This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Let E = {prime numbers less than 30} Work out n(E) |
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Answer» Step-by-step EXPLANATION: prime numbers |
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| 2. |
Calculate the equivalent discount of two successive discount of 15% and 25% |
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| 3. |
Three coins are tossed simultaneously 150 times with the following frequency of different outcomes: Compute the probability of getting(a) at least two heads (b) maximum two heads (c) at most one head (d) 3 tails. |
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Answer» Answer: (d). 3 TAILStep-by-step EXPLANATION: I think it can be HELPFULMARK me brainlist |
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| 5. |
3. Find the A, B values of the following 3 A 4+ 5 6 B9 4 0 |
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Answer» vaiwvsiueg1oohddiqp1ksb |
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| 6. |
If x/y = (-1/3)^-3÷(2/3)^-4, find the value of: (x/y+y/x)^-1 |
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Answer» ddowvzlogxixglsghzdigk |
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| 7. |
Show that the following equation and i need the answer |
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Answer» Step-by-step EXPLANATION: à²+b² b²+c². c²+ಠX. × X. × X ——————————————— a⁴. b⁴. c⁴ X. X. X a²+² b²+² c²+² X ----------------------- a⁴b⁴c⁴ X a⁴b⁴c⁴ X ----------- a⁴b⁴c⁴ X so =1 plz answer my qué BAPU was in doing LENDING business adjevtive and type |
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| 8. |
If the polynomials P(t) =3 + 42 + 3 − 4 and Q(t) = 3 − 4 + leave the same remainder when divided by (t - 3), then find the value of a. |
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| 9. |
) प्रसंगलेखन-पुढील प्रसंगी तुम्ही उपस्थित होतात अशी कल्पना करून प्रसंगाचे लेखन करा.एक्काहत्तरी सत्कार समारंभआजोबांचा एक्काहत्तरावा (७१)वा वाढदिवसऔक्षण-सत्कार दि.१३ मार्च,दुपारी ४ वाजताआजोबांच्या कार्यकर्तृत्वाचा आढावानातेवाईकांची उपस्थितीकसबा पेठ पुणे येथील राहते घर |
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Answer» gooooooooooooooooooooooooooooooooooooooooooooooooooooood Step-by-step EXPLANATION: |
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| 10. |
6 + 2√11 / 5-3√11 conjucate to rationalize denominator:- |
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Answer» In attachment I have answered this question. I hope it's HELP you.. Know more ALGEBRAIC Identities:-(a+ b)² = a² + b² + 2ab ( a - b )² = a² + b² - 2ab ( a + b )² + ( a - b)² = 2a² + 2b² ( a + b )² - ( a - b)² = 4ab ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca a² + b² = ( a + b)² - 2ab (a + b )³ = a³ + b³ + 3AB ( a + b) ( a - b)³ = a³ - b³ - 3ab ( a - b) If a + b + c = 0 then a³ + b³ + c³ = 3abc |
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| 11. |
The measurements of height in meter of 5 trees are given 92.8, 94, 42.8, 96.2, 13.6 what is the average height of a tree |
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Answer» Step-by-step explanation: Given :-The measurements of height in meter of 5 trees are given 92.8, 94, 42.8, 96.2, 13.6 To FIND:-What is the average height of a TREE? Solution:-Given that The measurements of height in meter of 5 trees are :92.8, 94, 42.8, 96.2, 13.6 SUM of all measurements of HEIGHTS of trees = 92.8+94+42.8+96.2+13.6 =339.4 m Number of trees = 5 We know that Average= Sum of all observations/Number of all observations Average = 339.4/5 Average = 67.88 m Answer:-The average height of the tree for the given problem is 67.88 m Used formula:-
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| 12. |
In a GST chain, a dealer X purchases an article for Rs 8000 and supplies it to another dealer Y(in the same state) at a profit of Rs 1000.The dealer Y sells it to a customer Z at a profit of Rs 2000. If the rate of GST is 12% and if all transactions were intrastate, Calculate (i) ITC for dealer X (ii) Input Tax payable by dealer Y (iii) Total cost price of the article for customer Z (iv)Output GST for customer Z. |
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Answer» Answer: 0 Step-by-step EXPLANATION: |
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| 13. |
Prove that(cos theta – sintheta+1)/(costheta + sintheta+1)= cosectheta + cottheta |
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Answer» Answer :- solving LHS, → (cosA - SINA + 1)/(cos A + sinA - 1) dividing numerator and denominator by sinA → (cosA / sinA - sinA/sinA + 1/sinA) / (cosA / sinA + sinA/sinA - 1/sinA) → (cot A + COSEC A - 1) / (cot A - cosec A + 1) putting 1 = cosec²A - cot²A in numerator, → {cot A + cosec A - (cosec²A - cot²A)} / (cot A - cosec A + 1) → using (a² - b²) = (a + b)(a - b) → (cotA + cosecA)(1 - cosecA + cotA) / (cot A - cosec A + 1) → cotA + cosecA = RHS (PROVED) Learn more :- It SINO + tano = m tano - sino an Then express the values of m²-n² in terms of M and N tanA/(1-cotA) + cotA/(1-tanA) |
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| 14. |
Find the range of the data 91,82,100,96,65,82,76,79,90,46,64,72,68,66,48,49 |
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Answer» Answer: 54 100-46 Step-by-step EXPLANATION: highest-lowest NUMBER |
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| 15. |
If difference between C.I. and S.I. is 21 with 5% annual rate in 2 years,Find the principle ? |
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Answer» Answer: the product of two rational NUMBER is 15/56 . if ONE of the number is -5/48 ,FIND the other |
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| 16. |
The difference of the two numbers is 72 and their quotient is 10 |
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Answer» The DIFFERENCE between two numbers is 72 and their quotient is 10 then the numbers are 80 and 8 Solution: Let the two numbers be X and y Given that difference between two numbers is 72 So x + y = 72 ---- EQN 1 x - y = 72 x - 8 = 72 x = 72 + 8 x = 80 |
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| 17. |
Which of the following are rational numbers?a) -3 b) -2/3 c) 4/0 d) 0/-5please answer me please guys help me on this question and main, listen only answer typing ok. |
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Answer» Answer: Ask me Any Question Message NowMy Inst a GRAM ID Vinit Sandhu00 |
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| 18. |
from the top of a 9 meter high building the angle of elevation of the top a cable pole is60° and angle of depression of its foot is 45° determine the height of the cable pole |
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Answer» Step-by-step EXPLANATION: |
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| 19. |
State whether True or False :(a) All rectangles are squares.(b) All rhombuses are parallelograms.(c) All squares are rhombuses and also rectangles.(d) All squares are not parallelograms.(e) All kites are rhombuses,(6) All rhombuses are kite.(8) All parallelograms are trapeziums.(h) All squares are trapeziums. |
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Answer» (a) All rectangles are squares. - False (B) All RHOMBUSES are parallelograms. - TRUE (c) All squares are rhombuses and also rectangles. - True (d) All squares are not parallelograms. - False (e) All kites are rhombuses. - False (f) All rhombuses are kite. - True (g) All parallelograms are trapeziums. - True (h) All squares are trapeziums. - True Hope It HELPS You! |
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| 21. |
Varsha is making different styles of colour pattern by drawing 5 vertical lines from left to right. She has decided to draw 3 vertical lines with crayon colours and 2 vertical lines with water colours. She has 3 different water colours and 2 different crayon colours (all 5 colours are distinct) at herdisposal How many different patterns can she create using these colours if repetition of colours is allowed? (The page on which vertical stripes aremade is not rotated while making or observing later) |
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Answer» Given : Varsha is MAKING different styles of colour pattern by drawing 5 vertical lines from left to right. She has decided to draw 3 vertical lines with CRAYON colours and 2 vertical lines with WATER colours. She has 3 different water colours and 2 different crayon colours (all 5 colours are distinct) at her disposal To Find : different patterns she can create using these colours if repetition of colours is allowed Solution: 3 lines with crayon 2 lines with water colors Total Lines = 5 3 lines out of 5 can be selected in ⁵C₃ = 10 way Hence 10 ways of selecting lines Now each water color line can be colored in 3 * 3 = 9 ways each crayon color line can be done in 2 ways Hence 3 lines can be in 2 * 2 * 2 = 8 ways Total Ways = 10 * 9 * 8 = 720 ways 720 different patterns can be created, learn More: find the number of ways in which n distinct balls can be put into three ... Find the number of ways of drawing 9 balls from a bag that has6 red ... 7. Find the number of ways of drawing 9 ballsfrom a bag that has 6 ... |
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| 22. |
If f(x) = x*2-1, solve f (x+2)-f(x-2) =16 |
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Answer» (X*2-1+2)-(x*2-1-2) 3x-x=16 2x=16 x=16/2 x=8 |
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| 23. |
PLease solve it, it is for class 3rd |
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Answer» Answer: 4000+700+10+8 7000+0+90+8 5000+0+0+2 6000+500+10+10 3000+400+50+6 mark me as BRAINLIEST |
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| 24. |
How many hours in 365 days |
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Answer» Answer: 1 day = 24hours365 DAYS = 365 × 24=> 8,760 hours |
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| 25. |
Price of 15×2/5 liters milk is Rs 231, then find price of 2 liters milk. |
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Answer» Answer: We need to find how MANY litres is worth 231 RS. So 15x2/5 Cancel 15 and 5 so we get 3x2 = 6 So 6 litres of MILK = Rs.231 Now find PRICE of 1 litre of milk = 231 ÷ 6 Which is equal to 38.5 Rs. So price of 2 litres of milk = Rs. 38.5 x 2 = Rs. 77 Hope it HELPS |
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| 27. |
7(2y-8)=7(2y−8)=\,\,14147(2y-8)= 14 |
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Answer» Answer: 7(2y-8)=14y-56 7(2y−8)=14y-56 \,\,14 147(2y-8)= 14 |
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| 28. |
A tricycle is sold at a gain of 15%. Had it been sold for Rs 27 more, the profit would been 20%. Find its cost price |
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Answer» Answer: 180+504+024+60+498+5688+458+159+5488+55 |
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| 29. |
A joiner has piece of wood 2m long he needs to cut lengths of wood that measure 50 cm each hoe many 50cm lengths can be cut from the piece of wood |
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Answer» Answer: 200 Step-by-step EXPLANATION: |
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| 30. |
Temp of mixture is 15 degrees C and mix is cooled to -24 degrees C = |
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| 31. |
Convert the following decimal into rational number :(a) 1.16(b) 2.3*Answer in full from* |
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Answer» Answer: 116 203 |
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| 32. |
if M=(8,5) is the midpoint of the line segment joining v=(9,-8) and w=(a,b) find the coordinates of w? |
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Answer» Answer: Here is your answer Step-by-step explanation: mid PT formula - X1 + x2 ÷ 2 ; Y1 + y2 ÷ 2 (8,5) = ( 9 + a / 2 ; -8 + B / 2) 9+a /2 = 8 ; -8 + b / 2 = 5 a + 9 = 16 ; b - 8 = 5 a = 7 , b = 18 w ( 7,18) |
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| 33. |
फाइव थ्री एक्स माइनस 5 डिवाइडेड बाय 5 माइनस 7 एक्स माइनस टू डिवाइडेड बाय टू इज इक्वल टू फाइव |
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Answer» hiiiiiiiiiiiiiiiiiiiiiiiii |
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| 34. |
What is gsheygeushsjskiwyeiwod |
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Answer» Answer: thdf ghbbvg rtyfdr and fyuhg do 6AM the RENOWNED vaishnav and its own web Step-by-step explanation: |
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| 35. |
Solve the quadratic equation : x + 9/x +6 = 0; x = 0 |
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Answer» x=-9 Step-by-step EXPLANATION: x+9 –––– = 0 x+6 x+9=0 x=-9PLEASE MARK ME AS BRAINLIST |
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| 36. |
c) A tower has a flag pole on it, and the tower has a height of 40 m. The angle of elevationof the top of the tower and the flag pole are respectively 30° and 45° to an observerstanding on the horizontal line from the foot of the tower. Find the length of the flagpole correct to two significant figures.[4] |
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Answer» hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii |
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| 37. |
In the figure angel B=90°,angel A= Angel C and BC=10cm , then find the value of tan 45° |
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Answer» Answer: Abe HOULE TERA question is out of sallybus HAI tere maths ke teacher kon hai re tujhe ITNA bhi ni malum |
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| 38. |
2 subtracted from 1/4 of a number gives 1.what is the number |
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Answer» Answer: Step-by-step EXPLANATION: x/4-2=1 x/4=1+2 x/4=3 x=3(4)=12 Hence,the NUMBER is 12. |
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| 39. |
What is the additive inverse of -478 ? (a) –(-478) (b) -478 (c) 1/478 (d) -1/47 |
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Answer» the CORRECT option is ( a ) additive inverse of -478 is 478 ( a ) -(-478)= 478 I hope it's help you |
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| 40. |
1.)X²-x³+2y²2. 5(x+2)3x-83. X²+y²4. 5(3x+2)=255. 3x-2y |
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Answer» ????????????????????? |
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| 41. |
The.place.100timessmaller.then.the.fence.place |
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Answer» Answer: Hello, Once we understand circumference we're almost home. The formula is: Circumference = pi (3.14) times diameter So LET's find the diameter of the tower. 10 = 3.14*D Divide 3.14 to get: Diameter is approx 3.18 meters for the tower so we now know with the fence the diameter is 7.18 meters.So now we can find the circumstance: Circumference = 3.14 times 7.18 Circumference = 22.55 meters approx Step-by-step explanation: The circumference of the tower is your 10 meters; we need to find a radius 2r%2Api+=10m r=10+m%2F2pi r=5m%2F3.14 r=1.59m a fence that surrounds a tower makes a CIRCLE that will have a radius of r1=r%2B2=1.59%2B2=3.59 meters (radius MEASURED from the CENTER of the tower), and will have a circumference of: 2r1%2Api+=+2%2A3.59%2A3.14=+22.55m which is the length of a fence |
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| 42. |
What is the sum of (-11)+(-3). |
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Answer» _+14 is the answer of the question___________________ |
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| 43. |
The line y=4 meets the line 2x + y= 8 at the point A. Find the coordinates of A |
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Answer» Step-by-step explanation: |
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| 44. |
If X is a geometric mean of 16 & 4 then find the value of X |
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Answer» An,ZG,safjghakjrhg.aer.jht Step-by-step EXPLANATION: |
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| 45. |
X=1/3-√2 find value of x-1/x |
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Answer» Step-by-step EXPLANATION: gixifsaruruaruarurusruqeuequeajdkgdjfaureuktsktzkxgkg |
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| 46. |
What is the full name of Great Mathematician ARYABHATTA |
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Answer» Aryabhata, ALSO called Aryabhata I or Aryabhata the Elder, (born 476, possibly Ashmaka or Kusumapura, India), ASTRONOMER and the earliest Indian mathematician whose work and history are AVAILABLE to modern scholars. Born: 476; Kusumapura?, India Notable works: “ARYABHATIYA” Died: c. 550 |
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| 47. |
What is the distance between the points (-1, 7) and (6, 7) in the xy-plane? |
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Answer» my ANSWERS Step-by-step explanation: SOMEONE SUGGESTED me how to increase point my POINTS -480 |
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| 48. |
Express cos4A in terms of sin2A |
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| 49. |
in a school the ratio of the number of the boys to the number of girls 4:5 when 100 girls leave the school the ratio becomes 6:7 find the number of boys in the schoo |
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Answer» Answer: Let number of boys = 4X and number of girls = 5X According to the question 4X / (5X - 100) = 6/7 ⇒ 28X = 6 ( 5X - 100 ) ⇒ 28X = 30X - 600 ⇒ 2X = 600 ∴ X = 600/2 = 300 ∴ Number of boys = 4X = 4 x 300 = 1200 |
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| 50. |
Solve for the following equation for 0°≤∅≤360° 1 + sin∅cos²∅ = sin∅ |
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Answer» Step-by-step EXPLANATION: Given :-To find:-Solve for the following EQUATION for 0°≤∅≤360° , 1 + Sin∅Cos^2∅ = Sin∅ Solution:-Given that 1 + Sin∅Cos^2∅ = Sin∅ We know that Sin^2 A + Cos^2 A = 1 Cos^2 A = 1-Sin^2 A => 1+ Sin∅(1-Sin^2∅) = Sin∅ => 1+ Sin∅- Sin∅ Sin^2∅ = Sin∅ => 1+ Sin∅- Sin^3∅ = Sin∅ =>1+ Sin∅- Sin^3∅ - Sin∅ = 0 => 1- Sin^3∅ = 0 => Sin^3∅ = 1 => Sin∅ = 1 => Sin ∅ = Sin 90° => ∅ = 90° Answer:-The value of ∅ for the given problem is 90° Used formulae:-
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