67486 + Interview Questions in Secondary School in Physics

1.	Which physical quantity is given by the area under the velocity - time graph and time axis
Answer» Answer: In a velocity time GRAPH: 2) The area under the velocity time graph GIVES the displacement of the object. It is mathematically POSSIBLE to CALCULATE the displacement of an object from the velocity time graph.

1.

Which physical quantity is given by the area under the velocity - time graph and time axis

Answer»

Answer:

In a velocity time GRAPH:

2) The area under the velocity time graph GIVES the displacement of the object. It is mathematically POSSIBLE to CALCULATE the displacement of an object from the velocity time graph.

Discussion

2.	In electric heating appliances the Material of the heating element is
Answer» Nichrome. USED in making heating elements for electric heaters and furnaces. Nichrome is best SUITABLE and ideal MATERIAL for making heating element. ... When the heating element is heated first time, chromium of alloy react with oxygen of atmosphere and FORM a layer of chromium oxide on outer surface of heating element. HOPE IT HELPS. PLEASE MARK ME BRAINLIEST AND FOLLOW ME.

2.

In electric heating appliances the Material of the heating element is

Answer»

Nichrome. USED in making heating elements for electric heaters and furnaces. Nichrome is best SUITABLE and ideal MATERIAL for making heating element. ... When the heating element is heated first time, chromium of alloy react with oxygen of atmosphere and FORM a layer of chromium oxide on outer surface of heating element.

HOPE IT HELPS. PLEASE MARK ME BRAINLIEST AND FOLLOW ME.

Discussion

3.	Will give 70 points who will answer from 6 to 10
Answer» Answer: kzdtksgksgksgkygk threw it away from the bottom of the African AMERICAN Horror Story SEASON ONE EPISODE is it a Z E up and down the road to

3.

Will give 70 points who will answer from 6 to 10

Answer»

Answer:

kzdtksgksgksgkygk threw it away from the bottom of the African AMERICAN Horror Story SEASON ONE EPISODE is it a Z E up and down the road to

Discussion

4.	A car travels a certain distance for 45 minutes with the velocity of 40 km per hour and then a distance for 30 minute with the velocity of 60 kilometre per hour in the same directionCalculate : 1. total distance travelled by a car2.total time of journey in hours3.average velocity of the car
Answer» speed =distance/ TIME distance=1800 km 1 st case speed = distance/ time =1800km 2nd case total distance =3600 km total time of journey is = 1hour 15 mins AVERAGE velocity =total distance/total time TAKEN =3600/115 minutes =now divide and you will get your answer

4.

A car travels a certain distance for 45 minutes with the velocity of 40 km per hour and then a distance for 30 minute with the velocity of 60 kilometre per hour in the same directionCalculate : 1. total distance travelled by a car2.total time of journey in hours3.average velocity of the car

Answer»

speed =distance/ TIME

distance=1800 km 1 st case

speed = distance/ time

=1800km 2nd case

total distance =3600 km

total time of journey is = 1hour 15 mins

AVERAGE velocity =total distance/total time TAKEN

=3600/115 minutes

=now divide and you will get your answer

Discussion

5.	What is the necessity of flitched beam?
Answer» Answer: They ( FLITCH Beams ) were USED as a cost-effecient way to strengthen long span of WOODEN beams, and have been LARGELY supplanted by more recent technological advances

5.

What is the necessity of flitched beam?

Answer»

Answer:

They ( FLITCH Beams ) were USED as a cost-effecient way to strengthen long span of WOODEN beams, and have been LARGELY supplanted by more recent technological advances

Discussion

6.	the speed of light in air is 310 power 8 m/s. in medium x, speed is 210 power of 8 and in medium y the speed is 2.5*10 power 8 calculate the refractive index of x in air, y in x, y in air
Answer» ANSWER: iisjeoeneo ek2no WEEKEND d DDK

6.

the speed of light in air is 310 power 8 m/s. in medium x, speed is 210 power of 8 and in medium y the speed is 2.5*10 power 8 calculate the refractive index of x in air, y in x, y in air

Answer»

ANSWER:

iisjeoeneo ek2no WEEKEND d DDK

Discussion

7.	Derivation of Snells law in short formplease say the answer fast
Answer» ANSWER: HEY mate☺❤✌ Explanation: *HOPE* It *Helps*✌❤☺

7.

Derivation of Snells law in short formplease say the answer fast

Answer»

ANSWER:

HEY mate☺❤✌

Explanation:

HOPE It Helps✌❤☺

Discussion

8.	Two angles are called adjacent if they lines
Answer» Answer: Two ANGLES are Adjacent when they have acommon SIDE and a COMMON vertex (corner POINT) and don't OVERLAP. Because: they have acommon side (line CB) they have a common vertex (point B)

8.

Two angles are called adjacent if they lines

Answer»

Answer:

Two ANGLES are Adjacent when they have acommon SIDE and a COMMON vertex (corner POINT) and don't OVERLAP. Because: they have acommon side (line CB) they have a common vertex (point B)

Discussion

9.	identify A B and C write the functions of each which among the following helps in accommodation of eye and how it adjust the focal length
Answer» ANSWER: PLS COMPLETE the QUESTION

9.

identify A B and C write the functions of each which among the following helps in accommodation of eye and how it adjust the focal length

Answer»

ANSWER:

PLS COMPLETE the QUESTION

Discussion

10.	electric bulb consumes 10kg joule electrical of energy in 4 minutes what is the power of electrical bulb
Answer» EXPLANATION: $energy = \frac{<klux>POWER</klux>}{time}$ *Given* E=10 kg t=4×60= *240* *SEC. So, $10 = \frac{p}{240}$ Therefore, Power* =*2400* *watts*

10.

electric bulb consumes 10kg joule electrical of energy in 4 minutes what is the power of electrical bulb

Answer»

EXPLANATION:

$energy = \frac{<klux>POWER</klux>}{time}$

Given E=10 kg

t=4×60= 240 SEC.

So,

$10 = \frac{p}{240}$

Therefore, Power =2400 watts

Discussion

11.	Which physical quantity is given by the slope of the velocity - time graph
Answer» Answer: ACCELERATION acceleration a=v/t hence the SLOPE IVES acceleration HOPE it helps

11.

Which physical quantity is given by the slope of the velocity - time graph

Answer»

Answer:

ACCELERATION

acceleration a=v/t

hence the SLOPE IVES acceleration

HOPE it helps

Discussion

12.	10) A body is acted upon by to forces each of magnitude F, but in opposite direction. The separation between two bodies are „r‟. Thenwhat is the value of resultant force and moment of force?
Answer» Answer: moment of FORCE is force X DISTANCE of MAGNITUDE

12.

10) A body is acted upon by to forces each of magnitude F, but in opposite direction. The separation between two bodies are „r‟. Thenwhat is the value of resultant force and moment of force?

Answer»

Answer:

moment of FORCE is force X DISTANCE of MAGNITUDE

Discussion

13.	AnMAMAN(RAB) ?Net=2
Answer» MAN is the CORRECT ANSWER please mark as brainleast

Discussion

14.	Which formula can be used when a light ray enters a medium with Refractive index n2 from a medium with Refractive index n1 at curved radius of curvature R?
Answer» ANSWER: (a+b)2 Explanation: mathamatially do this

14.

Which formula can be used when a light ray enters a medium with Refractive index n2 from a medium with Refractive index n1 at curved radius of curvature R?

Answer»

ANSWER:

(a+b)2

Explanation:

mathamatially do this

Discussion

15.	How are heat and light produced in the sun?
Answer» Answer: HEAT in the SUN is PRODUCED by the process of CHEMICAL reaction TAKING place in sun

15.

How are heat and light produced in the sun?

Answer»

Answer:

HEAT in the SUN is PRODUCED by the process of CHEMICAL reaction TAKING place in sun

Discussion

16.	The Sun is a hot plasma (ion-ized matter) with its inner coreat a temperature exceeding 107K, and its outer surface at atemperature of about 6000 K.At these high temperatures, nosubstance remains in a solidor liquid phase. In what rangedo you expect the mass densityof the Sun to be, in the rangeof densities of solids and liquidsor gases? Check if your guess iscorrect from the following data:mass of the Sun = 2.0 x 10³⁰ kg,radius of the Sun = 7.0 x 10⁸ m.
Answer» $\fbox{\texttt{\green{Answer:}}}$ Density of the SUN = $\bold{1391.8\:kgm^{-3}}$ (in the range of densities of SOLIDS and liquids) $\fbox{\texttt{\pink{Given:}}}$ Mass (M) of the sun = $\bold{2.0\times{}10^{30}\:kg.}$ Radius (R) of the sun = $\bold{7.0\times{}10^{8}\:m.}$ $\fbox{\texttt{\blue{To\:find:}}}$ Mass density of the Sun. $\fbox{\texttt{\red{How\:to\:Find:}}}$ We know mass of the sun, M = $\bold{2.0\times{}10^{30}\:kg.}$ Radius of the sun, R = $\bold{7.0\times{}10^{8}\:m.}$ ∴ Volume of the sun, $\bold{V=\frac{4}{3}\pi\:R^{3}}$ $\bold{=\frac{4}{3}\pi(7.0\times{}10^{8})^{3}}$ $\bold{=1.437\times{}10^{27}\:m^{3}}$ Now, density of the sun, $\bold{\rho\:=\dfrac{M}{V}=\dfrac{2.0\times{}10^{30}}{1.437\times{}10^{27}}}$ $\bold{=1391.8\:kgm^{-3}}$ The density of the sun is in the range of the densities of the solids and liquids and not gases. The high density of the sun (in the form of hot PLASMA) is due to INWARD gravitational attraction on the outer LAYERS due to the inner layers of the sun.

16.

The Sun is a hot plasma (ion-ized matter) with its inner coreat a temperature exceeding 107K, and its outer surface at atemperature of about 6000 K.At these high temperatures, nosubstance remains in a solidor liquid phase. In what rangedo you expect the mass densityof the Sun to be, in the rangeof densities of solids and liquidsor gases? Check if your guess iscorrect from the following data:mass of the Sun = 2.0 x 10³⁰ kg,radius of the Sun = 7.0 x 10⁸ m.

Answer»

$\fbox{\texttt{\green{Answer:}}}$

Density of the SUN = $\bold{1391.8\:kgm^{-3}}$ (in the range of densities of SOLIDS and liquids)

$\fbox{\texttt{\pink{Given:}}}$

Mass (M) of the sun = $\bold{2.0\times{}10^{30}\:kg.}$

Radius (R) of the sun = $\bold{7.0\times{}10^{8}\:m.}$

$\fbox{\texttt{\blue{To\:find:}}}$

Mass density of the Sun.

$\fbox{\texttt{\red{How\:to\:Find:}}}$

We know mass of the sun,

M = $\bold{2.0\times{}10^{30}\:kg.}$

Radius of the sun, R = $\bold{7.0\times{}10^{8}\:m.}$

∴ Volume of the sun,

$\bold{V=\frac{4}{3}\pi\:R^{3}}$

$\bold{=\frac{4}{3}\pi(7.0\times{}10^{8})^{3}}$

$\bold{=1.437\times{}10^{27}\:m^{3}}$

Now, density of the sun,

$\bold{\rho\:=\dfrac{M}{V}=\dfrac{2.0\times{}10^{30}}{1.437\times{}10^{27}}}$

$\bold{=1391.8\:kgm^{-3}}$

The density of the sun is in the range of the densities of the solids and liquids and not gases.

The high density of the sun (in the form of hot PLASMA) is due to INWARD gravitational attraction on the outer LAYERS due to the inner layers of the sun.

Discussion

17.	Series circuit with a resistance of 100ohm is connected to an ac source of 200 V and angular frequency300 rad/s. When only capacitor is removed, the current lags behind the voltage by 60°. When only theinductor is removed the current leads the voltage by 60°. The average power dissipated is(1) 50 W(2) 100 W(3) 200 W(4) 400 W
Answer» ANSWER: Here, R=100Ω,Eυ=200 volt, ω=300rad/s When capacitor is removed, tanϕ=XLR=tan60∘=3–√ XL=3–√R Z=(R2+(XL−XC)2) =1002+0−−−−−−−√=100Ω Iυ=EυZ=200100=2A P=EυIυcosϕ=EυIυ(RZ) =(200)(2)×100100=400W Explanation:

17.

Series circuit with a resistance of 100ohm is connected to an ac source of 200 V and angular frequency300 rad/s. When only capacitor is removed, the current lags behind the voltage by 60°. When only theinductor is removed the current leads the voltage by 60°. The average power dissipated is(1) 50 W(2) 100 W(3) 200 W(4) 400 W

Answer»

ANSWER:

Here, R=100Ω,Eυ=200 volt, ω=300rad/s

When capacitor is removed,

tanϕ=XLR=tan60∘=3–√

XL=3–√R

Z=(R2+(XL−XC)2)

=1002+0−−−−−−−√=100Ω

Iυ=EυZ=200100=2A

P=EυIυcosϕ=EυIυ(RZ)

=(200)(2)×100100=400W

Explanation:

Discussion

18.	A capacitor of capacity 4F is charged to SOV andanother capacitor of capacity 6F is charged to30V. When they are connected. then the energylost by Apulf capacitori(1) 7.8 m(2) 46 m() 3.2 ml(4) 2.5 m
Answer» EXPLANATION: HEAT loss will be, $heat = \frac{1}{2} \frac{c1 \times c2}{c1 + c2} {(v1 - v2)}^{2}$ Here, c1 =4F c2= 6F V1= 50V V2= 30V Solving, we will GET heat loss=480 JOULE

18.

A capacitor of capacity 4F is charged to SOV andanother capacitor of capacity 6F is charged to30V. When they are connected. then the energylost by Apulf capacitori(1) 7.8 m(2) 46 m() 3.2 ml(4) 2.5 m

Answer»

EXPLANATION:

HEAT loss will be,

$heat = \frac{1}{2} \frac{c1 \times c2}{c1 + c2} {(v1 - v2)}^{2}$

Here, c1 =4F

c2= 6F

V1= 50V

V2= 30V

Solving, we will GET heat loss=480 JOULE

Discussion

19.	an athlete completes one round of a circular track of diameter 200m in 40 second what will be the distance covered and the displacement at the end of 2 minutes 20 second
Answer» Answer: ANSWER The diameter of the circular track is given as 200 m. That is, 2r=200 m. From this radius is calculated as Radius, r = 100 m. In 40 sec the athlete complete ONE round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds. One round is considered as the circumference of the circular track. The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m. For each complete round the displacement is ZERO. Therefore for 3 complete rounds, the displacement will be zero. At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m. Hence, the distance covered is 2200 m and the displacement is 200 m. Explanation: pls FOLLOW me

19.

an athlete completes one round of a circular track of diameter 200m in 40 second what will be the distance covered and the displacement at the end of 2 minutes 20 second

Answer»

Answer:

ANSWER

The diameter of the circular track is given as 200 m. That is, 2r=200 m.

From this radius is calculated as Radius, r = 100 m.

In 40 sec the athlete complete ONE round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.

One round is considered as the circumference of the circular track.

The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.

For each complete round the displacement is ZERO. Therefore for 3 complete rounds, the displacement will be zero.

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Hence, the distance covered is 2200 m and the displacement is 200 m.

Explanation:

pls FOLLOW me

Discussion

20.	What you mean by focal point of spherical refracting surface
Answer» EXPLANATION: The refracted ray passes through the FOCAL point. • A ray that passes through the focal point. – The refracted ray is PARALLEL to the CENTRAL axis. • A ray that passes through the CENTER of curvature.

20.

What you mean by focal point of spherical refracting surface

Answer»

EXPLANATION:

The refracted ray passes through the FOCAL point. • A ray that passes through the focal point. – The refracted ray is PARALLEL to the CENTRAL axis. • A ray that passes through the CENTER of curvature.

Discussion

21.	What is the SI unit of volume.
Answer» ANSWER: m^3 is the SI UNIT of VOLUME

21.

What is the SI unit of volume.

Answer»

ANSWER:

m^3 is the SI UNIT of VOLUME

Discussion

22.	QUESTION: 22 When a hot body is placed in contact with coldbody.The energy of hot body increasesThe energy of cold body decreasesThe energy of hot body decreases while energyof cold body increasesEnergy of both body increases
Answer» ANSWER: The energy of hot body decreases while energy of COLD body increases Explanation: Newton's cooling law: dt dθ =−k(θ−θ 0 )

22.

QUESTION: 22 When a hot body is placed in contact with coldbody.The energy of hot body increasesThe energy of cold body decreasesThe energy of hot body decreases while energyof cold body increasesEnergy of both body increases

Answer»

ANSWER:

The energy of hot body decreases while energy

of COLD body increases

Explanation:

Newton's cooling law:

dt

dθ

=−k(θ−θ

0

)

Discussion

23.	Arrange the following speed in increasing order:1) 72km/hr2) 25m/sec3)1.5km/min
Answer» for deciding the ORDER of the speed you must bring all the TERMS in ONE UNIT 72km/HR<25m/s<1.5km/min.

23.

Arrange the following speed in increasing order:1) 72km/hr2) 25m/sec3)1.5km/min

Answer»

for deciding the ORDER of the speed you must bring all the TERMS in ONE UNIT

72km/HR<25m/s<1.5km/min.

Discussion

24.	Question 3 : - If an object is at 10 meters from starting position, after 5seconds it was found to be 20 meters from starting point. What is velocity of the object.
Answer» Answer: velocity is 2m/s Explanation: velocity=distance /TIME distance TRAVELLED is 20-10=10 given time 5 sec v=10/5 =2 hope this is CORRECT answer if not pls REPORT me

24.

Question 3 : - If an object is at 10 meters from starting position, after 5seconds it was found to be 20 meters from starting point. What is velocity of the object.

Answer»

Answer:

velocity is 2m/s

Explanation:

velocity=distance /TIME

distance TRAVELLED is 20-10=10

given time 5 sec

v=10/5

=2

hope this is CORRECT answer if not pls REPORT me

Discussion

25.	.Connect two resistors of 4 Ω each in such a way to get equivalent resistance of 2 Ω.
Answer» ANSWER: in PARALLEL COMBINATION

25.

.Connect two resistors of 4 Ω each in such a way to get equivalent resistance of 2 Ω.

Answer»

ANSWER:

in PARALLEL COMBINATION

Discussion

26.	For a fish inside the water an object falling exactly vertically, above it appears to be
Answer» ANSWER: FARTHER AWAY from it Explanation:

26.

For a fish inside the water an object falling exactly vertically, above it appears to be

Answer»

ANSWER:

FARTHER AWAY from it

Explanation:

Discussion

27.	Find the Resistance at AB, BC & AC ....
Answer» Answer: AB 8 ohm BC 7 ohm AC 5 ohm Explanation: as they are in series so answer will be this only

27.

Find the Resistance at AB, BC & AC ....

Answer»

Answer:

AB 8 ohm

BC 7 ohm

AC 5 ohm

Explanation:

as they are in series so answer will be this only

Discussion

28.	What do you know about the terms a) Focus and b)Focal Plane?
Answer» ANSWER: this the answer of your QUESTIONS

28.

What do you know about the terms a) Focus and b)Focal Plane?

Answer»

ANSWER:

this the answer of your QUESTIONS

Discussion

29.	How many types of current are available to us
Answer» EXPLANATION: There are two types of current i.e.Direct current and Alternating current.

29.

How many types of current are available to us

Answer»

EXPLANATION:

There are two types of current

i.e.Direct current and Alternating current.

Discussion

30.	A car moving in a horizontal circular track of radius 10 cm with a constant speed of 36 km per hour a simple pendulum is suspended from the Roof of the car if the length of the simple pendulum is 1 metre what is the angle made by the string with the track
Answer» These is your ANSWER #staysafe#stayhome

Discussion

31.	A bus moving along a straight line at 20 m/s undergoes an acceleration of 4 metre per second square.After 2 seconds ,its speed will be:
Answer» $using \: first \: equation \: of \: motion \: \\ v = u + at$ where v=final velocity u=initial velicity a=acceleration t=time v=20+4(2) v=20+8 final velocity=28m/s

31.

A bus moving along a straight line at 20 m/s undergoes an acceleration of 4 metre per second square.After 2 seconds ,its speed will be:

Answer»

$using \: first \: equation \: of \: motion \: \\ v = u + at$

where

v=final velocity

u=initial velicity

a=acceleration

t=time

v=20+4(2)

v=20+8

final velocity=28m/s

Discussion

32.	Hey... plzz solve these 2 questions ..........
Answer» ANSWER: Sore I have not SOLVED this PROBLEM REALLY sort

32.

Hey... plzz solve these 2 questions ..........

Answer»

ANSWER:

Sore I have not SOLVED this PROBLEM REALLY sort

Discussion

33.	What is visible spectrum
Answer» Answer: it is *combination* of *seven* *color* *vibgyor* *visible* *SPECTRUM* is a *ELECTROMAGNETIC* *radiation* *which* *are* *SEEN* by *naked* *eyes* *and* *that* is *found* in *rainy* *with* *sunny* *day* *and* *also* to *PASS* *white* *LIGHT* *from* *the* *spectrum*

33.

What is visible spectrum

Answer»

Answer:

it is combination of seven color vibgyor visible SPECTRUM is a ELECTROMAGNETIC radiation which are SEEN by naked eyes and that is found in rainy with sunny day and also to PASS white LIGHT from the spectrum

Discussion

34.	1.Calculate equivalent resistance of 5 ohm, 10 ohm,30 ohm(a)when connected in series(b)when connected in parallel
Answer» ANSWER:SERIES - 45OHM , PARALLEL - 3 ohm Explanation:

34.

1.Calculate equivalent resistance of 5 ohm, 10 ohm,30 ohm(a)when connected in series(b)when connected in parallel

Answer»

ANSWER:SERIES - 45OHM , PARALLEL - 3 ohm

Explanation:

Discussion

35.	Draw the situation in which light ray don't deviates from it's path
Answer» ANSWER: _________________⚡

35.

Draw the situation in which light ray don't deviates from it's path

Answer»

ANSWER:

_________________⚡

Discussion

36.	Who carries current? In solid and liquid
Answer» Answer: HEYA! Solids as Current carriers In solids free ELECTRONS CARRY current. These electrons are free to MOVE around freely. Consider Copper (Cu) ATOMIC number = 29. A conducting liquid or electrolyte contain ions that is positively charged and negatively charged ions. The flow of these ions conduct electricity through the conducting liquid or electrolyte. The solution of acids ,bases and salts in water are electrolyte pls mark it as brainlist answer

36.

Who carries current? In solid and liquid

Answer»

Answer:

HEYA!

Solids as Current carriers

In solids free ELECTRONS CARRY current. These electrons are free to MOVE around freely. Consider Copper (Cu) ATOMIC number = 29.

A conducting liquid or electrolyte contain ions that is positively charged and negatively charged ions. The flow of these ions conduct electricity through the conducting liquid or electrolyte. The solution of acids ,bases and salts in water are electrolyte

pls mark it as brainlist answer

Discussion

37.	Tab and ask it out you question s
Answer» ANSWER: what................

37.

Tab and ask it out you question s

Answer»

ANSWER:

what................

Discussion

38.	In feedback process explain how input impedance and output impedance varies with respect to input and output voltage and current at each type of feedback circuit.
Answer» Answer: Feedback Systems In a Feedback System, all or part of the output signal either positive or negative is fed back to the input Feedback Systems PROCESS signals and as such are signal processors. The processing part of a feedback system may be electrical or electronic, ranging from a very simple to a highly complex circuits. Simple analogue feedback control circuits can be constructed using individual or discrete components, such as transistors, resistors and capacitors, etc, or by using microprocessor-based and integrated circuits (IC’s) to form more complex digital feedback systems. As we have seen, OPEN-loop systems are just that, open ended, and no attempt is made to compensate for changes in circuit conditions or changes in load conditions due to variations in circuit parameters, such as gain and stability, temperature, supply voltage variations and/or external disturbances. But the effects of these “open-loop” variations can be eliminated or at least considerably reduced by the introduction of Feedback. A feedback system is one in which the output signal is sampled and then fed back to the input to form an ERROR signal that drives the system. In the previous tutorial about Closed-loop Systems, we saw that in general, feedback is comprised of a sub-circuit that allows a fraction of the output signal from a system to modify the effective input signal in such a way as to produce a response that can differ substantially from the response produced in the absence of such feedback. Feedback Systems are very useful and widely used in amplifier circuits, oscillators, process control systems as well as other types of electronic systems. But for feedback to be an effective tool it must be controlled as an UNCONTROLLED system will either oscillate or fail to function. The basic model of a feedback system is given as: Feedback System Block Diagram Model feedback systems block diagram This basic feedback loop of sensing, controlling and actuation is the main concept behind a feedback control system and there are several good REASONS why feedback is applied and used in electronic circuits: Circuit characteristics such as the systems gain and response can be precisely controlled. Circuit characteristics can be made independent of operating conditions such as supply voltages or temperature variations. Signal distortion due to the non-linear nature of the components used can be greatly reduced. The Frequency Response, Gain and Bandwidth of a circuit or system can be easily controlled to within tight limits.

38.

In feedback process explain how input impedance and output impedance varies with respect to input and output voltage and current at each type of feedback circuit.

Answer»

Answer:

Feedback Systems

In a Feedback System, all or part of the output signal either positive or negative is fed back to the input

Feedback Systems PROCESS signals and as such are signal processors. The processing part of a feedback system may be electrical or electronic, ranging from a very simple to a highly complex circuits.

Simple analogue feedback control circuits can be constructed using individual or discrete components, such as transistors, resistors and capacitors, etc, or by using microprocessor-based and integrated circuits (IC’s) to form more complex digital feedback systems.

As we have seen, OPEN-loop systems are just that, open ended, and no attempt is made to compensate for changes in circuit conditions or changes in load conditions due to variations in circuit parameters, such as gain and stability, temperature, supply voltage variations and/or external disturbances. But the effects of these “open-loop” variations can be eliminated or at least considerably reduced by the introduction of Feedback.

A feedback system is one in which the output signal is sampled and then fed back to the input to form an ERROR signal that drives the system. In the previous tutorial about Closed-loop Systems, we saw that in general, feedback is comprised of a sub-circuit that allows a fraction of the output signal from a system to modify the effective input signal in such a way as to produce a response that can differ substantially from the response produced in the absence of such feedback.

Feedback Systems are very useful and widely used in amplifier circuits, oscillators, process control systems as well as other types of electronic systems. But for feedback to be an effective tool it must be controlled as an UNCONTROLLED system will either oscillate or fail to function. The basic model of a feedback system is given as:

Feedback System Block Diagram Model

feedback systems block diagram

This basic feedback loop of sensing, controlling and actuation is the main concept behind a feedback control system and there are several good REASONS why feedback is applied and used in electronic circuits:

Circuit characteristics such as the systems gain and response can be precisely controlled.

Circuit characteristics can be made independent of operating conditions such as supply voltages or temperature variations.

Signal distortion due to the non-linear nature of the components used can be greatly reduced.

The Frequency Response, Gain and Bandwidth of a circuit or system can be easily controlled to within tight limits.

Discussion

39.	What is the source of charging a body ?
Answer» Answer: *The* *source of charging* a *BODY* is *conduction.If* we *BRING* a *neutral body* *close* to *charged* *body* *then* *the* *body* *will* be *charged*. Also by rubbing process. Hope it HELPS you**.

39.

What is the source of charging a body ?

Answer»

Answer:

The source of charging a BODY is conduction.If we BRING a neutral body close to charged body then the body will be charged.

Also by rubbing process.

Hope it HELPS you.

Discussion

40.	Who invented portable handset and when
Answer» ANSWER: Hey mate...... Your answer is here.......⬇️ Martin Cooper invented portable handset. Hope it HELPS U..... Plzz mark it as brainliest answer.....

40.

Who invented portable handset and when

Answer»

ANSWER:

Hey mate......

Your answer is here.......⬇️

Martin Cooper invented portable handset.

Hope it HELPS U.....

Plzz mark it as brainliest answer.....

Discussion

41.	An air bubble in water behaves like a converging lens.How would you justify it?
Answer» Answer: $\huge \boxed{Answer}$ The air bubble inside water behaves like a Concave LENS. This is because The normal at any POINT of a SPHERICAL bubble will pass through the center of the bubble. It is clearly visible that theair bubble ACTS as a DIVERGING lens.

41.

An air bubble in water behaves like a converging lens.How would you justify it?

Answer»

Answer:

$\huge \boxed{Answer}$

The air bubble inside water behaves like a Concave LENS. This is because The normal at any POINT of a SPHERICAL bubble will pass through the center of the bubble. It is clearly visible that theair bubble ACTS as a DIVERGING lens.

Discussion

42.	Ymr. kale travels 5km towardsmest troms left and travek 3kmand then travels another 1 kmto reach a church.How faris he from the starting position in Kilometres? I
Answer» Answer:2 km Explanation:

42.

Ymr. kale travels 5km towardsmest troms left and travek 3kmand then travels another 1 kmto reach a church.How faris he from the starting position in Kilometres? I

Answer»

Answer:2 km

Explanation:

Discussion

43.	What is interplanetary space?
Answer» Answer: interplanetary space in British English (ˌɪntəˈplænɪtərɪ speɪs) astronomy. the REGION of spaceoccurring around the sun and planets of the SOLAR system. The density is NORMALLY NEGLIGIBLE although cosmic rays, METEORITES, gas clouds, etc, can occur. hope this helps you plz mark as brainliest answer #rocket....

43.

What is interplanetary space?

Answer»

Answer:

interplanetary space in British English

(ˌɪntəˈplænɪtərɪ speɪs) astronomy. the REGION of spaceoccurring around the sun and planets of the SOLAR system. The density is NORMALLY NEGLIGIBLE although cosmic rays, METEORITES, gas clouds, etc, can occur.

hope this helps you

plz mark as brainliest answer

#rocket....

Discussion

44.	Other name for negative acceleration.
Answer» ANSWER: retardation.........is the correct answer..... MARK as BRAINIEST..... follow me..

44.

Other name for negative acceleration.

Answer»

ANSWER:

retardation.........is the correct answer..... MARK as BRAINIEST..... follow me..

Discussion

45.	Write LEP and UFP values on Fahrenheit scale
Answer» EXPLANATION: LEP =32 F UFP=212 F values on FAHRENHEIT SCALE

45.

Write LEP and UFP values on Fahrenheit scale

Answer»

EXPLANATION:

LEP =32 F

UFP=212 F

values on FAHRENHEIT SCALE

Discussion

46.	10) A body is acted upon by to forces each of magnitude F, but inopposite direction. The separation between two bodies are „r‟. Thenwhat is the value of resultant force and moment of force?
Answer» ANSWER: the value of RESULTANT is (NET) and movement is non zero as it is UNBALANCED FORCES

46.

10) A body is acted upon by to forces each of magnitude F, but inopposite direction. The separation between two bodies are „r‟. Thenwhat is the value of resultant force and moment of force?

Answer»

ANSWER:

the value of RESULTANT is (NET)

and movement is non zero as it is UNBALANCED FORCES

Discussion

47.	A quantity of hot water at 91 degree Celsius and another cold one at 12 degree celsius. How much kilogram of each one is needed to make an 800 liter of water bath at 35 degree celsius? hint; mc (T2-T1) solve for m NOTE mh + mc = 800 kg
Answer» Answer: can you love me please say YES U RIGHT 4TH and

47.

A quantity of hot water at 91 degree Celsius and another cold one at 12 degree celsius. How much kilogram of each one is needed to make an 800 liter of water bath at 35 degree celsius? hint; mc (T2-T1) solve for m NOTE mh + mc = 800 kg

Answer»

Answer:

can you love me please say YES U RIGHT 4TH and

Discussion

48.	A particle travels at a constant velocity of 3ms–1 for 20s. Then it stops for 10s before completingits journey in another 30s at a constant velocity of 2 ms–1. Its average velocity for the wholejourney is [ ]a) 2 ms–1 b) 2.4 ms–1 c) 2.7 ms–1 d) 3 ms–1
Answer» Given : Velocity FOT FIRST 20 sec = 3m/s Velocity fot another 30 sec = 2m/s To find : Average velocity for the whole journey = ? Solution : DISTANCE travelled in first 20 sec Distance = speed × Time = 20 × 3 = 60m Distance travelled in another 30 sec Distance = speed × Time = 30 × 2 = 60m Average velocity = Total distance travelled / Time taken = 60 + 60 / (30+20+ 10) =120 / 60 = 2m/s The average velocity of the particle is 2m/s

48.

A particle travels at a constant velocity of 3ms–1 for 20s. Then it stops for 10s before completingits journey in another 30s at a constant velocity of 2 ms–1. Its average velocity for the wholejourney is [ ]a) 2 ms–1 b) 2.4 ms–1 c) 2.7 ms–1 d) 3 ms–1

Answer»

Given :

Velocity FOT FIRST 20 sec = 3m/s

Velocity fot another 30 sec = 2m/s

To find :

Average velocity for the whole journey = ?

Solution :

DISTANCE travelled in first 20 sec

Distance = speed × Time

= 20 × 3

= 60m

Distance travelled in another 30 sec

Distance = speed × Time

= 30 × 2

= 60m

Average velocity = Total distance travelled / Time taken

= 60 + 60 / (30+20+ 10)

=120 / 60

= 2m/s

The average velocity of the particle is 2m/s

Discussion

49.	How do we measure potential difference
Answer» Answer:To measure the potential difference across a component, a voltmeter MUST be PLACED in parallel with that component in order to measure the difference in energy from one side of the component to the other. HOPE IT HELPED YOU THANK YOU...:)

49.

How do we measure potential difference

Answer»

Answer:To measure the potential difference across a component, a voltmeter MUST be PLACED in parallel with that component in order to measure the difference in energy from one side of the component to the other.

HOPE IT HELPED YOU

THANK YOU...:)

Discussion

50.	A uniform but time varying magnetic field exists in cylindrical region and directed into the paper. If field decreases with time and a positive charge is placed at any point inside the region, then it moves :-(1)along 1(2)along 2(3)along 3(4)along 4
Answer» The positive charge placed at any point inside the region moves along the arrow 4 The magnetic field is decreasing in the circuit, the INDUCED electric field should be increasing in LOOP. The increase in induced emf in the loop produces current which flows in clock-wise direction. If a positive PARTICLE is placed at any point it also will MOVE in clockwise direction i.e., along the direction of arrow 4.

50.

A uniform but time varying magnetic field exists in cylindrical region and directed into the paper. If field decreases with time and a positive charge is placed at any point inside the region, then it moves :-(1)along 1(2)along 2(3)along 3(4)along 4

Answer»

The positive charge placed at any point inside the region moves along the arrow 4

The magnetic field is decreasing in the circuit, the INDUCED electric field should be increasing in LOOP.

The increase in induced emf in the loop produces current which flows in clock-wise direction.

If a positive PARTICLE is placed at any point it also will MOVE in clockwise direction i.e., along the direction of arrow 4.

Discussion

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pls mark it as brainlist answer

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hope this helps you

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