332354 + Interview Questions in Secondary School in Math

1.	The numerator of a fraction is 3 less than its denominator. if the numerator is increased by 1 and the denominator is increased by 3 the fraction becomes 1 by 2. find the original fraction?Please answer with step by step explanation .
Answer» ANSWER: LET denominator be x... ACC. to the question numerator will b x-3 acc. to the question: (x-2)/(x+3) = 1/2 2x - 4 = x + 3 x = 7 denominator, x= 7 numerator, x-3= 4 original fraction= 4/7

1.

The numerator of a fraction is 3 less than its denominator. if the numerator is increased by 1 and the denominator is increased by 3 the fraction becomes 1 by 2. find the original fraction?Please answer with step by step explanation .

Answer»

ANSWER:

LET denominator be x... ACC. to the question numerator will b x-3

acc. to the question:

(x-2)/(x+3) = 1/2

2x - 4 = x + 3

x = 7

denominator, x= 7

numerator, x-3= 4

original fraction= 4/7

Discussion

2.	In a circle of diameter 56 cm, an arc subtends an angle of 60° at the centre, then what will be the length of arc. (=22/7)
Answer» ANSWER: GIVEN: Diameter of the CIRCLE = 56 cm Radius of the circle = 56/2 = 28 cm An arc subtends an and of 60° at the centre. To Find: The length of the arc. Formula: Length of the arc = THETA / 360° × 2πr Solution: According to the question, Theta = 60° π = 22/7 r, radius = 28 cm Length of the arc = 60°/360° × 2 × 22/7 × 28 Length of the arc = 1/6 × 44/7 × 28 Length of the arc = 1/3 × 22 × 4 Length of the arc = 88/3 Length of the arc = 29.3 cm (approx.)

2.

In a circle of diameter 56 cm, an arc subtends an angle of 60° at the centre, then what will be the length of arc. (=22/7)

Answer»

ANSWER:

GIVEN:

Diameter of the CIRCLE = 56 cm

Radius of the circle = 56/2 = 28 cm

An arc subtends an and of 60° at the centre.

To Find:

The length of the arc.

Formula:

Length of the arc = THETA / 360° × 2πr

Solution:

According to the question,

Theta = 60°

π = 22/7

r, radius = 28 cm

Length of the arc = 60°/360° × 2 × 22/7 × 28

Length of the arc = 1/6 × 44/7 × 28

Length of the arc = 1/3 × 22 × 4

Length of the arc = 88/3

Length of the arc = 29.3 cm (approx.)

Discussion

3.	17. Name the property under multiplication used in each of the following(3/4)×(4/3) = 1(ii) 2/5 x (1/5x3/5) = (2/5 x 1/5) ×3/511/13×(-5/7) =(-5/7) ×11/13(iv) 2/3 (4/7 - 3/5) = (2/3x4/7) - (2/3 x 5/7) -(2/3×3/5)
Answer» ANSWER: COMMUTATIVE PROPERTY.

3.

17. Name the property under multiplication used in each of the following(3/4)×(4/3) = 1(ii) 2/5 x (1/5x3/5) = (2/5 x 1/5) ×3/511/13×(-5/7) =(-5/7) ×11/13(iv) 2/3 (4/7 - 3/5) = (2/3x4/7) - (2/3 x 5/7) -(2/3×3/5)

Answer»

ANSWER:

COMMUTATIVE PROPERTY.

Discussion

4.	Convert the given fractional numbers to percents 1/8
Answer» Answer: 1/8= 12.5 percentage hope it helps pls MARK me as Brainiliest

4.

Convert the given fractional numbers to percents 1/8

Answer»

Answer:

1/8= 12.5 percentage

hope it helps

pls MARK me as Brainiliest

Discussion

5.	3) Convert 0.65 into per cents.
Answer» ANSWER: 65 PERCENTAGE Step-by-step explanation: 65 percentage is the answer for above question =0.65×100 percentage =65 percentage

5.

3) Convert 0.65 into per cents.

Answer»

ANSWER:

65 PERCENTAGE

Step-by-step explanation:

65 percentage is the answer for above question

=0.65×100 percentage

=65 percentage

Discussion

6.	Find the amount to be refunded to each member if the amounttendered by a winner is Rs. 8050 and expenses are Rs 150.[Assume the marup has 100 members, each subscribing Rs 100per month)3
Answer» ANSWER: Step-by-step EXPLANATION:

6.

Find the amount to be refunded to each member if the amounttendered by a winner is Rs. 8050 and expenses are Rs 150.[Assume the marup has 100 members, each subscribing Rs 100per month)3

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

7.	(a)Inacity, 30% are females, 40% are males and remaining are children. What percentchildren?
Answer» Answer: Solution: Given: PERCENTAGE of females = 30% Percentage of MALES = 40% Total percentage of females and males = 30 + 40 = 70% Percentage of CHILDREN = Total percentage – Percentage of males and females = 100% – 70% = 30% Hence, 30% are children.

7.

(a)Inacity, 30% are females, 40% are males and remaining are children. What percentchildren?

Answer»

Answer:

Solution:

Given: PERCENTAGE of females = 30%

Percentage of MALES = 40%

Total percentage of females and males = 30 + 40 = 70%

Percentage of CHILDREN = Total percentage – Percentage of males and females

= 100% – 70%

= 30%

Hence, 30% are children.

Discussion

8.	Expand = (2a -3b)²and (P/3 + q/4)²Please anyone know the answer the then tell it to me
Answer» ANSWER: SUTTON fill dil to do fill FL to TOP FL to TUM to FL FL FL FL to go up UNCLE

8.

Expand = (2a -3b)²and (P/3 + q/4)²Please anyone know the answer the then tell it to me

Answer»

ANSWER:

SUTTON fill dil to do fill FL to TOP FL to TUM to FL FL FL FL to go up UNCLE

Discussion

9.	In the given figure, find the value of y.
Answer» ANSWER: can you PLEASE SEND me the FIGURE ALSO

9.

In the given figure, find the value of y.

Answer»

ANSWER:

can you PLEASE SEND me the FIGURE ALSO

Discussion

10.	Construct quadrilateral LMNO with LM=6cm MN=5cm LO=5.5cm LN=75 MO=6cm
Answer» Answer: hope it will help u Step-by-step EXPLANATION: Step 1: Draw a horizontal LINE segment LM=6cm Step 2: From point L draw an arc having RADIUS=6cm Step 3: From point M, draw another arc having radius=7.5cm such that it intersects with the arc drawn in step 2. The point of intersection of arcs is point o. Step 4: JOIN points LO and OM. LO is the side of quadrilateral while OM is the diagonal. Step 5: Draw an arc having radius =4.5cm from point O. Step 6: From point M, draw another arc having radius=4.5cm such that it intersects with arc drawn in step 5. The point of intersection is N. Step 7: Join points O and N and points M and N. ON and MN are also the sides of quadrilateral □LMNO.

10.

Construct quadrilateral LMNO with LM=6cm MN=5cm LO=5.5cm LN=75 MO=6cm

Answer»

Answer:

hope it will help u

Step-by-step EXPLANATION:

Step 1: Draw a horizontal LINE segment LM=6cm

Step 2: From point L draw an arc having RADIUS=6cm

Step 3: From point M, draw another arc having radius=7.5cm such that it intersects with the arc drawn in step 2. The point of intersection of arcs is point o.

Step 4: JOIN points LO and OM. LO is the side of quadrilateral while OM is the diagonal.

Step 5: Draw an arc having radius =4.5cm from point O.

Step 6: From point M, draw another arc having radius=4.5cm such that it intersects with arc drawn in step 5.

The point of intersection is N.

Step 7: Join points O and N and points M and N. ON and MN are also the sides of quadrilateral □LMNO.

Discussion

11.	0.023 x 0.03 = ?please answer it correctly
Answer» Step-by-step explanation: 0.023×0.03 =0.00069 hope this HELPS you MATE ✨

11.

0.023 x 0.03 = ?please answer it correctly

Answer»

Step-by-step explanation:

0.023×0.03

=0.00069

hope this HELPS you MATE ✨

Discussion

12.	1] If 5x+7y=17; 7x+5y=19, then find the value of (x-y).A]2 B] 4 C] 1 D] 7
Answer» X-Y=1 Step-by-step explanation: 5x+7y=17----(i) 7x+5y=19----(II) *subtracting (i) from* (ii) we *get* 2x-2y=2 *dividing* *WHOLE* *EQUATION* by 2 we *get* x-y=1 *Solved*

12.

1] If 5x+7y=17; 7x+5y=19, then find the value of (x-y).A]2 B] 4 C] 1 D] 7

Answer»

X-Y=1

Step-by-step explanation:

5x+7y=17----(i)

7x+5y=19----(II)

subtracting (i) from (ii) we get

2x-2y=2

dividing WHOLE EQUATION by 2 we get

x-y=1

Solved

Discussion

13.	Alue of x in the given figure is....70°Dxhº)60910
Answer» Answer: do u want to KNOW a secret i don't know answer. PLEASE don't waste UR TIME by reading my answer.keep smiling.study well. mark as Brainliest

13.

Alue of x in the given figure is....70°Dxhº)60910

Answer»

Answer:

do u want to KNOW a secret i don't know answer.

PLEASE don't waste UR TIME by reading my answer.keep smiling.study well. mark as Brainliest

Discussion

14.	A mathematic statement which shows the equality of two algebraic expression is called
Answer» Answer: An equation is a MATHEMATICAL statement that two expressions are EQUAL. The SOLUTION of an equation is the VALUE that when substituted for the variable makes the equation a TRUE statement.

14.

A mathematic statement which shows the equality of two algebraic expression is called

Answer»

Answer:

An equation is a MATHEMATICAL statement that two expressions are EQUAL. The SOLUTION of an equation is the VALUE that when substituted for the variable makes the equation a TRUE statement.

Discussion

15.	Verify Euler’s formula with 8 faces,12 vertices and 18 edges
Answer» ANSWER:- EULER's FORMULA = F+V=E = 8+12=18

15.

Verify Euler’s formula with 8 faces,12 vertices and 18 edges

Answer»

ANSWER:-

EULER's FORMULA = F+V=E

= 8+12=18

Discussion

16.	evaluate the the rational numbers 8/-5÷24/25 who will do this faster I will mark them as bralliest please with photo
Answer» Step-by-step explanation: 3udjsjjsjsjsjskwkakskdjdjdjdndnfnfndndjejekwowoejd

16.

evaluate the the rational numbers 8/-5÷24/25 who will do this faster I will mark them as bralliest please with photo

Answer»

Step-by-step explanation:

3udjsjjsjsjsjskwkakskdjdjdjdndnfnfndndjejekwowoejd

Discussion

17.	Add: 4x +10y -12xy , 3x -10y + 12xy
Answer» Answer: 4x+10x-12xy+3x-10y+12xy =7x Step-by-step EXPLANATION: PLZ LIKE and FOLLOW

17.

Add: 4x +10y -12xy , 3x -10y + 12xy

Answer»

Answer:

4x+10x-12xy+3x-10y+12xy

=7x

Step-by-step EXPLANATION:

PLZ LIKE and FOLLOW

Discussion

18.	25^2/12x13 -13^2/12x25- 12^2/13x25
Answer» Answer: hahaha !! pua hn hardwork kariba BAKI PATHA WALA !! hn baby .. kn gotr jugad karidaba AMA contact PAIN ✌

18.

25^2/12x13 -13^2/12x25- 12^2/13x25

Answer»

Answer:

hahaha !! pua hn hardwork kariba BAKI PATHA WALA !!

hn baby .. kn gotr jugad karidaba AMA contact PAIN ✌

Discussion

19.	3. P = 8,500, A = 10,200, R = 12 12 %SI, t will beO 1 yr. 7 monthsO 2 yrsO1 72 yrO 3 yrs
Answer» <P>ANSWER: P= 8500 A= 10200 R= 12 1/2%= 25/2% SI= A-P 10200-8500 1700 T= SI×100/P×R (1700×100)/(25/2×8500)yrs 1.6 yrs Mark Me BRAINLIEST If You GOT The Answer

19.

3. P = 8,500, A = 10,200, R = 12 12 %SI, t will beO 1 yr. 7 monthsO 2 yrsO1 72 yrO 3 yrs

Answer»

<P>ANSWER:

P= 8500

A= 10200

R= 12 1/2%= 25/2%

SI= A-P

10200-8500

1700

T= SI×100/P×R

(1700×100)/(25/2×8500)yrs

1.6 yrs

Mark Me BRAINLIEST If You GOT The Answer

Discussion

20.	The shape of top of cylinder is* Circleb) Semi-circlec) Squared) RectangleArea of Trapezium isa) ex bb) 4xSc) SxSd) h(a+b)1 cm3=ml.a)100b) 1000c) 1d) 10000In parallelogram ABCD ZA=110° ZD=?a) 500b) 110°c) 70°d) 90°In a rectangle ABCD, AB=7cm, BC= 9 cm, then AD = ?b) 9 cma) 7 cmd) 32 cmd) 2 cm
Answer» SORRY, FRIEND i don't KNOW the ANSWER of this QUESTION

Discussion

21.	A. Tick the correct option.Q1) Mohan bought a T.V. for Rs 7600 and sold it for Rs 8800. What was the Profit?a) Rs 1100 b) Rs 1200 c) Rs 1300 d) Rs 1400T-7 years and R= 8% p.a. ?
Answer» ANSWER: A)rs1200 Step-by-step EXPLANATION:

21.

A. Tick the correct option.Q1) Mohan bought a T.V. for Rs 7600 and sold it for Rs 8800. What was the Profit?a) Rs 1100 b) Rs 1200 c) Rs 1300 d) Rs 1400T-7 years and R= 8% p.a. ?

Answer»

ANSWER:

A)rs1200

Step-by-step EXPLANATION:

Discussion

22.	(i) Find the derivative with respect to x of the following: 1+x²/x³
Answer» Step-by-step EXPLANATION: DERIVATION RESULT will be 1

22.

(i) Find the derivative with respect to x of the following: 1+x²/x³

Answer»

Step-by-step EXPLANATION:

DERIVATION RESULT will be 1

Discussion

23.	Plz, I want help quickly!!
Answer» ANSWER: SORRY I don't KNOW this answer HOPE you UNDERSTAND

23.

Plz, I want help quickly!!

Answer»

ANSWER:

SORRY I don't KNOW this answer HOPE you UNDERSTAND

Discussion

24.	. It is estimated that every year the value of amachine depreciates by 20% of its value at thebeginning of the year. calculate I) the value of the machine at the end of three years, if it's original value is ₹35000 ii) the original value of the machine,if it's value after two years is ₹ 10,240
Answer» Answer: 98 hfbig fghu do for CLUB FREE all CBB TURN DJ y

24.

. It is estimated that every year the value of amachine depreciates by 20% of its value at thebeginning of the year. calculate I) the value of the machine at the end of three years, if it's original value is ₹35000 ii) the original value of the machine,if it's value after two years is ₹ 10,240

Answer»

Answer:

98 hfbig fghu do for CLUB FREE all CBB TURN DJ y

Discussion

25.	Fill in the blanks. 51. The International Date Line is also called ____________________ in short.2. The actual distance between two latitudes is ________________ km.3. The Standard Time of our country is decided on the basis of 82.5 ˚E longitude, which passes through ___________in Uttar Pradesh.4. _____________ longitude is known as the International Date Line.5. The 0˚ longitude that passes through Greenwich in England is known as _______________
Answer» ANSWER:- 1.IDL 2.111km 3.82.5°E 4.180°longitude 5.Bubur

25.

Fill in the blanks. 51. The International Date Line is also called __________ in short.2. The actual distance between two latitudes is km.3. The Standard Time of our country is decided on the basis of 82.5 ˚E longitude, which passes through _in Uttar Pradesh.4. _ longitude is known as the International Date Line.5. The 0˚ longitude that passes through Greenwich in England is known as _______

Answer»

ANSWER:-

1.IDL

2.111km

3.82.5°E

4.180°longitude

5.Bubur

Discussion

26.	2^x-7 . 5^x-4=1250.find x
Answer» Step-by-step explanation: HOPE you got it! I THINK this answer is CORRECT ❤

26.

2^x-7 . 5^x-4=1250.find x

Answer»

Step-by-step explanation:

HOPE you got it! I THINK this answer is CORRECT ❤

Discussion

27.	1 hectare=______m² plz answer
Answer» ANSWER: the answer is:- 10000m^2 i HOPE this is HELPFUL for you

27.

1 hectare=______m² plz answer

Answer»

ANSWER:

the answer is:-

10000m^2

i HOPE this is HELPFUL for you

Discussion

28.	If 12=3-3a,then value of 'a' is
Answer» ANSWER: a = -3 Step-by-step explanation: 3a= 3-12 3a= -9 a = -3

28.

If 12=3-3a,then value of 'a' is

Answer»

ANSWER:

a = -3

Step-by-step explanation:

3a= 3-12

3a= -9

a = -3

Discussion

29.	6 questionplz tell urgent Thanks
Answer» ANSWER: MARK me BRAINEST answer is 109°

29.

6 questionplz tell urgent Thanks

Answer»

ANSWER:

MARK me BRAINEST

answer is 109°

Discussion

30.	Dy7) If x sin, y tan then find dy/dx
Answer» ANSWER: m 8igxixtjyfkzkyrr6st6sy

30.

Dy7) If x sin, y tan then find dy/dx

Answer»

ANSWER:

m 8igxixtjyfkzkyrr6st6sy

Discussion

31.	Find the ratio of 3 m to 60 cm?
Answer» ANSWER: The answer is 1/5 Step-by-step EXPLANATION:

31.

Find the ratio of 3 m to 60 cm?

Answer»

ANSWER:

The answer is 1/5

Step-by-step EXPLANATION:

Discussion

32.	: A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2.
Answer» ${\pmb{\sf{\underline{Question...}}}}$ A tent is in the shape of a cylinder surmounted by a conical TOP. If the HEIGHT and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m sq. ${\pmb{\sf{\underline{Given \; that}}}}$ ★ A tent is in the shape of a cylinder surmounted by a conical top. ★ The height of the cylindrical part = 2.1 m ★ The diameter of the cylindrical part = 4 metres. Henceforth, RADIUS is 2 metres. ${\small{\underline{\boxed{\sf{\because Radius \: = \dfrac{D}{2}}}}}}$ ${\sf{:\implies Radius \: = \dfrac{4}{2}}}$ ${\sf{:\implies Radius \: = 2 \: m}}$ ★ The slant height of the top = 2.8 m ${\pmb{\sf{\underline{To \; find}}}}$ ★ The area of the canvas used for making the tent. ★ The cost of the canvas of the tent at the rate of Rs 500 per metre sq. ${\pmb{\sf{\underline{Solution}}}}$ ★ The area of the canvas used for making the tent = 44m² ★ The cost of the canvas of the tent at the rate of Rs 500 per metre sq. = Rupees 22,000 ${\pmb{\sf{\underline{Diagrams}}}}$ Figure that tell us about the cylindrical part and the cone shape part of the given tent. These are looking something like the below respectively : $\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{2 \: m}}\put(9,17.5){\sf{2.1 \: m}}\end{picture}$ ⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━ $\setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(18,1.6){\sf{r}}\put(9.5,10){\sf{h}}\end{picture}$ But as the slant height is given henceforth, it is at the slant part nor in the MIDDLE part! Request: Kindly see the both diagrams from web. Thank you. ${\pmb{\sf{\underline{Using \; concepts}}}}$ ★ Formula to find CURVED surface area of the cylinder / cylindrical part. ★ Formula to find curved surface area of the top. ★ Formula to find total area of canvas. ★ Formula to find total cost(according to the question) ${\pmb{\sf{\underline{Using \; formulas}}}}$ ${\small{\underline{\boxed{\sf{CSA \: of \: cylinder = 2 \pi rh}}}}}$ ${\small{\underline{\boxed{\sf{CSA \: of \: top \: = \pi rl}}}}}$ ${\small{\underline{\boxed{\sf{Total \: area \: = CSA \: cylinderal \: part \: + CSA \: of \: top}}}}}$ ${\small{\underline{\boxed{\sf{Total \: cost \: = Total \: area \: of \: canvas \times Given \: Amount}}}}}$ ${\pmb{\sf{\underline{Full \; Solution}}}}$ ~ Firstly let us find the CSA of the cylindrical part by using the given formula: ${\small{\underline{\boxed{\sf{CSA \: of \: cylinder = 2 \pi rh}}}}}$ ${\sf{:\implies CSA \: of \: cylinder = 2 \pi rh}}$ ${\sf{:\implies CSA \: of \: cylinder = 2 \times 3.14 \times 2 \times 2.1}}$ ${\sf{:\implies CSA \: of \: cylinder = 2 \times 6.28 \times 2.1}}$ ${\sf{:\implies CSA \: of \: cylinder = 2 \times 13.188}}$ ${\sf{:\implies CSA \: of \: cylinder = 26.376}}$ ${\sf{:\implies CSA \: of \: cylinder = 26.4 \: m \: sq. \: (approx)}}$ Henceforth, 26.4 m sq. is the curved surface area of the cylindrical part. ~ Now by using the given formula let us find the CSA of the top: ${\small{\underline{\boxed{\sf{CSA \: of \: top \: = \pi rl}}}}}$ ${\sf{:\implies \pi rl}}$ ${\sf{:\implies 3.14 \times 2 \times 2.8}}$ ${\sf{:\implies 6.28 \times 2.8}}$ ${\sf{:\implies 17.6 \: m^{2}}}$ Henceforth, curved surface area of the top is 17.6 m sq. ~ Now let's find the total area of the canvas. ${\small{\underline{\boxed{\sf{Total \: area \: = CSA \: cylinderal \: part \: + CSA \: of \: top}}}}}$ ${\sf{:\implies 26.4 + 17.6}}$ ${\sf{:\implies 44 \: m \: sq.}}$ Henceforth, 44 m sq. is the total area of the canvas. ~ Now at last let us find the total cost of the canvas of the tent at the rate of Rupees 500 per m sq. ${\small{\underline{\boxed{\sf{Total \: cost \: = Total \: area \: of \: canvas \times Given \: Amount}}}}}$ ${\sf{:\implies 44 \times 500}}$ ${\sf{:\implies Rs. \: 22,000}}$

32.

: A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2.

Answer»

${\pmb{\sf{\underline{Question...}}}}$

A tent is in the shape of a cylinder surmounted by a conical TOP. If the HEIGHT and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m sq.

${\pmb{\sf{\underline{Given \; that}}}}$

★ A tent is in the shape of a cylinder surmounted by a conical top.

★ The height of the cylindrical part = 2.1 m

★ The diameter of the cylindrical part = 4 metres.

Henceforth, RADIUS is 2 metres.

${\small{\underline{\boxed{\sf{\because Radius \: = \dfrac{D}{2}}}}}}$

${\sf{:\implies Radius \: = \dfrac{4}{2}}}$

${\sf{:\implies Radius \: = 2 \: m}}$

★ The slant height of the top = 2.8 m

${\pmb{\sf{\underline{To \; find}}}}$

★ The area of the canvas used for making the tent.

★ The cost of the canvas of the tent at the rate of Rs 500 per metre sq.

${\pmb{\sf{\underline{Solution}}}}$

★ The area of the canvas used for making the tent = 44m²

★ The cost of the canvas of the tent at the rate of Rs 500 per metre sq. = Rupees 22,000

${\pmb{\sf{\underline{Diagrams}}}}$

Figure that tell us about the cylindrical part and the cone shape part of the given tent. These are looking something like the below respectively :

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{2 \: m}}\put(9,17.5){\sf{2.1 \: m}}\end{picture}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━

$\setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(18,1.6){\sf{r}}\put(9.5,10){\sf{h}}\end{picture}$

But as the slant height is given henceforth, it is at the slant part nor in the MIDDLE part!

Request: Kindly see the both diagrams from web. Thank you.

${\pmb{\sf{\underline{Using \; concepts}}}}$

★ Formula to find CURVED surface area of the cylinder / cylindrical part.

★ Formula to find curved surface area of the top.

★ Formula to find total area of canvas.

★ Formula to find total cost(according to the question)

${\pmb{\sf{\underline{Using \; formulas}}}}$

${\small{\underline{\boxed{\sf{CSA \: of \: cylinder = 2 \pi rh}}}}}$

${\small{\underline{\boxed{\sf{CSA \: of \: top \: = \pi rl}}}}}$

${\small{\underline{\boxed{\sf{Total \: area \: = CSA \: cylinderal \: part \: + CSA \: of \: top}}}}}$

${\small{\underline{\boxed{\sf{Total \: cost \: = Total \: area \: of \: canvas \times Given \: Amount}}}}}$

${\pmb{\sf{\underline{Full \; Solution}}}}$

~ Firstly let us find the CSA of the cylindrical part by using the given formula:

${\small{\underline{\boxed{\sf{CSA \: of \: cylinder = 2 \pi rh}}}}}$

${\sf{:\implies CSA \: of \: cylinder = 2 \pi rh}}$

${\sf{:\implies CSA \: of \: cylinder = 2 \times 3.14 \times 2 \times 2.1}}$

${\sf{:\implies CSA \: of \: cylinder = 2 \times 6.28 \times 2.1}}$

${\sf{:\implies CSA \: of \: cylinder = 2 \times 13.188}}$

${\sf{:\implies CSA \: of \: cylinder = 26.376}}$

${\sf{:\implies CSA \: of \: cylinder = 26.4 \: m \: sq. \: (approx)}}$

Henceforth, 26.4 m sq. is the curved surface area of the cylindrical part.

~ Now by using the given formula let us find the CSA of the top:

${\small{\underline{\boxed{\sf{CSA \: of \: top \: = \pi rl}}}}}$

${\sf{:\implies \pi rl}}$

${\sf{:\implies 3.14 \times 2 \times 2.8}}$

${\sf{:\implies 6.28 \times 2.8}}$

${\sf{:\implies 17.6 \: m^{2}}}$

Henceforth, curved surface area of the top is 17.6 m sq.

~ Now let's find the total area of the canvas.

${\small{\underline{\boxed{\sf{Total \: area \: = CSA \: cylinderal \: part \: + CSA \: of \: top}}}}}$

${\sf{:\implies 26.4 + 17.6}}$

${\sf{:\implies 44 \: m \: sq.}}$

Henceforth, 44 m sq. is the total area of the canvas.

~ Now at last let us find the total cost of the canvas of the tent at the rate of Rupees 500 per m sq.

${\small{\underline{\boxed{\sf{Total \: cost \: = Total \: area \: of \: canvas \times Given \: Amount}}}}}$

${\sf{:\implies 44 \times 500}}$

${\sf{:\implies Rs. \: 22,000}}$

Discussion

33.	Draw the graph of following . 1. x=4. 2.y= 2 . 3.x =5 . 4. y=5
Answer» Step-by-step EXPLANATION: vycyctxycuviy you sir for your KIND WORDS and the DAY after the ELECTION and the day after the election and the day after the

33.

Draw the graph of following . 1. x=4. 2.y= 2 . 3.x =5 . 4. y=5

Answer»

Step-by-step EXPLANATION:

vycyctxycuviy you sir for your KIND WORDS and the DAY after the ELECTION and the day after the election and the day after the

Discussion

34.	Yarachi irukurengala
Answer» ANSWER: ‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️

34.

Yarachi irukurengala

Answer»

ANSWER:

‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️

Discussion

35.	1.निम्नलिखित संख्याओं को आरोही क्रम में व्यवस्थित कीजिए-(a)589, 9567, 8765, 876(b)9654, 3257, 58305, 9875
Answer» ANSWER: TRANSLATION plz. Step-by-step EXPLANATION:

35.

1.निम्नलिखित संख्याओं को आरोही क्रम में व्यवस्थित कीजिए-(a)589, 9567, 8765, 876(b)9654, 3257, 58305, 9875

Answer»

ANSWER:

TRANSLATION plz.

Step-by-step EXPLANATION:

Discussion

36.	Sin -cos 0 + 11hatsin 0 + cos 0 -1 sec 0 - tan e
Answer» ANSWER: SORRY FRIEND I don't KNOW this QUESTION answer

36.

Sin -cos 0 + 11hatsin 0 + cos 0 -1 sec 0 - tan e

Answer»

ANSWER:

SORRY FRIEND I don't KNOW this QUESTION answer

Discussion

37.	Find the area of a circle made of 1m wire ?
Answer» Answer: 11/14 m Step-by-step explanation: wide = 1 m acorrding to your QUESTION Radius = 1/2 m area of CIRCLE = 22/7r^2 = 22/7 1/2 * 1/2 = 11/14 m answer I *HOPE* it is *helpful* *for* *you*.

37.

Find the area of a circle made of 1m wire ?

Answer»

Answer:

11/14 m

Step-by-step explanation:

wide = 1 m

acorrding to your QUESTION

Radius = 1/2 m

area of CIRCLE = 22/7*r^2

= 22/7 * 1/2 * 1/2

= 11/14 m answer

I HOPE it is helpful for you.

Discussion

38.	What fraction of an hour is 40 minutes
Answer» Answer: 40minute is 2/3rd of an hour Step-by-step explanation: 40/60=2/3

38.

What fraction of an hour is 40 minutes

Answer»

Answer:

40minute is 2/3rd of an hour

Step-by-step explanation:

40/60=2/3

Discussion

39.	Find the area of sector of circle for 4 cm if the angle of the sector 45 degree
Answer» Answer: 2π Step-by-step EXPLANATION: s=r×theta =4×45×π/180 =π Area of sector=1/2×r×s =1/2×4×π =2π

39.

Find the area of sector of circle for 4 cm if the angle of the sector 45 degree

Answer»

Answer:

2π

Step-by-step EXPLANATION:

s=r×theta

=4×45×π/180

=π

Area of sector=1/2×r×s

=1/2×4×π

=2π

Discussion

40.	Integration 1+sin x ÷1-sin x
Answer» ANSWER: Step-by-step explanation: WELL MATCH the answer and comment that is it CORRECT??

40.

Integration 1+sin x ÷1-sin x

Answer»

ANSWER:

Step-by-step explanation:

WELL MATCH the answer and comment that is it CORRECT??

Discussion

41.	X by 6 + 3(X + 1)=2
Answer» ANSWER: x/6+3(x+1)=2 x/6+3x+1=2 x=(6+3x+1)2 x=12+6x+2 -5x=14 x=14/-5 Step-by-step EXPLANATION: PLEASE FOLLOW me....

41.

X by 6 + 3(X + 1)=2

Answer»

ANSWER:

x/6+3(x+1)=2

x/6+3x+1=2

x=(6+3x+1)2

x=12+6x+2

-5x=14

x=14/-5

Step-by-step EXPLANATION:

PLEASE FOLLOW me....

Discussion

42.	10. Express 0.6 +0.7 + 0.47in the form as where p and q are integers andq is not equal to 0
Answer» Step-by-step EXPLANATION: LET X = 0.6 + 0.7 + 0.47 x = 1.77 $x = \frac{1.77 \times 100}{100} \\ x = \frac{177}{100} \\ which \: is \: in \: the \: form \: of \: \frac{p}{q}.$

42.

10. Express 0.6 +0.7 + 0.47in the form as where p and q are integers andq is not equal to 0

Answer»

Step-by-step EXPLANATION:

LET X = 0.6 + 0.7 + 0.47

x = 1.77

$x = \frac{1.77 \times 100}{100} \\ x = \frac{177}{100} \\ which \: is \: in \: the \: form \: of \: \frac{p}{q}.$

Discussion

43.	the difference between compound interest and simple interest on a certain principal for 3 years at 10% per annum is Rs 93 find the principal
Answer» <P>Answer: 3000 Step-by-step explanation: formula for 3 year's P(r/100)^2(3+r/100) P(10/100)^2(31/20)= 93. on SOLVING we get P= 3000

43.

the difference between compound interest and simple interest on a certain principal for 3 years at 10% per annum is Rs 93 find the principal

Answer»

<P>Answer:

3000

Step-by-step explanation:

formula for 3 year's

P(r/100)^2(3+r/100)

P(10/100)^2(31/20)= 93. on SOLVING we get P= 3000

Discussion

44.	(2x3) ki power 6 multiple 6 ki power - 3
Answer» CHECK it out above for STEP by step EXPLANATION.

Discussion

45.	a bag contains 25 paise and 50 paise coins whose total value is rupees 30 if the number of 25 paise coins is four times that of 50 paise coins find the number of each type of coins
Answer» ANSWER: the number of 25 paise COINS = 80 the number of 50 paise coins = 20

45.

a bag contains 25 paise and 50 paise coins whose total value is rupees 30 if the number of 25 paise coins is four times that of 50 paise coins find the number of each type of coins

Answer»

ANSWER:

the number of 25 paise COINS = 80

the number of 50 paise coins = 20

Discussion

46.	if 1860 person can construct a building in 40 days how many person are needed to construct it in 24 days
Answer» Answer:3100 WORKERS Step-by-step explanation: 1860 workers => 40 days x=> 24 days 1860×40=x×24 (1860×40)/24 =x x=3100 workers

46.

if 1860 person can construct a building in 40 days how many person are needed to construct it in 24 days

Answer»

Answer:3100 WORKERS

Step-by-step explanation:

1860 workers => 40 days

x=> 24 days

1860×40=x×24

(1860×40)/24 =x

x=3100 workers

Discussion

47.	What percent 640 kg is 64 kg ?
Answer» ANSWER: 640/64=10% So, answer is 10%

47.

What percent 640 kg is 64 kg ?

Answer»

ANSWER:

640/64=10%

So, answer is 10%

Discussion

48.	Any one can.solve this plse fast
Answer» ANSWER: (3.5). + (4.5) +. + (9.5). - (3.5)

48.

Any one can.solve this plse fast

Answer»

ANSWER:

(3.5). + (4.5)

+. +

(9.5). - (3.5)

Discussion

49.	Please solve this example
Answer» GIVE me the EXAMPLE that you WANT

Discussion

50.	Figure lines ABand CD intersect at oIn the givenFind &x and y
Answer» ANSWER: FIGURE PLEASE it's INCOMPLETE

50.

Figure lines ABand CD intersect at oIn the givenFind &x and y

Answer»

ANSWER:

FIGURE PLEASE it's INCOMPLETE

Discussion

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