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18. In Fig. 1.35, a uniform bar of length 1 m is supported at its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf​

Answer»

ong>ANSWER:

R1+R2=w (BALANCING Forces in Y−ax) __(I)

WRITING EQUATION for torque about the centre  of bar :

R1(0.5)+w(0)−R2(0.5)=0

R1=R2 __(II)

From eq. (I) & (II)

R1=R2=2wKgf.



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