Saved Bookmarks
| 1. |
Series circuit with a resistance of 100ohm is connected to an ac source of 200 V and angular frequency300 rad/s. When only capacitor is removed, the current lags behind the voltage by 60°. When only theinductor is removed the current leads the voltage by 60°. The average power dissipated is(1) 50 W(2) 100 W(3) 200 W(4) 400 W |
|
Answer» Here, R=100Ω,Eυ=200 volt, ω=300rad/s When capacitor is removed, tanϕ=XLR=tan60∘=3–√ XL=3–√R Z=(R2+(XL−XC)2) =1002+0−−−−−−−√=100Ω Iυ=EυZ=200100=2A P=EυIυcosϕ=EυIυ(RZ) =(200)(2)×100100=400W Explanation: |
|