1.

Series circuit with a resistance of 100ohm is connected to an ac source of 200 V and angular frequency300 rad/s. When only capacitor is removed, the current lags behind the voltage by 60°. When only theinductor is removed the current leads the voltage by 60°. The average power dissipated is(1) 50 W(2) 100 W(3) 200 W(4) 400 W

Answer»

ANSWER:

Here, R=100Ω,Eυ=200 volt, ω=300rad/s

When capacitor is removed,

tanϕ=XLR=tan60∘=3–√

XL=3–√R

Z=(R2+(XL−XC)2)

=1002+0−−−−−−−√=100Ω

Iυ=EυZ=200100=2A

P=EυIυcosϕ=EυIυ(RZ)

=(200)(2)×100100=400W

Explanation:



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