67486 + Interview Questions in Secondary School in Physics

1.	What does the slope of v- t graph indicate
Answer» ONG>ANSWER: Slope of v-t graph gives :- Acceleration. Explanation: slope MEANS y coordinate/ x coordinate = v/t = ACC

1.

What does the slope of v- t graph indicate

Answer» ONG>ANSWER:

Slope of v-t graph gives :- Acceleration.

Explanation:

slope MEANS y coordinate/ x coordinate

= v/t = ACC

Discussion

2.	A bulb is rated at 220V, 200W. What is its resistance
Answer» ong>Answer: P=v²/R, v=220 R=? P=200w Therefore: 200w=220²v/R = 200R=220² =200R=48400 R=48400/200 R=242ohms Explanation:* *Hiii* *dude* *this* is *your* *answer* *Please* *MARK me* *in BRAINLIST*

2.

A bulb is rated at 220V, 200W. What is its resistance

Answer»

ong>Answer:

P=v²/R, v=220

R=?

P=200w

Therefore: 200w=220²v/R

= 200*R=220²

=200R=48400

R=48400/200

R=242ohms

Explanation:

Hiii dude this is your answer

Please MARK me in BRAINLIST

Discussion

3.	او3h +2 2 and B = 31+ j+2E then sind vector produceA x B²
Answer» ONG>ANSWER: chxhfudududiojfjsiffoklslsuddi

Discussion

4.	The areas of pistons in a hydraulic machine are 5 centimetre square and 250 centimetre square. What force on the smaller piston will port a load of 1250 N on the larger piston?10 N15 N20 N25 N
Answer» uzotsiz7ra74q3y4q7xlxgzufzits59s6psori6s6osyspyoetisw7

Discussion

5.	A protons resembles a hydrogen ion is it true or false
Answer» s a FALSE statement. plz MARK as BRAINLIST and FOLLOW me

5.

A protons resembles a hydrogen ion is it true or false

Answer»

s a FALSE statement.

plz MARK as BRAINLIST and FOLLOW me

Discussion

6.	A heater rated at and , calculate: a) Currentb) Energy consumed in 2 hoursc) Cost if is priced at `4.60/-
Answer» ENT ENERGY CONSUMED in 2 HOUR

Discussion

7.	वाह! तुमने तो कमाल कर दिया। (निषेधवाचक वाक्य में बदलिए \| )
Answer» ONG>ANSWER: vaiha thumna THO KAMAL

Discussion

8.	Some political parties join hands to form government .This type government is called –
Answer» ong>ANSWER: coalition GOVERNMENT Explanation: mark me brainlist and FOLLOW me DEAR

8.

Some political parties join hands to form government .This type government is called –

Answer»

ong>ANSWER:

coalition GOVERNMENT

Explanation:

mark me brainlist and FOLLOW me DEAR

Discussion

9.	Which of the following can be explained on the basis of newton's second law? A) catching a cricket ball B)high jump C)case of hose pipe D)both (i) and (ii)
Answer» ong>ANSWER: CATCHING a cricket ball Explanation: because when fielder CATCH the ball he moves his hand slight back to reduce the momentum hence FORCE reduce and second law STATE that rate of change of momentum is force

9.

Which of the following can be explained on the basis of newton's second law? A) catching a cricket ball B)high jump C)case of hose pipe D)both (i) and (ii)

Answer»

ong>ANSWER:

CATCHING a cricket ball

Explanation:

because when fielder CATCH the ball he moves his hand slight back to reduce the momentum hence FORCE reduce and second law STATE that rate of change of momentum is force

Discussion

10.	Define Dispersion of light
Answer» ION of the light can be defines as the SEPARATION of VISIBLE light beam into its CONSTITUENT colours For example RED ,yellow.orange,green ,blue,indigo are obtained when a white light beam is despersed Dispersion of light happens when a light beam passes through a dispersive medium

Discussion

11.	At what place on the earth’s surface is the weight of a body maximum?
Answer» IGH altitude cause there g=10 not9.8 HENCE MG VALUE increases

Discussion

12.	A jeep traveling at a constant speed of 108 km/h rounds a cure of radius 100m. Find its acceleration? A. 3m/sec? B. 6m/sec? C. 7m/sec? D. 8m/sec? E. 9m/sec The answer is E. All I want is the solution with explanation plz
Answer» /sec Explanation: Speed of JEEP = 108×1000 60 × 60 v = 30 m/sec Radius (r) = 100m Acceleration of jeep (a) = = v^2 = 30×30 = 9m/sec r 100 a = 9m/sec .Ans.

12.

A jeep traveling at a constant speed of 108 km/h rounds a cure of radius 100m. Find its acceleration? A. 3m/sec? B. 6m/sec? C. 7m/sec? D. 8m/sec? E. 9m/sec The answer is E. All I want is the solution with explanation plz

Answer»

/sec

Explanation:

Speed of JEEP = 108×1000
60 × 60
v = 30 m/sec
Radius (r) = 100m
Acceleration of jeep (a) =
= v^2 = 30×30 = 9m/sec
r 100
a = 9m/sec .Ans.

Discussion

13.	18. In Fig. 1.35, a uniform bar of length 1 m is supported at its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf
Answer» ong>ANSWER: R1+R2=w (BALANCING Forces in Y−ax) __(I) WRITING EQUATION for torque about the centre of bar : R1(0.5)+w(0)−R2(0.5)=0 R1=R2 __(II) From eq. (I) & (II) R1=R2=2wKgf.

13.

18. In Fig. 1.35, a uniform bar of length 1 m is supported at its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf

Answer»

ong>ANSWER:

R1+R2=w (BALANCING Forces in Y−ax) __(I)

WRITING EQUATION for torque about the centre of bar :

R1(0.5)+w(0)−R2(0.5)=0

R1=R2 __(II)

From eq. (I) & (II)

R1=R2=2wKgf.

Discussion

14.	3. Reaction with metals
Answer» ong>Answer: PLEASE DESCRIBE your QUESTION COMPLETELY

14.

3. Reaction with metals

Answer»

ong>Answer:

PLEASE DESCRIBE your QUESTION COMPLETELY

Discussion

15.	Calculate the change of momentum of a body weighing 5kg when its velocity decreases from 20m/s to 0.20m/s?
Answer» ONG>ANSWER: The answer is as FOLLOWS:-

Discussion

16.	F = 6.67 x 10 x 6 x 1024 xTux10223.84x108 km6.67 x 10 11 X6 x 1024 x 7. uxis3.84
Answer» ONG>ANSWER: wwwjshssbsbsbsbabababwbqbqbqbwbabsbbabsbsnsnsbsbsnababsbsbsbssbsbans dmxxnxxvxnxnxnxbxbxndndssaaqqjqkqiqowieuygrgddbxb

Discussion

17.	5. Explain the formation of mirage? (AS)
Answer» ong>Answer: MIRAGE HAPPEN when the GROUND is very HOT and the AIR is cool

17.

5. Explain the formation of mirage? (AS)

Answer»

ong>Answer:

MIRAGE HAPPEN when the GROUND is very HOT and the AIR is cool

Discussion

18.	define centripetal acceleration . derive an expression for direction and magnitude moving with velocity v and radius r
Answer» EVENING guys i am leaving this app TOMORROW so today how MUCH people will follow me i want to see take care miss U BYE my followers and who has answered my questions love u all and miss u all so tomorrow .

Discussion

19.	17. A uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknownmass m at the mark 20 cm.(i) Find the value of m.(ii) To which side the rule will tilt if the mass m ismoved to the mark 10 cm ?(iii) What is the resultant moment now?(iv) How can it be balanced by another mass of50 g ?Ans. (i) m = 50 g, (ii) on the side of mass m,(iii) 500 gf x cm (anticlockwise),(iv) by suspending the mass 50 g at the mark 50 cm.
Answer» align="absmiddle" alt="\LARGE{ \underline{\underline{ \pink{ \BF{Required \: answer:}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5CLARGE%7B%20%5Cunderline%7B%5Cunderline%7B%20%5Cpink%7B%20%5Cbf%7BRequired%20%5C%3A%20answer%3A%7D%7D%7D%7D%7D" TITLE="\LARGE{ \underline{\underline{ \pink{ \bf{Required \: answer:}}}}}"> From the PRINCIPLE of moments, Clockwise moment = Anticlockwise moment 100 g × (50 – 40) cm = m × (40 – 20) cm 100 g × 10 cm = m × 20 cm m = 50 g If the mass m is moved to the mark 10 cm, the rule will tilt on the side of mass m (anticlockwise) Anticlockwise moment if mass m is moved to the mark 10 cm = 50 g × (40 – 10) cm = 50 g × 30 cm = 1500 g cm Clockwise moment = 100 g × (50 – 40) cm = 100 g × 10 cm = 1000 g cm Resultant moment = 1500 g cm – 1000 g cm = 500 g cm (anticlockwise) According to the principle of moments. Clockwise moment = Anticlockwise moment To balance it, 50 g weight should be kept on right-hand side so as to produce a clockwise moment. LET d cm be the distance from the fulcrum. Then, 100 g × (50 – 40) cm + 50 g × d = 50 g × (40 – 10) cm 100 g × 10 cm + 50 g × d = 50 g × 30 cm 1000 g cm + 50 g × d = 1500 g cm 50 g × d = 500 g cm Then, d = 10 cm It can be balanced by suspending the mass 50 g at the mark 50 cm. $\pink{}$ $\red{Mark}$ $\green{As}$ $\blue{Brainliest}$ $\orange{}$ $\pink{}$ $\red{Please}$ $\green{Like}$ $\blue{}$ $\orange{}$ ${\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: DecentMortal\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}$

19.

17. A uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknownmass m at the mark 20 cm.(i) Find the value of m.(ii) To which side the rule will tilt if the mass m ismoved to the mark 10 cm ?(iii) What is the resultant moment now?(iv) How can it be balanced by another mass of50 g ?Ans. (i) m = 50 g, (ii) on the side of mass m,(iii) 500 gf x cm (anticlockwise),(iv) by suspending the mass 50 g at the mark 50 cm.

Answer»

align="absmiddle" alt="\LARGE{ \underline{\underline{ \pink{ \BF{Required \: answer:}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5CLARGE%7B%20%5Cunderline%7B%5Cunderline%7B%20%5Cpink%7B%20%5Cbf%7BRequired%20%5C%3A%20answer%3A%7D%7D%7D%7D%7D" TITLE="\LARGE{ \underline{\underline{ \pink{ \bf{Required \: answer:}}}}}">

From the PRINCIPLE of moments,

Clockwise moment = Anticlockwise moment

100 g × (50 – 40) cm = m × (40 – 20) cm

100 g × 10 cm = m × 20 cm

m = 50 g

If the mass m is moved to the mark 10 cm, the rule will tilt on the side of mass m (anticlockwise)

Anticlockwise moment if mass m is moved to the mark 10 cm

= 50 g × (40 – 10) cm

= 50 g × 30 cm

= 1500 g cm

Clockwise moment = 100 g × (50 – 40) cm

= 100 g × 10 cm

= 1000 g cm

Resultant moment = 1500 g cm – 1000 g cm

= 500 g cm (anticlockwise)

According to the principle of moments.

Clockwise moment = Anticlockwise moment

To balance it, 50 g weight should be kept on right-hand side so as to produce a clockwise moment. LET d cm be the distance from the fulcrum. Then,

100 g × (50 – 40) cm + 50 g × d = 50 g × (40 – 10) cm

100 g × 10 cm + 50 g × d = 50 g × 30 cm

1000 g cm + 50 g × d = 1500 g cm

50 g × d = 500 g cm

Then, d = 10 cm

It can be balanced by suspending the mass 50 g at the mark 50 cm.

$\pink{}$ $\red{Mark}$ $\green{As}$ $\blue{Brainliest}$ $\orange{}$

$\pink{}$ $\red{Please}$ $\green{Like}$ $\blue{}$ $\orange{}$

${\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: DecentMortal\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}$

Discussion

20.	5. The following observations were take for determining surface tension of water bycapillary tube method. Diameter of capillar,D=125x10-2m and rise of water incapillaryh=1.46 x 10-2m.Taking g=9.80ms-2 and using therelationT=(rgh/2) x 103Nm"?, what is the possibleerror in surface tension T?(a) 2.4%(b) 15%(c) 1.6%(d)0.15%
Answer» ONG>Answer: The force of surface tension on a RING situated on the surface of water is 14π×10^-4N. Then the diameter of the ring is (surface tension of water = 70×10^-3 N/m) a) 5 mm b) 1 cm c) 2 cm d) 4 cm plz.SOLVE & explain it..

20.

5. The following observations were take for determining surface tension of water bycapillary tube method. Diameter of capillar,D=125x10-2m and rise of water incapillaryh=1.46 x 10-2m.Taking g=9.80ms-2 and using therelationT=(rgh/2) x 103Nm"?, what is the possibleerror in surface tension T?(a) 2.4%(b) 15%(c) 1.6%(d)0.15%

Answer» ONG>Answer:

The force of surface tension on a RING situated on the surface of water is 14π×10^-4N. Then the diameter of the ring is (surface tension of water = 70×10^-3 N/m)

a) 5 mm

b) 1 cm

c) 2 cm

d) 4 cm

plz.*SOLVE* & *explain it..*

Discussion

21.	Which of the following posses gravitation
Answer» ong>ANSWER: PLEASE EXPLAIN the WHOLE QUESTION

21.

Which of the following posses gravitation

Answer»

ong>ANSWER:

PLEASE EXPLAIN the WHOLE QUESTION

Discussion

22.	A body of mass 30 kg has a momentum of 150 kg m/s. Its velocity is:
Answer» ONG>Answer: velocity = 5m/sec Explanation: m*V =p

22.

A body of mass 30 kg has a momentum of 150 kg m/s. Its velocity is:

Answer» ONG>Answer:

velocity = 5m/sec

Explanation:

m*V =p

Discussion

23.	Kyun kya hua kujh kehna hai ehno ne
Answer» mai unse khunga to yh tumko khegi MESSAGE TRANSFER KREGI

23.

Kyun kya hua kujh kehna hai ehno ne

Answer»

mai unse khunga to yh tumko khegi

MESSAGE TRANSFER KREGI

Discussion

24.	The kinetic energy of a system in laboratory system as compared to that in the centre of mass system is always…….
Answer» ong>ANSWER: The kinetic ENERGY of the center of mass (i.e. modeling the SYSTEM as a POINT particle with all of its mass concentrated at its center of mass) is called translational kinetic energy.

24.

The kinetic energy of a system in laboratory system as compared to that in the centre of mass system is always…….

Answer»

ong>ANSWER:

The kinetic ENERGY of the center of mass (i.e. modeling the SYSTEM as a POINT particle with all of its mass concentrated at its center of mass) is called translational kinetic energy.

Discussion

25.	Which quantity has the dimension [MLT_¹]
Answer» ong>Explanation: Answer. Taking the GIVEN dimensional formula [M^1 L^1 T^-1] in the corresponding SI units, we GET (kg×m)/s, which is clearly the SI unit for MOMENTUM

25.

Which quantity has the dimension [MLT_¹]

Answer»

ong>Explanation:

Answer. Taking the GIVEN dimensional formula [M^1 L^1 T^-1] in the corresponding SI units, we GET (kg×m)/s, which is clearly the SI unit for MOMENTUM

Discussion

26.	What will happen to the gravitational force between two bodies if the masses of one body is doubled?
Answer» ONG>Answer: The gravitational FORCE will ALSO be doubled

Discussion

27.	The two stars which points towards the pole star belongs to which of the following constellation?
Answer» ong>ANSWER: i think its ursa major, hope THOS HELPS

27.

The two stars which points towards the pole star belongs to which of the following constellation?

Answer»

ong>ANSWER:

i think its ursa major, hope THOS HELPS

Discussion

28.	A pulley of radius 0.9m is used to lift a bucket from the well. If it took 3.6 rotation for the pulley-------------------?
Answer» ong>Answer: A PULLEY of radius 0.9 m is used to LIFT a BUCKET from the well. If it took 3.6 Explanation: depth = circumference X no. of rotations =2π 0.9 x 3.6 = 20.34m

28.

A pulley of radius 0.9m is used to lift a bucket from the well. If it took 3.6 rotation for the pulley-------------------?

Answer»

ong>Answer:

A PULLEY of radius 0.9 m is used to LIFT a BUCKET from the well. If it took 3.6

Explanation:

depth = circumference X no. of rotations

=2π 0.9 x 3.6

= 20.34m

Discussion

29.	A body thrown vertically upward with a velocity,u final velocity maximum height
Answer» ONG>ANSWER: MAKE me as BRAINLIST Explanation: make me as brainlist

29.

A body thrown vertically upward with a velocity,u final velocity maximum height

Answer» ONG>ANSWER:

MAKE me as BRAINLIST

Explanation:

make me as brainlist

Discussion

30.	Which of following nature of light waves is supported 10.by the phenomenon of interference :(1) longitudinal(2) transverse(3) both transverse and longitudinal(4) None of the above
Answer» ONG>Answer: OPTION( 1)is the CORRECT answer

Discussion

31.	Which of the following help you add graphics to your presentations what is answer this question
Answer» ONG>EXPLANATION: hhhlhkjhjjnjhgjjhggghgggghgghhhhhhhh

Discussion

32.	Can displacement be greater than distance travelled
Answer» ONG>ANSWER: YES sometimes it can be so MARK me as brainliest plz

32.

Can displacement be greater than distance travelled

Answer» ONG>ANSWER:

YES sometimes it can be

so MARK me as brainliest plz

Discussion

33.	Write a dialogue on the contribution of luminaries
Answer» ong>Answer: BABLI : When I entered into the complex, I felt a SORT of PEACE in my mind. I expressed my felicitation to the brave sons of Bangladesh for their contribution to make us free. Aysha : Would that I could go there! Babli : Try to make a trip. Explanation: mark me as the BRAINLIEST

33.

Write a dialogue on the contribution of luminaries

Answer»

ong>Answer:

BABLI : When I entered into the complex, I felt a SORT of PEACE in my mind. I expressed my felicitation to the brave sons of Bangladesh for their contribution to make us free.

Aysha : Would that I could go there!

Babli : Try to make a trip.

Explanation:

mark me as the BRAINLIEST

Discussion

34.	Derive an expression for relative velocity between two moving objects.
Answer» ong>Explanation: THUS relative VELOCITY of a moving body, A, with respect to another moving body, B, is found by considering B to be FIXED and then finding the velocity of A which an OBSERVER resting on B will observe. ... The velocity of A will be v a and the velocity of B will be –v b .

34.

Derive an expression for relative velocity between two moving objects.

Answer»

ong>Explanation:

THUS relative VELOCITY of a moving body, A, with respect to another moving body, B, is found by considering B to be FIXED and then finding the velocity of A which an OBSERVER resting on B will observe. ... The velocity of A will be v a and the velocity of B will be –v b .

Discussion

35.	What is radial pulse
Answer» ong>Explanation: (radial ARTERY). It can also be found in the ANATOMICAL snuff box. Ulnar PULSE: located on the MEDIAL of the wrist (ulnar artery). BIOLOGICAL system: Circulatory system Frequency: 60–100 per minute

35.

What is radial pulse

Answer»

ong>Explanation:

(radial ARTERY). It can also be found in the ANATOMICAL snuff box. Ulnar PULSE: located on the MEDIAL of the wrist (ulnar artery).

BIOLOGICAL system: Circulatory system

Frequency: 60–100 per minute

Discussion

36.	The displacement of a particle is givenby x(1) = 4t^2sq + 8 t velocity att = 5 s is. m/s
Answer» ONG>Answer: 48m/s Explanation: differentiating you GET V=8t+8 substituting t=5 V=40+8=48 PLS pls mark me as brainliest

36.

The displacement of a particle is givenby x(1) = 4t^2sq + 8 t velocity att = 5 s is. m/s

Answer» ONG>Answer:

48m/s

Explanation:

differentiating you GET V=8t+8 substituting t=5 V=40+8=48

PLS pls mark me as brainliest

Discussion

37.	What is meant by reaction time? give example
Answer» ong>Answer: the LENGTH of TIME taken for a person or system to RESPOND to a given STIMULUS or event

37.

What is meant by reaction time? give example

Answer»

ong>Answer:

the LENGTH of TIME taken for a person or system to RESPOND to a given STIMULUS or event

Discussion

38.	Object at distance of 40 cm from a concave mirror gets it's image at the same poi t the focal length of mirror is
Answer» ONG>Answer: Since focal length of concave mirror GIVEN is 20cm l. Object is at 40cm distance which means it is at centre of curvature. hence, IMAGE will be formed of same size and at centre focus only but real and inverted.

Discussion

39.	what is change of momentum of a body weighing 1500kg when its speed increases from 36km/h to 72km/h uniformly?
Answer» ONG>Answer: 72=20m/s 36=10m/s Explanation: m(v-u 15000(20-10 15×10^42

39.

what is change of momentum of a body weighing 1500kg when its speed increases from 36km/h to 72km/h uniformly?

Answer» ONG>Answer:

72=20m/s

36=10m/s

Explanation:

m(v-u

15000(20-10

15×10^42

Discussion

40.	How do insects move easily on the surface of water?
Answer» ong>Explanation: Water STRIDE are small insect that are adapted for life on top of still water, USING surface tension to their advantage so they can walk on water, by repelling water, the tiny water strider stand on the water surface and the CAPTURED airs ALLOWS them to float and move easily.

40.

How do insects move easily on the surface of water?

Answer»

ong>Explanation:

Water STRIDE are small insect that are adapted for life on top of still water, USING surface tension to their advantage so they can walk on water, by repelling water, the tiny water strider stand on the water surface and the CAPTURED airs ALLOWS them to float and move easily.

Discussion

41.	16. The far point of a myopic eye is 80 cm in front of the eye. What is the power of the lens required to enable him to see far off objects?
Answer» ong>Answer: The nature and the power of lens required to enable him to see very DISTANT objects clearly is concave lens with -1.25 D. Explanation: For PERSON AFFECTED with myopic condition, the image instead of FORMING on retina, it forms in front of it. In order to cure such type of defect, concave lens is used this is RIGHT answer

41.

16. The far point of a myopic eye is 80 cm in front of the eye. What is the power of the lens required to enable him to see far off objects?

Answer»

ong>Answer:

The nature and the power of lens required to enable him to see very DISTANT objects clearly is concave lens with -1.25 D. Explanation: For PERSON AFFECTED with myopic condition, the image instead of FORMING on retina, it forms in front of it. In order to cure such type of defect, concave lens is used

this is RIGHT answer

Discussion

42.	what is change of momentum of a body weighing 1500kg when its speed increases from 36km/h to 72km/h uniformly
Answer» ong>Answer: The change in momentum of a CAR weighing 1500 KG when its speed INCREASES from 36 km/h to 72 km/h = 30000 kg.

42.

what is change of momentum of a body weighing 1500kg when its speed increases from 36km/h to 72km/h uniformly

Answer»

ong>Answer:

The change in momentum of a CAR weighing 1500 KG when its speed INCREASES from 36 km/h to 72 km/h = 30000 kg.

Discussion

43.	With respect to you, what is the state of atmosphere of earth?why?
Answer» ong>Answer: This mixture of gases is commonly known as air. The atmosphere protects life on Earth by absorbing ULTRAVIOLET solar radiation and reducing temperature EXTREMES between day and NIGHT. The atmosphere has no abrupt cut-off. Explanation: PLEASE FOLLOW ME PLEASE

43.

With respect to you, what is the state of atmosphere of earth?why?

Answer»

ong>Answer:

This mixture of gases is commonly known as air. The atmosphere protects life on Earth by absorbing ULTRAVIOLET solar radiation and reducing temperature EXTREMES between day and NIGHT. The atmosphere has no abrupt cut-off.

Explanation:

PLEASE FOLLOW ME PLEASE

Discussion

44.	Calculate the mass of the body whose volume is 5 cu.m and relative density is 2.5? 1250 kg 2500 kf 12,500 kg 12.5 kg
Answer» ONG>ANSWER: OKAY SURE .............

44.

Calculate the mass of the body whose volume is 5 cu.m and relative density is 2.5? 1250 kg 2500 kf 12,500 kg 12.5 kg

Answer» ONG>ANSWER:

OKAY SURE

.............

Discussion

45.	What is the motion of object due to gravity called
Answer» ong>Answer: GRAVITY..... EXPLANATION: brain LIST please. .

45.

What is the motion of object due to gravity called

Answer»

ong>Answer:

GRAVITY.....

EXPLANATION:

brain LIST

please. .

Discussion

46.	An athlete completes one round of a circular track of diameter 200 m in 40s . What will be the distance covered and the displacement at the end of 2 min 20s
Answer» ONG>Explanation: Time taken by athlete to complete ONE round = 40 SECONDS. Distance covered = ?? Displacement = ?? Hence, the distance covered at the end of 2 MIN 20 seconds is 22000 m or 22 KM

Discussion

47.	ਸਿੱਖ ਰੈਜ਼ੀਮੈਂਟ ਦੀ ਅਗਵਾਈ ਕੌਣ ਕਰ ਰਿਹਾ ਸੀ? *
Answer» ONG>Answer: PLEASE talk in ENGLISH

Discussion

48.	A particle moves in straight line with velocity 6 m/s and 3 m/s for time intervals which are in ratio 1:2. Findaverage velocity.(a) 2 m/s (6) 3 m/s (c) 4 m/s(d) 5 m/s
Answer» ong>Answer: Key Idea average velocity and INSTANTANEOUS velocities have same value in a UNIFORM motion. Average velocity is that uniform velocity with which the OBJECT will cover the same displacement in same interval of TIME as it does with actual variable velocity during that time interval. =(3m/s×20s)+(4m/s×20s)+(5m/s×20s) =(60+80+100)−240m Total time taken =20+20+20 =60s ∴ Average velocity = 60 240 =4m/s Explanation: mark as brainliest

48.

A particle moves in straight line with velocity 6 m/s and 3 m/s for time intervals which are in ratio 1:2. Findaverage velocity.(a) 2 m/s (6) 3 m/s (c) 4 m/s(d) 5 m/s

Answer»

ong>Answer:

Key Idea average velocity and INSTANTANEOUS velocities have same value in a UNIFORM motion. Average velocity is that uniform velocity with which the OBJECT will cover the same displacement in same interval of TIME as it does with actual variable velocity during that time interval.

=(3m/s×20s)+(4m/s×20s)+(5m/s×20s)

=(60+80+100)−240m

Total time taken =20+20+20

=60s

∴ Average velocity =

60

240

=4m/s

Explanation:

mark as brainliest

Discussion

49.	Question related to physics the first correct answer for the same question will be marked as brainliest Irrelevant answer will be reported
Answer» ONG>ANSWER: 1 is the answer bro PLEASE MARK AS BRAINLIEST

49.

Question related to physics the first correct answer for the same question will be marked as brainliest Irrelevant answer will be reported

Answer» ONG>ANSWER:

1 is the answer bro

PLEASE MARK AS BRAINLIEST

Discussion

50.	A stone thrown vertically upwards with an initial velocity 30 metre per second comes to a stop in 5 s. Find the retardation options are: 6 metre per second square- 6 metre per second square5 metre per second square-5 metre per second square
Answer» ong>ANSWER: ACCELERATION a= t v−u = 5s 0−50ms −1 =−10ms −2 Retardation=−Acceleration =10 ms −2

50.

A stone thrown vertically upwards with an initial velocity 30 metre per second comes to a stop in 5 s. Find the retardation options are: 6 metre per second square- 6 metre per second square5 metre per second square-5 metre per second square

Answer»

ong>ANSWER:

ACCELERATION a=

t

v−u

=

5s

0−50ms

−1

=−10ms

−2

Retardation=−Acceleration

=10 ms

−2

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