332354 + Interview Questions in Secondary School in Math

1.	Solve the following simuttaners equation. 2x+y=5 ; 3x-y=5 .
Answer» ANSWER: LET X = 1 2×1+y=5 2+y=5 y=5-2 y=3 let x = 2 3×2-y=5 6-y=5 -y=5-6 -y=-1 y=1

1.

Solve the following simuttaners equation. 2x+y=5 ; 3x-y=5 .

Answer»

ANSWER:

LET X = 1

2×1+y=5

2+y=5

y=5-2

y=3

let x = 2

3×2-y=5

6-y=5

-y=5-6

-y=-1

y=1

Discussion

2.	Without actually performing the long division, state whether the following rationalnumbers will have a terminating decimal expansion or a non-terminating repeating decimalexpansion:
Answer» Answer: LISTEN dude, WRITE in the FULL QUESTION

2.

Without actually performing the long division, state whether the following rationalnumbers will have a terminating decimal expansion or a non-terminating repeating decimalexpansion:

Answer»

Answer:

LISTEN dude, WRITE in the FULL QUESTION

Discussion

3.	Using Cartesian Coordinates we mark a point on a graph by how far along and how far is. The left-right (horizontal) direction is commonly called X-axis. The up-down (vertical) direction is commonly called Y-axis. When we include negative values, the x and y axes18 Case study-based-2up itdividethe space up into 4 pieces. Read the following passage and answer the questions that follow the above information: In a classroom, four students Sita, Gita, Rita and Anita are sitting at A (3,4), B (6,7), C (9.4), D (6,1) respectively. Then a new student Anjali joins the class.109 876Rows321D4 5 6 7 ColumnsTeacher tells Anjali to sit in the middle of the four students. Find the coordinates of thei) Position where she sits.a. (2,4)b. (4,4)(ii) The distance between Sita and Anita is3v3 units(i) Which two studentsb. 3√2 unitsare equidistant from Gitaa. Anjali and Anita b. Anita and Rita c. Sita and Anita(IV) The geometrical figure formed after joining the ABCD is aa. Squareb. Rectangle(v) The distance between Sita and Rita isa. 4 units
Answer» Answer: An ESSAY is nothing but a piece of content which is written from the perception of writer or author. Essays are similar to a story, pamphlet, THESIS, ETC. The best thing about Essay is you can use any type

3.

Using Cartesian Coordinates we mark a point on a graph by how far along and how far is. The left-right (horizontal) direction is commonly called X-axis. The up-down (vertical) direction is commonly called Y-axis. When we include negative values, the x and y axes18 Case study-based-2up itdividethe space up into 4 pieces. Read the following passage and answer the questions that follow the above information: In a classroom, four students Sita, Gita, Rita and Anita are sitting at A (3,4), B (6,7), C (9.4), D (6,1) respectively. Then a new student Anjali joins the class.109 876Rows321D4 5 6 7 ColumnsTeacher tells Anjali to sit in the middle of the four students. Find the coordinates of thei) Position where she sits.a. (2,4)b. (4,4)(ii) The distance between Sita and Anita is3v3 units(i) Which two studentsb. 3√2 unitsare equidistant from Gitaa. Anjali and Anita b. Anita and Rita c. Sita and Anita(IV) The geometrical figure formed after joining the ABCD is aa. Squareb. Rectangle(v) The distance between Sita and Rita isa. 4 units

Answer»

Answer:

An ESSAY is nothing but a piece of content which is written from the perception of writer or author. Essays are similar to a story, pamphlet, THESIS, ETC. The best thing about Essay is you can use any type

Discussion

4.	(d) 180 minutes makehours.
Answer» Answer: 180 MINUTES make 3 hours Step-by-step explanation: if 1 hour have 60 minutes so - 60 × 3 -- 180

4.

(d) 180 minutes makehours.

Answer»

Answer:

180 MINUTES make 3 hours

Step-by-step explanation:

if 1 hour have 60 minutes

*so* - 60 × 3 -- 180

Discussion

5.	The elevation of Desert Shores, California, is less than -50 meters. Which of the following best describes Desert Shores?A. Desert Shores is higher than 50 meters above sea level.B. Desert Shores is higher than 50 meters below sea level.C. Desert Shores is lower than 50 meters below sea level.D. Desert Shores is lower than 50 meters above sea level.
Answer» Step-by-step explanation: Desert SHORES is lower than 47 meters above SEA LEVEL. ... Desert Shores is HIGHER than 47 meters above sea level.

5.

The elevation of Desert Shores, California, is less than -50 meters. Which of the following best describes Desert Shores?A. Desert Shores is higher than 50 meters above sea level.B. Desert Shores is higher than 50 meters below sea level.C. Desert Shores is lower than 50 meters below sea level.D. Desert Shores is lower than 50 meters above sea level.

Answer»

Step-by-step explanation:

Desert SHORES is lower than 47 meters above SEA LEVEL. ... Desert Shores is HIGHER than 47 meters above sea level.

Discussion

6.	Find the mean:60,50,54,46,50
Answer» FINAL ANSWER:- MEAN ⇒ 52 GIVEN:- TERMS 60,50,54,46,50 TO FIND:- mean of the terms FORMULA USED:- $mean=\frac{sum\:of \:all\:terms}{number\:of\:terms}$ SOLUTION:- $mean=\frac{60+50+54+46+50}{5}\\mean=\frac{260}{5} \\mean=52$ =================================================================

6.

Find the mean:60,50,54,46,50

Answer»

FINAL ANSWER:-

MEAN ⇒ 52

GIVEN:-

TERMS 60,50,54,46,50

TO FIND:-

mean of the terms

FORMULA USED:-

$mean=\frac{sum\:of \:all\:terms}{number\:of\:terms}$

SOLUTION:-

$mean=\frac{60+50+54+46+50}{5}\\mean=\frac{260}{5} \\mean=52$

=================================================================

Discussion

7.	Two cross roads, each of width 5m, run at right angles through the centre of a rectanglepark of lengths 70m and breadth 45m and parallel to its sides. Find the area of the roads.
Answer» $\large\underline{\bf{Solution-}}$ GIVEN that, RECTANGULAR Park = ABCD Longer Path = EFGH Shorter Path = PQRS Common Path = WXYZ Dimensions of FIELD are $\rm :\longmapsto\:Length \: of \: rectangular \: park, \: l \: = \: 70 \: m$ $\rm :\longmapsto\:Width \: of \: rectangular \: park, \: b \: = \: 45 \: m$ $\red{\rm :\longmapsto\:Length \: of \: the \: shorter \: path, \: l_1=45 \: m}$ $\red{\rm :\longmapsto\:Breadth \: of \: the \: shorter \: path, \: b_1=5 \: m}$ $\blue{\rm :\longmapsto\:Length \: of \: the \: longer \: path, \: l_2=70 \: m}$ $\blue{\rm :\longmapsto\:Breadth \: of \: the \: longer \: path, \: b_2=5 \: m}$ Consider, $\red{\bf :\longmapsto\:Area \: of \: shorter \: path, \: A_1=l_1×b_1}$ $\rm :\longmapsto\:A_1 = 45 \times 5$ $\red{\bf :\longmapsto\:A_1 = 225 \: {m}^{2}}$ Consider, $\blue{\bf :\longmapsto\:Area \: of \: longer \: path, \: A_2=l_2×b_2}$ $\rm :\longmapsto\:A_2 = 70 \times 5$ $\blue{\bf :\longmapsto\:A_2 = 350\: {m}^{2}}$ Thus, Area of path (P) is given by, $\green{\bf :\longmapsto\:P=A_1+A_2−Area \: of \: common \: path}$ $\rm :\longmapsto\:P=225 + 350 - 5 \times 5$ $\rm :\longmapsto\:P=575 - 25$ $\green{\bf :\longmapsto\:P = 550 \: {m}^{2}}$ ADDITIONAL INFORMATION :- $\boxed{ \sf \: Area_{(rectangle)} = length \times breadth}$ $\boxed{ \sf \: Area_{(square)} = {(side)}^{2}}$ $\boxed{ \sf \: Area_{(rhombus)} = base \times height}$ $\boxed{ \sf \: Area_{(parallelogram)} = base \times height}$ $\boxed{ \sf \: Area_{(circle)} = \pi {r}^{2} }$

7.

Two cross roads, each of width 5m, run at right angles through the centre of a rectanglepark of lengths 70m and breadth 45m and parallel to its sides. Find the area of the roads.

Answer»

$\large\underline{\bf{Solution-}}$

GIVEN that,

RECTANGULAR Park = ABCD

Longer Path = EFGH

Shorter Path = PQRS

Common Path = WXYZ

Dimensions of FIELD are

$\rm :\longmapsto\:Length \: of \: rectangular \: park, \: l \: = \: 70 \: m$

$\rm :\longmapsto\:Width \: of \: rectangular \: park, \: b \: = \: 45 \: m$

$\red{\rm :\longmapsto\:Length \: of \: the \: shorter \: path, \: l_1=45 \: m}$

$\red{\rm :\longmapsto\:Breadth \: of \: the \: shorter \: path, \: b_1=5 \: m}$

$\blue{\rm :\longmapsto\:Length \: of \: the \: longer \: path, \: l_2=70 \: m}$

$\blue{\rm :\longmapsto\:Breadth \: of \: the \: longer \: path, \: b_2=5 \: m}$

Consider,

$\red{\bf :\longmapsto\:Area \: of \: shorter \: path, \: A_1=l_1×b_1}$

$\rm :\longmapsto\:A_1 = 45 \times 5$

$\red{\bf :\longmapsto\:A_1 = 225 \: {m}^{2}}$

Consider,

$\blue{\bf :\longmapsto\:Area \: of \: longer \: path, \: A_2=l_2×b_2}$

$\rm :\longmapsto\:A_2 = 70 \times 5$

$\blue{\bf :\longmapsto\:A_2 = 350\: {m}^{2}}$

Thus,

Area of path (P) is given by,

$\green{\bf :\longmapsto\:P=A_1+A_2−Area \: of \: common \: path}$

$\rm :\longmapsto\:P=225 + 350 - 5 \times 5$

$\rm :\longmapsto\:P=575 - 25$

$\green{\bf :\longmapsto\:P = 550 \: {m}^{2}}$

ADDITIONAL INFORMATION :-

$\boxed{ \sf \: Area_{(rectangle)} = length \times breadth}$

$\boxed{ \sf \: Area_{(square)} = {(side)}^{2}}$

$\boxed{ \sf \: Area_{(rhombus)} = base \times height}$

$\boxed{ \sf \: Area_{(parallelogram)} = base \times height}$

$\boxed{ \sf \: Area_{(circle)} = \pi {r}^{2} }$

Discussion

8.	A²x²+ (ax² + 1) x + a
Answer» ANSWER: GIVEN,A2X2+(AX2+1)x+a =a2x2+ax3+x+a = ax2(a+x)+1(a+x) =(ax2+1)(a+x)

8.

A²x²+ (ax² + 1) x + a

Answer»

ANSWER:

GIVEN,A2X2+(AX2+1)x+a

=a2x2+ax3+x+a

= ax2(a+x)+1(a+x)

=(ax2+1)(a+x)

Discussion

9.	Can anyone graph x+y=2 and 2x+2y=8
Answer» ANSWER: yes I can plot this data in graph but I didn't have graph paper right now , it is EASY . I love LINEAR equation in ONE variable not in two variable .

9.

Can anyone graph x+y=2 and 2x+2y=8

Answer»

ANSWER:

yes I can plot this data in graph but I didn't have graph paper right now , it is EASY . I love LINEAR equation in ONE variable not in two variable .

Discussion

10.	Divide 16952 by 187plz answer this question.fast plz
Answer» Answer: 187×quotent(9)+(122) REMINDER

10.

Divide 16952 by 187plz answer this question.fast plz

Answer»

Answer:

187×quotent(9)+(122) REMINDER

Discussion

11.	√3 is not rational number
Answer» letLet US assume on the contrary that 3 is a rational NUMBER. Then, there EXIST positive integers a and b such that 3=ba where, a and b, are co-prime i.e. their HCF is 1 Now, 3=ba ⇒3=b2a2 ⇒3b2=A2 ⇒3 divides a2[∵3 divides 3b2] ⇒3 divides a...(i) ⇒a=3c for some integer c ⇒a2=9c2 ⇒3b2=9c2[∵a2=3b2] ⇒b2=3c2 ⇒3 divides b2[∵3 divides 3c2] ⇒3 divides b. From (i) and (ii), we observe that a and b have at least 3 as a common factor. But, this CONTRADICTS the fact that a and b are co-prime. This means that our assumption is not correct. Hence, 3 is an irrational number.

11.

√3 is not rational number

Answer»

letLet US assume on the contrary that 3 is a rational NUMBER.

Then, there EXIST positive integers a and b such that

3=ba where, a and b, are co-prime i.e. their HCF is 1

Now,

3=ba

⇒3=b2a2

⇒3b2=A2

⇒3 divides a2[∵3 divides 3b2]

⇒3 divides a...(i)

⇒a=3c for some integer c

⇒a2=9c2

⇒3b2=9c2[∵a2=3b2]

⇒b2=3c2

⇒3 divides b2[∵3 divides 3c2]

⇒3 divides b.

From (i) and (ii), we observe that a and b have at least 3 as a common factor. But, this CONTRADICTS the fact that a and b are co-prime. This means that our assumption is not correct.

Hence, 3 is an irrational number.

Discussion

12.	the product of two rational number is 15/56 . if one of the number is -5/48 ,find the other. (show the step by step)
Answer» Answer: The other number is - 18/7. Step-by-step explanation: Given that: The product of two RATIONAL number is 15/56. One of the number is -5/48. To Find: The other number. Let us assume: The other number be x. Finding the other number: ACCORDING to the question. ⟿ - 5/48 × x = 15/56 ⟿ x = (15 × 48)/(56 × - 5) ⟿ x = - 18/7 ∴ The other number = - 18/7

12.

the product of two rational number is 15/56 . if one of the number is -5/48 ,find the other. (show the step by step)

Answer»

Answer:

The other number is - 18/7.

Step-by-step explanation:

Given that:

The product of two RATIONAL number is 15/56.
One of the number is -5/48.

To Find:

The other number.

Let us assume:

The other number be x.

Finding the other number:

ACCORDING to the question.

⟿ - 5/48 × x = 15/56

⟿ x = (15 × 48)/(56 × - 5)

⟿ x = - 18/7

∴ The other number = - 18/7

Discussion

13.	To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80° to a distance of 16.5 km. Find the area of the sea over which the ships are warned. (Use π = 3.14)Instructions:- ❎ No Spamming ❎✔️Quality Answers Needed✔️❎No Websites Answers ❎Spam+Websites answer will be reported!!!!Important Notice:- Answer Will Be shown to Moderators..All the best :)
Answer» ${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$ ${\bigstar \: {\pmb{\sf{\underline{Understanding \: the \: Question...}}}}}$ ⋆ This question says that we have to find out the area of the sea over which the ships are warned. Given that: To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80 degrees, means there is light over a sector of angle to a distance of 16.5 kilometres. As it's a sector henceforth, the distance be the radius of the circle. It is ALSO given that we have to TAKE the value of π as 3.14 It is also cleared that we have to USE formula regard where π is used. Let us see how to solve this question properly! ${\bigstar \: {\pmb{\sf{\underline{Given \: that...}}}}}$ ⠀⠀⠀⠀ ⠀⠀⠀To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80° to a distance of 16.5 km. ⋆ Radius = 16.5 kilometres ⋆ Angle = 80 degrees ${\bigstar \: {\pmb{\sf{\underline{To \: find...}}}}}$ ⋆ The area of the sea over which the ships are warned. ${\bigstar \: {\pmb{\sf{\underline{Solution...}}}}}$ ⋆ The area of the sea over which the ships are warned = 189.97 km² ${\bigstar \: {\pmb{\sf{\underline{Using \: concept...}}}}}$ ⋆ Formula to find out the area of the sector of a circle. ${\bigstar \: {\pmb{\sf{\underline{Using \: formula...}}}}}$ Remember that the formula to find out the area of circle is πr²? Nice! ${\underline{\boxed{\pmb{\sf{\star \: \dfrac{\theta}{360 \degree} \times \pi r^2}}}}}$ ${\bigstar \: {\pmb{\sf{\underline{Where...}}}}}$ ⋆ θ denotes angle ⋆ θ is pronounced as theta ⋆ π is pronounced as pi ⋆ The value of π is 22/7 or 3.14 ⠀⠀⠀⠀ ⠀⠀(But according to the question, we have to take the value of π as 3.14) ⋆ r denotes radius ${\bigstar \: {\pmb{\sf{\underline{Full \; Solution...}}}}}$ ~ Now we just have to use the given formula and have to put the values according to that and at last we get our final RESULT very easily! Let's do it! $:\implies \sf \dfrac{\theta}{360 \degree} \times \pi r^2 \\ \\ :\implies \sf \dfrac{80}{360} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{8{\cancel{0}}}{36{\cancel{0}}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{8}{36} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \cancel{\dfrac{8}{36}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \cancel{\dfrac{4}{18}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times 16.5 \times 16.5 \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times 272.25 \\ \\ :\implies \sf \dfrac{2}{9} \times 8548.50 \\ \\ :\implies \sf 189.97 \: km \: sq. \\ \\ {\pmb{\sf{Hence, \: 189.97 \: km \: sq. \: is \: area \dots \dots}}}$ ${\large{\pmb{\sf{\underline{AdditioNal \: Knowledge...}}}}}$ ★ The region between the chord and either of it's arcs is known as the segment of a circle or a circular region. ★ There are two type of segments that are major segment and minor segment. ★ The region between an arc and the two radii, joining the centre to the end points of the arc is known as sector. *________________* Dear web users, you can see the step of cancelling from the attachment 1st Thanks for understanding! Kindly see the DIAGRAM regard question from attachment 2nd.

13.

To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80° to a distance of 16.5 km. Find the area of the sea over which the ships are warned. (Use π = 3.14)Instructions:- ❎ No Spamming ❎✔️Quality Answers Needed✔️❎No Websites Answers ❎Spam+Websites answer will be reported!!!!Important Notice:- Answer Will Be shown to Moderators..All the best :)

Answer»

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

${\bigstar \: {\pmb{\sf{\underline{Understanding \: the \: Question...}}}}}$

⋆ This question says that we have to find out the area of the sea over which the ships are warned. Given that: To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80 degrees, means there is light over a sector of angle to a distance of 16.5 kilometres. As it's a sector henceforth, the distance be the radius of the circle. It is ALSO given that we have to TAKE the value of π as 3.14 It is also cleared that we have to USE formula regard where π is used. Let us see how to solve this question properly!

${\bigstar \: {\pmb{\sf{\underline{Given \: that...}}}}}$

⠀⠀⠀⠀ ⠀⠀⠀To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80° to a distance of 16.5 km.

⋆ Radius = 16.5 kilometres

⋆ Angle = 80 degrees

${\bigstar \: {\pmb{\sf{\underline{To \: find...}}}}}$

⋆ The area of the sea over which the ships are warned.

${\bigstar \: {\pmb{\sf{\underline{Solution...}}}}}$

⋆ The area of the sea over which the ships are warned = 189.97 km²

${\bigstar \: {\pmb{\sf{\underline{Using \: concept...}}}}}$

⋆ Formula to find out the area of the sector of a circle.

${\bigstar \: {\pmb{\sf{\underline{Using \: formula...}}}}}$

Remember that the formula to find out the area of circle is πr²? Nice!

${\underline{\boxed{\pmb{\sf{\star \: \dfrac{\theta}{360 \degree} \times \pi r^2}}}}}$

${\bigstar \: {\pmb{\sf{\underline{Where...}}}}}$

⋆ θ denotes angle

⋆ θ is pronounced as theta

⋆ π is pronounced as pi

⋆ The value of π is 22/7 or 3.14

⠀⠀⠀⠀ ⠀⠀(But according to the question, we have to take the value of π as 3.14)

⋆ r denotes radius

${\bigstar \: {\pmb{\sf{\underline{Full \; Solution...}}}}}$

~ Now we just have to use the given formula and have to put the values according to that and at last we get our final RESULT very easily! Let's do it!

$:\implies \sf \dfrac{\theta}{360 \degree} \times \pi r^2 \\ \\ :\implies \sf \dfrac{80}{360} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{8{\cancel{0}}}{36{\cancel{0}}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{8}{36} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \cancel{\dfrac{8}{36}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \cancel{\dfrac{4}{18}} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times (16.5)^{2} \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times 16.5 \times 16.5 \\ \\ :\implies \sf \dfrac{2}{9} \times 3.14 \times 272.25 \\ \\ :\implies \sf \dfrac{2}{9} \times 8548.50 \\ \\ :\implies \sf 189.97 \: km \: sq. \\ \\ {\pmb{\sf{Hence, \: 189.97 \: km \: sq. \: is \: area \dots \dots}}}$

${\large{\pmb{\sf{\underline{AdditioNal \: Knowledge...}}}}}$

★ The region between the chord and either of it's arcs is known as the segment of a circle or a circular region.

★ There are two type of segments that are major segment and minor segment.

★ The region between an arc and the two radii, joining the centre to the end points of the arc is known as sector.

________________

Dear web users, you can see the step of cancelling from the attachment 1st Thanks for understanding!

Kindly see the DIAGRAM regard question from attachment 2nd.

Discussion

14.	Find 64½ answerrrrrrrrrrrrrr pleaseeeeeeeee
Answer» ANSWER: answer is 8 Step-by-step explanation: 64½ = 8 I hope it HELPED you!! THANKS!!

14.

Find 64½ answerrrrrrrrrrrrrr pleaseeeeeeeee

Answer»

ANSWER:

answer is 8

Step-by-step explanation:

64½ = 8

I hope it HELPED you!! THANKS!!

Discussion

15.	show that the diagonal of a parallelogram divide it into four triangle of equal area (any one who helped me)
Answer» Step-by-step explanation: To PROVE:- AR(△AOB)=ar(△BOC)=ar(△COD)=ar(△AOD) Proof:- Let ABCD be a parallelogram with diagonals AC and BD intersecting at O. Since the diagonals of a parallelogram bisect each other at the point of intersection. Therefore, AO=OC and BO=OD We KNOW that the median of a triangle divides it into two equal parts. Now, In △ABC, ∵BO is median. ar(△AOB)=ar(△BOC)._____(1) In △BCD, ∵CO is median. ar(△BOC)=ar(△COD)_____(2) In △ACD, ∵DO is median. ar(△AOD)=ar(△COD)._____(3) From equation (1),(2)&(3), we get ar(△AOB)=ar(△BOC)=ar(△COD)=ar(△AOD) Hence proved.

15.

show that the diagonal of a parallelogram divide it into four triangle of equal area (any one who helped me)

Answer»

Step-by-step explanation:

To PROVE:- AR(△AOB)=ar(△BOC)=ar(△COD)=ar(△AOD)

Proof:-

Let ABCD be a parallelogram with diagonals AC and BD

intersecting at O. Since the diagonals of a parallelogram bisect each other at the point of intersection.

Therefore,

AO=OC and BO=OD

We KNOW that the median of a triangle divides it into two equal parts.

Now,

In △ABC,

∵BO is median.

ar(△AOB)=ar(△BOC)._____(1)

In △BCD,

∵CO is median.

ar(△BOC)=ar(△COD)_____(2)

In △ACD,

∵DO is median.

ar(△AOD)=ar(△COD)._____(3)

From equation (1),(2)&(3), we get

ar(△AOB)=ar(△BOC)=ar(△COD)=ar(△AOD)

Hence proved.

Discussion

16.	The demand function is a/an ____________.
Answer» Answer: ACROCENTRIC If the CENTROMERE is situated near the end of the CHROMOSOME, the chromosome is CALLED acrocentric.

16.

The demand function is a/an ____________.

Answer»

Answer:

ACROCENTRIC

If the CENTROMERE is situated near the end of the CHROMOSOME, the chromosome is CALLED acrocentric.

Discussion

17.	Find the 27th term of the following A.P.9, 4, –1, –6, –11,…
Answer» ANSWER: ALWAYS LESS 5 CONTINUOUSLY

17.

Find the 27th term of the following A.P.9, 4, –1, –6, –11,…

Answer»

ANSWER:

ALWAYS LESS 5 CONTINUOUSLY

Discussion

18.	Triangles are similar. Find the value of A
Answer» Answer: a = 14.46 Step-by-step explanation: (6²-a²)^½ = [108 - (12-a)²]^½ 6² - a² = 108 - 144 + a² -24A 36 - 2a² = -36 - 24a 72 - 2a² + 24a = 0 2a² - 24a -72 = 0 a = -(-24) ± √[(-24)² - 4×2×-72] 2 × 2 a = 24 ± √[576 + 576] = 24 ± 24√2 = 6±6√2 4 4 a = 6(1+1.41) ≠ 6(1-1.41) a = 14.46

18.

Triangles are similar. Find the value of A

Answer»

Answer:

a = 14.46

Step-by-step explanation:

(6²-a²)^½ = [108 - (12-a)²]^½

6² - a² = 108 - 144 + a² -24A

36 - 2a² = -36 - 24a

72 - 2a² + 24a = 0

2a² - 24a -72 = 0

a = -(-24) ± √[(-24)² - 4×2×-72]

2 × 2

a = 24 ± √[576 + 576] = 24 ± 24√2 = 6±6√2

4 4

a = 6(1+1.41) ≠ 6(1-1.41)

a = 14.46

Discussion

19.	Factorise it-42x^3y^3-35y^2don't spam
Answer» ANSWER: Answer is -7y2(6x3y+5) Steps =−42x3y3−35y2 Apply EXPONENT RULE: ab+c=abac x3y3=y2y =−42y2y−35y2 Rewrite −35 as 5· 7 Rewrite −42 as 6· 7 =6· 7y2y+5· 7y2 Factor out COMMON TERM −7y2 =-7y2(6x3y+5)

19.

Factorise it-42x^3y^3-35y^2don't spam

Answer»

ANSWER:

Answer is -7y2(6x3y+5)

Steps

=−42x3y3−35y2

Apply EXPONENT RULE: ab+c=abac

x3y3=y2y

=−42y2y−35y2

Rewrite −35 as 5· 7

Rewrite −42 as 6· 7

=6· 7y2y+5· 7y2

Factor out COMMON TERM −7y2

=-7y2(6x3y+5)

Discussion

20.	Plz tell me the ans I have to submit my assignment
Answer» ANSWER: this is the answer.,...

20.

Plz tell me the ans I have to submit my assignment

Answer»

ANSWER:

this is the answer.,...

Discussion

21.	Given that root 5 is irrational prove that 5 plus root 5 is irrational
Answer» Answer: So it can be EXPRESSED in the FORM p/q where p,q are co-prime integers and q≠0 ⇒ √5 = p/q On SQUARING both the sides we get, ⇒5 = p²/q² ⇒5q² = p² —————–(i) p²/5 = q² So 5 divides p p is a multiple of 5 ⇒ p = 5m ⇒ p² = 25m² ————-(ii) From EQUATIONS (i) and (ii), then u Will get thanks me and mark me as brainlist

21.

Given that root 5 is irrational prove that 5 plus root 5 is irrational

Answer»

Answer:

So it can be EXPRESSED in the FORM p/q where p,q are co-prime integers and q≠0

⇒ √5 = p/q

On SQUARING both the sides we get,

⇒5 = p²/q²

⇒5q² = p² —————–(i)

p²/5 = q²

So 5 divides p

p is a multiple of 5

⇒ p = 5m

⇒ p² = 25m² ————-(ii)

From EQUATIONS (i) and (ii), then u Will get

thanks me and mark me as brainlist

Discussion

22.	4. 2x*2- X-6
Answer» Answer: 4. 2X*2- X-6 $2x {2 }^{2} - x - 6$

22.

4. 2x*2- X-6

Answer»

Answer:

4. 2X*2- X-6

$2x {2 }^{2} - x - 6$

Discussion

23.	List all the nuWrite the smallest and the largest numbers which are rounded off to 90.the mollect and the largest numbers which are rounded off to 130
Answer» ANSWER: Smallest number rounded off to 90 is 85 and the BIGGEST number is 94 Largest number which is rounded off to 130 is 134 Step-by-step EXPLANATION:

23.

List all the nuWrite the smallest and the largest numbers which are rounded off to 90.the mollect and the largest numbers which are rounded off to 130

Answer»

ANSWER:

Smallest number rounded off to 90 is 85 and the BIGGEST number is 94

Largest number which is rounded off to 130 is 134

Step-by-step EXPLANATION:

Discussion

24.	500 रु को abc में इस प्रकार विभाजित किया जाता है की a के हिस्से के 2/5 भाग से 16 ज्यादा ,b के हिस्से के 3/4 भाग से 70 कम और c के हिस्से के 3/5 भाग से 4 कम बराबर है तो b का हिस्सा ?
Answer» Answer: 500 रु को ABC में इस प्रकार विभाजित किया जाता है की a के हिस्से के 2/5 भाग से 16 ज्यादा ,B के हिस्से के 3/4 भाग से

24.

500 रु को abc में इस प्रकार विभाजित किया जाता है की a के हिस्से के 2/5 भाग से 16 ज्यादा ,b के हिस्से के 3/4 भाग से 70 कम और c के हिस्से के 3/5 भाग से 4 कम बराबर है तो b का हिस्सा ?

Answer»

Answer:

500 रु को ABC में इस प्रकार विभाजित किया जाता है की a के हिस्से के 2/5 भाग से 16 ज्यादा ,B के हिस्से के 3/4 भाग से

Discussion

25.	At the time of shipping, Tom can place 10 small boxes or 8 large boxes into a carton. A total of 96 boxes were sent in one shipment. The number of small boxes was less than large boxes. What is the total number of cartons he shipped? Give me answer fast urgent
Answer» Answer: y of a GOOD weekend of a lot to learn about this and let the best thing in my CASE the FIRST one that was what the PROBLEM I can do you want a great time with a bit more information please do so MUCH and a lot more information on how do you know what I am

25.

At the time of shipping, Tom can place 10 small boxes or 8 large boxes into a carton. A total of 96 boxes were sent in one shipment. The number of small boxes was less than large boxes. What is the total number of cartons he shipped? Give me answer fast urgent

Answer»

Answer:

y of a GOOD weekend of a lot to learn about this and let the best thing in my CASE the FIRST one that was what the PROBLEM I can do you want a great time with a bit more information please do so MUCH and a lot more information on how do you know what I am

Discussion

26.	find the area of triangle ABC , whose coordinates are A (4, - 6), B (3,-2) and C (5,2) then find the length of the median AD ?
Answer» ANSWER: SMALL WOODEN 666874 ei 9*75639 yiogdd etji rod rugg

26.

find the area of triangle ABC , whose coordinates are A (4, - 6), B (3,-2) and C (5,2) then find the length of the median AD ?

Answer»

ANSWER:

SMALL WOODEN 666874

ei 9*75639

yiogdd

etji rod

rugg

Discussion

27.	standard form of rational numbers minus 3 upon 8 minus 5 upon 2 - 7 upon 16 - 13 upon 18 11 upon - 24
Answer» Answer: share s can be a GOOD time by paying this INVOICE X factor be CONSIDERED for s Step-by-step explanation: old songs regards to the same DAY as well v

27.

standard form of rational numbers minus 3 upon 8 minus 5 upon 2 - 7 upon 16 - 13 upon 18 11 upon - 24

Answer»

Answer:

share s can be a GOOD time by paying this INVOICE X factor be CONSIDERED for s

Step-by-step explanation:

old songs regards to the same DAY as well v

Discussion

28.	Construct ∆XYZ such that XY = 3.5 cm, ∠Y = 55˚, YZ = 5 cm. Draw incircle of ∆XYZ.
Answer» Answer: Hope it will be helpfull to you Step-by-step explanation: (i) Draw a line SEGMENT which is sufficiently long using RULER. (ii) LOCATE points X and Y on it such that XY=3.5cm. (iii) At Y, construct a line segment YW, sufficiently large, such that ∠XYZ=100˚ ; use protractor to measure 100˚ (iv) With Y as centre and radius 5.5 CM, draw the line cutting YW at Z; join XZ. ⇒ Then XYZ is the required triangle.

28.

Construct ∆XYZ such that XY = 3.5 cm, ∠Y = 55˚, YZ = 5 cm. Draw incircle of ∆XYZ.

Answer»

Answer:

Hope it will be helpfull to you

Step-by-step explanation:

(i) Draw a line SEGMENT which is sufficiently long using RULER.

(ii) LOCATE points X and Y on it such that XY=3.5cm.

(iii) At Y, construct a line segment YW, sufficiently large, such that ∠XYZ=100˚ ; use protractor to measure 100˚

(iv) With Y as centre and radius 5.5 CM, draw the line cutting YW at Z; join XZ.

⇒ Then XYZ is the required triangle.

Discussion

29.	1 by 2+ 1 by 2 square+ 1 by 2 cube+ 1 by 2 rises 4
Answer» ANSWER: 15/16 is the answer for UR QUESTION

29.

1 by 2+ 1 by 2 square+ 1 by 2 cube+ 1 by 2 rises 4

Answer»

ANSWER:

15/16 is the answer for UR QUESTION

Discussion

30.	4 lemons are bought for Rs 40 and sold 3 for Rs 24. Find the profit or loss percent
Answer» Step-by-step EXPLANATION: eueueururjddjdjjdjdjdjdjdjdjdjdidjfjfnfnfnf

30.

4 lemons are bought for Rs 40 and sold 3 for Rs 24. Find the profit or loss percent

Answer»

Step-by-step EXPLANATION:

eueueururjddjdjjdjdjdjdjdjdjdjdidjfjfnfnfnf

Discussion

31.	LTE LTE 45% - 9:28 PMQ. 4income or expenditure exceeding of the revenuefrom operation or Rs. 100000 whichever is higher needto be disclosed by way of notes(A)1%(B)2%(C)5%(D)10%Now Ulland Mari
Answer» Answer: questions KYA hai Step-by-step EXPLANATION: please write in COMMENTS box

31.

LTE LTE 45% - 9:28 PMQ. 4income or expenditure exceeding of the revenuefrom operation or Rs. 100000 whichever is higher needto be disclosed by way of notes(A)1%(B)2%(C)5%(D)10%Now Ulland Mari

Answer»

Answer:

questions KYA hai

Step-by-step EXPLANATION:

please write in COMMENTS box

Discussion

32.	For any integer a, a ÷0 is ______.
Answer» Answer: undefined Step-by-step explanation: any INTEGER DIVIDED by ZERO is undefined or infinity

32.

For any integer a, a ÷0 is ______.

Answer»

Answer:

undefined

Step-by-step explanation:

any INTEGER DIVIDED by ZERO is undefined or infinity

Discussion

33.	) In a hostel canteen 50 students can finish food items in 2 months.In how many months can 30 students finish the same food itemsstep by step
Answer» Answer: 6/5 Step-by-step explanation: 50 STUDENTS - 2 months =60 days 30 students -? 50:30=2:x PRODUCT of means =product of EXTREMES 30×2=50×x 60 =50x 60/50 =x 6/5=x . then , x = 6/5×30/1=36 days .

33.

) In a hostel canteen 50 students can finish food items in 2 months.In how many months can 30 students finish the same food itemsstep by step

Answer»

Answer:

6/5

Step-by-step explanation:

50 STUDENTS - 2 months =60 days

30 students -?

50:30=2:x

PRODUCT of means =product of EXTREMES

30×2=50×x

60 =50x

60/50 =x

6/5=x .

then , x = 6/5×30/1=36 days .

Discussion

34.	How much maximum volume of right circular cone can be formed by a cube with side 9cm
Answer» ANSWER: Since the cube's edge is 9cm, the HEIGHT of the largest cone cut out from the cube is also 9 cm. Also the diameter of the base of the cube WOULD also be 9 cm as the base covers and touches all parts of the EDGES of the cube. HENCE Radius would be half of 9 which is 4.5 cm

34.

How much maximum volume of right circular cone can be formed by a cube with side 9cm

Answer»

ANSWER:

Since the cube's edge is 9cm, the HEIGHT of the largest cone cut out from the cube is also 9 cm. Also the diameter of the base of the cube WOULD also be 9 cm as the base covers and touches all parts of the EDGES of the cube. HENCE Radius would be half of 9 which is 4.5 cm

Discussion

35.	X= ½-x , find the value of (i) x + ⅟x ,(ii) x² + ⅟x² ,(iii) x³ + ⅟x³
Answer» ANSWER: ????????????????????????

35.

X= ½-x , find the value of (i) x + ⅟x ,(ii) x² + ⅟x² ,(iii) x³ + ⅟x³

Answer»

ANSWER:

????????????????????????

Discussion

36.	Insert the resnal number of 2.5 and 3.5
Answer» Answer: 3. Step-by-step EXPLANATION: MARK me as BRAINLIEST

36.

Insert the resnal number of 2.5 and 3.5

Answer»

Answer:

3.

Step-by-step EXPLANATION:

MARK me as BRAINLIEST

Discussion

37.	If 2a2b, 4ab2, x are in continued proportion then find the value of x.
Answer» 2a2b, 4AB2, X in CONTINUED proportion (2a2b./ 4ab2) = (4ab2/x) x= [(4ab2) *( 4ab2) ] / 2a2b = 4ab2 × 2a = 8a^2 B2

37.

If 2a2b, 4ab2, x are in continued proportion then find the value of x.

Answer»

2a2b, 4AB2, X in CONTINUED proportion

(2a2b./ 4ab2) = (4ab2/x)

x= [(4ab2) *( 4ab2) ] / 2a2b

= 4ab2 × 2a = 8a^2 B2

Discussion

38.	Prove that any finitely generated subgroup (Q,+) is cyclic
Answer» Step-by-step explanation: 〉 and HENCE H is cyclic itself. This PROVES the claim that EVERY finitely generated subgroup of Q is cyclic. ... For example, 〈(1, 0), (0, 1)〉 = Z × Z is finitely generated but not cyclic. This implies that the groups Q and Q × Q are not isomorphic.

38.

Prove that any finitely generated subgroup (Q,+) is cyclic

Answer»

Step-by-step explanation:

〉 and HENCE H is cyclic itself. This PROVES the claim that EVERY finitely generated subgroup of Q is cyclic. ... For example, 〈(1, 0), (0, 1)〉 = Z × Z is finitely generated but not cyclic. This implies that the groups Q and Q × Q are not isomorphic.

Discussion

39.	Give me the Answerof worksheet
Answer» Step-by-step EXPLANATION: 1) (a) 12342, 67544, 76654, 90876, 56509 (b) 50101, 50021, 50002, 50045, 50066, 50098 (c) 34541, 38654, 36665, 38765, 32767, 31209 2) (a) 56170, 56150, 56140, 56130, 56120, 56110 (b) 78968, 15467, 54367, 43267, 66543, 34215 (c) 90009, 90006, 90005, 90004, 90002, 90001

39.

Give me the Answerof worksheet

Answer»

Step-by-step EXPLANATION:

1) (a) 12342, 67544, 76654, 90876, 56509

(b) 50101, 50021, 50002, 50045, 50066, 50098

(c) 34541, 38654, 36665, 38765, 32767, 31209

2) (a) 56170, 56150, 56140, 56130, 56120, 56110

(b) 78968, 15467, 54367, 43267, 66543, 34215

(c) 90009, 90006, 90005, 90004, 90002, 90001

Discussion

40.	Factories it-21a-15b+9Don't spam
Answer» Answer: 3(7a-5b+3) Step-by-step EXPLANATION: HOPE it HELPS you

40.

Factories it-21a-15b+9Don't spam

Answer»

Answer:

3(7a-5b+3)

Step-by-step EXPLANATION:

HOPE it HELPS you

Discussion

41.	If 3x-2y=18 , x=-1 , find y
Answer» Answer: 3x-2y=18 , X=-1 put x value 3(-1)-2y=18 -3-2y=18 -2y =18+3 -2y = 21 y =-21/2

41.

If 3x-2y=18 , x=-1 , find y

Answer»

Answer:

3x-2y=18 , X=-1

put x value

3(-1)-2y=18

-3-2y=18

-2y =18+3

-2y = 21

y =-21/2

Discussion

42.	Cos/1-sin = 1/sin+cos solve l.h.s =r.h.s
Answer» $\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$ वंशीधर पिता से आशीर्वाद लेकर नौकरी की तलाश में निकल जाते हैं। भाग्य से नमक विभाग के दारोगा पद की नौकरी मिल जाती है जिसमें वेतन अच्छा था साथ ही ऊपरी कमाई भी ज्यादा थी। यह खबर जब पिता को पता चली तो वह बहुत खुश हुए। मुंशी वंशीधर ने छः महीने में अपनी कार्यकुशलता और अच्छे आचरण से सभी अधिकारियों को मोहित कर लिया।

42.

Cos/1-sin = 1/sin+cos solve l.h.s =r.h.s

Answer»

$\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

वंशीधर पिता से आशीर्वाद लेकर नौकरी की तलाश में निकल जाते हैं। भाग्य से नमक विभाग के दारोगा पद की नौकरी मिल जाती है जिसमें वेतन अच्छा था साथ ही ऊपरी कमाई भी ज्यादा थी। यह खबर जब पिता को पता चली तो वह बहुत खुश हुए। मुंशी वंशीधर ने छः महीने में अपनी कार्यकुशलता और अच्छे आचरण से सभी अधिकारियों को मोहित कर लिया।

Discussion

43.	Prove that the quadratic equation x square+ax-4=0 has distinct, real roots.
Answer» Step-by-step EXPLANATION: *Prove that the QUADRATIC equation X square+ax-4=0 has distinct, REAL ROOTS.*

43.

Prove that the quadratic equation x square+ax-4=0 has distinct, real roots.

Answer»

Step-by-step EXPLANATION:

Prove that the QUADRATIC equation X square+ax-4=0 has distinct, REAL ROOTS.

Discussion

44.	Can you graph x+y=2 and 2 x+2 y=8
Answer» Answer: *Here* is a *ROUGH* *GRAPH* *HOPE* *this* *helps* *youuu.. PEACE*.......

44.

Can you graph x+y=2 and 2 x+2 y=8

Answer»

Answer:

Here is a ROUGH GRAPH HOPE this helps youuu..

PEACE.......

Discussion

45.	Show that the diagonal of a parallelogram divide it into four triangle of equal area
Answer» ANSWER: HI do U USE inst.a FLW me them_1266

45.

Show that the diagonal of a parallelogram divide it into four triangle of equal area

Answer»

ANSWER:

HI do U USE inst.a FLW me them_1266

Discussion

46.	the lengthof room is two times its breadth and five times its height if the volume of the room is hundred metre cube what is the cost of the paying is for wall and selling at rs 6 per square metre
Answer» ANSWER: L DONT KNOW what is this Step-by-step EXPLANATION:

46.

the lengthof room is two times its breadth and five times its height if the volume of the room is hundred metre cube what is the cost of the paying is for wall and selling at rs 6 per square metre

Answer»

ANSWER:

L DONT KNOW what is this

Step-by-step EXPLANATION:

Discussion

47.	A और B एक कार्य को ₹ 4500 में करने के लिए तैयार होते हैं। Aअकेला उस कार्य को 8 दिन में और B अकेला उस कार्य को 12 दिनमेंपूराकर सकता है। C की सहायता से वे इस कार्य को 4 दिन मेंकरते हैं। बताएं कि इस राशि में C का हिस्सा कितना होगा?₹ 1500(d) ₹2250
Answer» ANSWER: ho gi JOE the correct NUMBER for a while then I need to do to the BODY

47.

A और B एक कार्य को ₹ 4500 में करने के लिए तैयार होते हैं। Aअकेला उस कार्य को 8 दिन में और B अकेला उस कार्य को 12 दिनमेंपूराकर सकता है। C की सहायता से वे इस कार्य को 4 दिन मेंकरते हैं। बताएं कि इस राशि में C का हिस्सा कितना होगा?₹ 1500(d) ₹2250

Answer»

ANSWER:

ho gi JOE the correct NUMBER for a while then I need to do to the BODY

Discussion

48.	Solve: 52 − 2 − 3 = 0 (By SDA formula)
Answer» ANSWER: 2-2-3=0 2-5=0 -3=0 =3 it is your answer i HOPE you it HELPED

48.

Solve: 52 − 2 − 3 = 0 (By SDA formula)

Answer»

ANSWER:

2-2-3=0

2-5=0

-3=0

=3

it is your answer i HOPE you it HELPED

Discussion

49.	Prove that tan48º. tan27º. tan42°. tan63°. cot45° = sec²30° - tan²30°
Answer» ANSWER: answer is in the PIC PLEASE MARK my answer as BRAINLIEST answer

49.

Prove that tan48º. tan27º. tan42°. tan63°. cot45° = sec²30° - tan²30°

Answer»

ANSWER:

answer is in the PIC

PLEASE MARK my answer as BRAINLIEST answer

Discussion

50.	The coordinates of a point m(4,-3).what are the distance of the point m from areas
Answer» Step-by-step EXPLANATION: soryyyyyyyyyyyyyyy dontttttttttt knowwwww

50.

The coordinates of a point m(4,-3).what are the distance of the point m from areas

Answer»

Step-by-step EXPLANATION:

soryyyyyyyyyyyyyyy dontttttttttt knowwwww

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Solve the following simuttaners equation. 2x+y=5 ; 3x-y=5 .​

Without actually performing the long division, state whether the following rationalnumbers will have a terminating decimal expansion or a non-terminating repeating decimalexpansion:​

(d) 180 minutes makehours.​

Find the mean:60,50,54,46,50​

FINAL ANSWER:-

GIVEN:-

TO FIND:-

FORMULA USED:-

SOLUTION:-

Two cross roads, each of width 5m, run at right angles through the centre of a rectanglepark of lengths 70m and breadth 45m and parallel to its sides. Find the area of the roads.​

Dimensions of FIELD are

Consider,

Consider,

Thus,

ADDITIONAL INFORMATION :-

A²x²+ (ax² + 1) x + a​

Can anyone graph x+y=2 and 2x+2y=8

Divide 16952 by 187plz answer this question.fast plz​

√3 is not rational number

the product of two rational number is 15/56 . if one of the number is -5/48 ,find the other. (show the step by step)​

________________

Find 64½ answerrrrrrrrrrrrrr pleaseeeeeeeee​

show that the diagonal of a parallelogram divide it into four triangle of equal area​ (any one who helped me)​

The demand function is a/an ____________.​

Find the 27th term of the following A.P.9, 4, –1, –6, –11,…​

Triangles are similar. Find the value of A

Factorise it-42x^3y^3-35y^2don't spam​

Plz tell me the ans I have to submit my assignment​

Given that root 5 is irrational prove that 5 plus root 5 is irrational​

4. 2x*2- X-6​

List all the nuWrite the smallest and the largest numbers which are rounded off to 90.the mollect and the largest numbers which are rounded off to 130​

At the time of shipping, Tom can place 10 small boxes or 8 large boxes into a carton. A total of 96 boxes were sent in one shipment. The number of small boxes was less than large boxes. What is the total number of cartons he shipped? Give me answer fast urgent ​

find the area of triangle ABC , whose coordinates are A (4, - 6), B (3,-2) and C (5,2) then find the length of the median AD ?​

standard form of rational numbers minus 3 upon 8 minus 5 upon 2 - 7 upon 16 - 13 upon 18 11 upon - 24​

Construct ∆XYZ such that XY = 3.5 cm, ∠Y = 55˚, YZ = 5 cm. Draw incircle of ∆XYZ.

1 by 2+ 1 by 2 square+ 1 by 2 cube+ 1 by 2 rises 4

4 lemons are bought for Rs 40 and sold 3 for Rs 24. Find the profit or loss percent

LTE LTE 45% - 9:28 PMQ. 4income or expenditure exceeding of the revenuefrom operation or Rs. 100000 whichever is higher needto be disclosed by way of notes(A)1%(B)2%(C)5%(D)10%Now Ulland Mari​

For any integer a, a ÷0 is ______.

) In a hostel canteen 50 students can finish food items in 2 months.In how many months can 30 students finish the same food itemsstep by step​

How much maximum volume of right circular cone can be formed by a cube with side 9cm

X= ½-x , find the value of (i) x + ⅟x ,(ii) x² + ⅟x² ,(iii) x³ + ⅟x³

Insert the resnal number of 2.5 and 3.5

If 2a2b, 4ab2, x are in continued proportion then find the value of x.​

Prove that any finitely generated subgroup (Q,+) is cyclic ​

Give me the Answerof worksheet​

Factories it-21a-15b+9Don't spam ​

If 3x-2y=18 , x=-1 , find y​

Cos/1-sin = 1/sin+cos solve l.h.s =r.h.s​

Prove that the quadratic equation x square+ax-4=0 has distinct, real roots.​

Can you graph x+y=2 and 2 x+2 y=8

Show that the diagonal of a parallelogram divide it into four triangle of equal area​

the lengthof room is two times its breadth and five times its height if the volume of the room is hundred metre cube what is the cost of the paying is for wall and selling at rs 6 per square metre ​

Solve: 52 − 2 − 3 = 0 (By SDA formula)​

Prove that tan48º. tan27º. tan42°. tan63°. cot45° = sec²30° - tan²30°​

The coordinates of a point m(4,-3).what are the distance of the point m from areas​

Solve the following simuttaners equation. 2x+y=5 ; 3x-y=5 .

Without actually performing the long division, state whether the following rationalnumbers will have a terminating decimal expansion or a non-terminating repeating decimalexpansion:

(d) 180 minutes makehours.

Find the mean:60,50,54,46,50

Two cross roads, each of width 5m, run at right angles through the centre of a rectanglepark of lengths 70m and breadth 45m and parallel to its sides. Find the area of the roads.

A²x²+ (ax² + 1) x + a

Divide 16952 by 187plz answer this question.fast plz

the product of two rational number is 15/56 . if one of the number is -5/48 ,find the other. (show the step by step)

Find 64½ answerrrrrrrrrrrrrr pleaseeeeeeeee

show that the diagonal of a parallelogram divide it into four triangle of equal area (any one who helped me)

The demand function is a/an ____________.

Find the 27th term of the following A.P.9, 4, –1, –6, –11,…

Factorise it-42x^3y^3-35y^2don't spam

Plz tell me the ans I have to submit my assignment

Given that root 5 is irrational prove that 5 plus root 5 is irrational

4. 2x*2- X-6

List all the nuWrite the smallest and the largest numbers which are rounded off to 90.the mollect and the largest numbers which are rounded off to 130

At the time of shipping, Tom can place 10 small boxes or 8 large boxes into a carton. A total of 96 boxes were sent in one shipment. The number of small boxes was less than large boxes. What is the total number of cartons he shipped? Give me answer fast urgent

find the area of triangle ABC , whose coordinates are A (4, - 6), B (3,-2) and C (5,2) then find the length of the median AD ?

standard form of rational numbers minus 3 upon 8 minus 5 upon 2 - 7 upon 16 - 13 upon 18 11 upon - 24

LTE LTE 45% - 9:28 PMQ. 4income or expenditure exceeding of the revenuefrom operation or Rs. 100000 whichever is higher needto be disclosed by way of notes(A)1%(B)2%(C)5%(D)10%Now Ulland Mari

) In a hostel canteen 50 students can finish food items in 2 months.In how many months can 30 students finish the same food itemsstep by step

If 2a2b, 4ab2, x are in continued proportion then find the value of x.

Prove that any finitely generated subgroup (Q,+) is cyclic

Give me the Answerof worksheet

Factories it-21a-15b+9Don't spam

If 3x-2y=18 , x=-1 , find y

Cos/1-sin = 1/sin+cos solve l.h.s =r.h.s

Prove that the quadratic equation x square+ax-4=0 has distinct, real roots.

Show that the diagonal of a parallelogram divide it into four triangle of equal area

the lengthof room is two times its breadth and five times its height if the volume of the room is hundred metre cube what is the cost of the paying is for wall and selling at rs 6 per square metre

Solve: 52 − 2 − 3 = 0 (By SDA formula)

Prove that tan48º. tan27º. tan42°. tan63°. cot45° = sec²30° - tan²30°

The coordinates of a point m(4,-3).what are the distance of the point m from areas