes the whole circuit to fail. If it is burned that means it making an OPEN circiut. Then there will be no current flow in the circuit.Now if it was a parallel connection as we know already, the parallel connection is nothing but individual appliances connected to the same line by TAPPINGS. That means there's no dependency of one appliance on another. So if an appliance fail or burns it doesn't effects the remaining appliances. And there will be uninterrupted supply to the healthy appliances can be achieved.So we use parallel connection for house wiring.HOPE IT HELPS MAKE ME BRAINLIEST

In a cyclic process the system returns to its initial STATE and so the internal ENERGY is not changed. The HEAT ADDED to the system EQUALS the work done by the system. A free expansion is an adiabatic change that does no work.

tion:The Planck CONSTANT (Planck's constant) links the AMOUNT of energy a photon carries with the frequency of its electromagnetic wave. It is NAMED after the PHYSICIST Max Planck. It is an important quantity in quantum physics. ... In SI units, the Planck constant is expressed in joule SECONDS (J⋅s) or (N⋅m⋅s)

re is DIAGRAM??????but where is diagram??????

The FIRST laser was built in 1960 by Theodore H. Maiman at Hughes Research Laboratories, based on theoretical work by CHARLES Hard Townes and ARTHUR LEONARD Schawlow.

1.We can say that the volume of the object is directly PROPORTIONAL to its mass. As the volume INCREASES the mass of the object increases in direct proportion2.We can say that the volume of the object is directly proportional to its mass.     As the volume increases the mass of the object increases in direct proportion.3. density is directly proportional to the mass (or weight) and INDIRECTLY proportional to the volume: If volume STAYS the same as mass increases, the density will increase by the same factor. If volume stays the same as mass decreases, the density will decrease by the same factor.

We define average coefficent of LINEAR EXPANSION in the temperature range ΔT as:α¯=1LΔLΔTThe coefficient of linear expansion at temperature T is the limit of average coefficient as ΔT→0, i.e.,α=limΔT→01LΔLΔT=1LdLdTSuppose the length of a rod at 0∘C is L0, and at temperature θ (MEASURED in Celsius) is Lθ. If α is SMALL and constant over given temperature interval,α=Lθ−L0L0θ

6Explanation:(2i-j).(3i+k)2i.3i - j.3i + k.2i - k.j6i^2-0 +0 -06i^26 ×1=6because i.i =i^2 =1

Photon Energies and the Electromagnetic Spectrum | Physics A photon is a quantum of EM radiation. Its energy is GIVEN by E = HF and is related to the frequency f and wavelength λ of the radiation by. E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , where E is the energy of a single photon and c is the SPEED of light.

hey mate your is as followsExplanation:The word जागरूकता MEANS awarenessexamples of awareness1) There MUST be AWARENESS among people regarding water conservation

the ANSWER for your QUESTION is 4000Å to 8000Å