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6 + 2√11 / 5-3√11 conjucate to rationalize denominator:- |
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Answer» In attachment I have answered this question. I hope it's HELP you.. Know more ALGEBRAIC Identities:-(a+ b)² = a² + b² + 2ab ( a - b )² = a² + b² - 2ab ( a + b )² + ( a - b)² = 2a² + 2b² ( a + b )² - ( a - b)² = 4ab ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca a² + b² = ( a + b)² - 2ab (a + b )³ = a³ + b³ + 3AB ( a + b) ( a - b)³ = a³ - b³ - 3ab ( a - b) If a + b + c = 0 then a³ + b³ + c³ = 3abc |
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