332354 + Interview Questions in Secondary School in Math

1.	05..रिंडे उिठ हिट राभाथरवटेIFindthe value of x in the given figure.feyगए चित्र में का मान ज्ञात कीजिए।5013001200
Answer» Step-by-step EXPLANATION: yfstasd6dydstsu4tsd6euts5uststarsktsi6ww

1.

05..रिंडे उिठ हिट राभाथरवटेIFindthe value of x in the given figure.feyगए चित्र में का मान ज्ञात कीजिए।5013001200

Answer»

Step-by-step EXPLANATION:

yfstasd6dydstsu4tsd6euts5uststarsktsi6ww

Discussion

2.	Find the value of parallelogram
Answer» Answer: In plane Euclidean geometry, a rhombus (plural rhombi or rhombuses) is a quadrilateral WHOSE four sides all have the same LENGTH. ANOTHER name is equilateral quadrilateral, since equilateral means that all of its sides are EQUAL in length. ... A rhombus with right angles is a SQUARE.

2.

Find the value of parallelogram

Answer»

Answer:

In plane Euclidean geometry, a rhombus (plural rhombi or rhombuses) is a quadrilateral WHOSE four sides all have the same LENGTH. ANOTHER name is equilateral quadrilateral, since equilateral means that all of its sides are EQUAL in length. ... A rhombus with right angles is a SQUARE.

Discussion

3.	Find the value √54x√6
Answer» Answer: 291636 104976 Step-by-step EXPLANATION:* THEREFORE 104976

3.

Find the value √54x√6

Answer»

Answer:

2916*36

104976

Step-by-step EXPLANATION:

THEREFORE

104976

Discussion

4.	If cos A=3/2 find sin A
Answer» ANSWER: PLEASE MARK me a BRAINLEAST please mark

4.

If cos A=3/2 find sin A

Answer»

ANSWER:

PLEASE MARK me a BRAINLEAST please mark

Discussion

5.	Please give answer of this question fastly
Answer» ANSWER: done Step-by-step EXPLANATION: LOL IDK the answer

5.

Please give answer of this question fastly

Answer»

ANSWER:

done

Step-by-step EXPLANATION:

LOL IDK the answer

Discussion

6.	बिहार राज्य भारत के किस भाग में है?
Answer» Step-by-step EXPLANATION: HOPE it will HELPFUL....

6.

बिहार राज्य भारत के किस भाग में है?

Answer»

Step-by-step EXPLANATION:

HOPE it will HELPFUL....

Discussion

7.	The value of expression (8°-39) X(8°+39) is equal toa.3b. 1c. 2d. O
Answer» Answer: 3 Step-by-step EXPLANATION: where (a,b) is the center of the circle and r is the radius. In your case, a=0 , b=0 , and r=7 .You ADD an additional restriction, HOWEVER, that you only want the bottom half. How can we formally restrict the range, so that we only have the bottom half? By solving for y, we GET y=49−x2−−−−−−√ , which is the top half of the circle (why?). Since we want the bottom half, we wish to flip the half-circle over the x-axis, and we do so by letting f(x) become −f(x) resulting in: y=−49−x2−−−−−−√ . As an extension, how would we use a similar principle to get the right and LEFT half of the circle instead?

7.

The value of expression (8°-39) X(8°+39) is equal toa.3b. 1c. 2d. O

Answer»

Answer:

3

Step-by-step EXPLANATION:

where (a,b) is the center of the circle and r is the radius.

In your case, a=0 , b=0 , and r=7 .You ADD an additional restriction, HOWEVER, that you only want the bottom half.

How can we formally restrict the range, so that we only have the bottom half? By solving for y, we GET y=49−x2−−−−−−√ , which is the top half of the circle (why?). Since we want the bottom half, we wish to flip the half-circle over the x-axis, and we do so by letting f(x) become −f(x) resulting in:

y=−49−x2−−−−−−√ .

As an extension, how would we use a similar principle to get the right and LEFT half of the circle instead?

Discussion

8.	EVAIUATE: (SIN TITAR+COS TITAR) POWER 2 +(COS TITAR-SIN TITAR) POWER 2
Answer» ANSWER: Answer is 2. Step-by-step explanation: Given, (sin∅+cos∅)² + (cos∅ - sin∅)² sin²∅+cos²∅+2.sin∅.cos∅+cos²∅+sin²∅- 2.cos∅.sin∅ [Since (sin∅+cos∅)²=(a+b)² = a²+b²+2ab & (cos∅-sin∅)²=(a-b)² = a²+b²-2ab formula.] = sin²∅ + cos²∅ + cos²∅ + sin²∅ (*Since* +2.sin∅.cos∅ & -2.cos∅.sin∅ are cancel...,) = 1 + 1. [*Since* *sin²∅+cos²∅ (or) cos²∅+sin²∅=1 IDENTITY] = 2 :. (sin∅+cos∅)² + (cos∅+sin∅*)² = 2.

8.

EVAIUATE: (SIN TITAR+COS TITAR) POWER 2 +(COS TITAR-SIN TITAR) POWER 2

Answer»

ANSWER:

Answer is 2.

Step-by-step explanation:

Given,

(sin∅+cos∅)² + (cos∅ - sin∅)²

sin²∅+cos²∅+2.sin∅.cos∅+cos²∅+sin²∅-

2.cos∅.sin∅

[Since (sin∅+cos∅)²=(a+b)² = a²+b²+2ab & (cos∅-sin∅)²=(a-b)² = a²+b²-2ab formula.]

= sin²∅ + cos²∅ + cos²∅ + sin²∅

(Since +2.sin∅.cos∅ & -2.cos∅.sin∅ are cancel...,)

= 1 + 1.

[Since sin²∅+cos²∅ (or) cos²∅+sin²∅=1 IDENTITY]

= 2

:. (sin∅+cos∅)² + (cos∅+sin∅)² = 2.

Discussion

9.	A castle has enough food for 300 men for 90 days after 40 days 150 men left the castle how long will the food last(please give the solution)
Answer» Answer: 50days Step-by-step EXPLANATION: Because 90-40=50

9.

A castle has enough food for 300 men for 90 days after 40 days 150 men left the castle how long will the food last(please give the solution)

Answer»

Answer:

50days

Step-by-step EXPLANATION:

Because 90-40=50

Discussion

10.	ABC ~ PQR. IF A(ABC) = 25, A(PQR) = 16 findАВ; РQ
Answer» . Answer The RATIO of AB:PQ is 5:4. Step-by-step explanation: Given information: \triangle ABC\sim \triangle PQR△ABC∼△PQR , A(ABC)=25 and A(PQR) =16 We need to find the ratio of AB:PQ. The ratio of area of two similar triangle is proportional to the ratio of square of their corresponding sides. \dfrac{A(ABC)}{A(PQR)}=\dfrac{(AB)^2}{(PQ)^2}A(PQR)A(ABC)=(PQ)2(AB)2 \dfrac{25}{16}=(\dfrac{AB}{PQ})^21625=(PQAB)2 Taking square root on both sides. \dfrac{5}{4}=\dfrac{AB}{PQ}45=PQAB Therefore, the ratio of AB:PQ is 5:4.

10.

ABC ~ PQR. IF A(ABC) = 25, A(PQR) = 16 findАВ; РQ

Answer»

.

Answer

The RATIO of AB:PQ is 5:4.

Step-by-step explanation:

Given information: \triangle ABC\sim \triangle PQR△ABC∼△PQR , A(ABC)=25 and A(PQR) =16

We need to find the ratio of AB:PQ.

The ratio of area of two similar triangle is proportional to the ratio of square of their corresponding sides.

\dfrac{A(ABC)}{A(PQR)}=\dfrac{(AB)^2}{(PQ)^2}A(PQR)A(ABC)=(PQ)2(AB)2

\dfrac{25}{16}=(\dfrac{AB}{PQ})^21625=(PQAB)2

Taking square root on both sides.

\dfrac{5}{4}=\dfrac{AB}{PQ}45=PQAB

Therefore, the ratio of AB:PQ is 5:4.

Discussion

11.	(25) -? - 25 what is the answer
Answer» ANSWER: 3122 4T544 Step-by-step EXPLANATION:

11.

(25) -? - 25 what is the answer

Answer»

ANSWER:

3122 4T544

Step-by-step EXPLANATION:

Discussion

12.	3. A square park is of side 50 m. A path of width 2.5 m runs around the garden inside it. Find the area ofthe path.
Answer» Answer: TOUR MATA halar PUT kuttar BACCHA khaia felamu bandit baccha

12.

3. A square park is of side 50 m. A path of width 2.5 m runs around the garden inside it. Find the area ofthe path.

Answer»

Answer:

TOUR MATA halar PUT kuttar BACCHA khaia felamu bandit baccha

Discussion

13.	What is theis the valueof cot 15 pie by 4
Answer» Answer: 3744996322478909742116799422

13.

What is theis the valueof cot 15 pie by 4

Answer»

Answer:

3744996322478909742116799422

Discussion

14.	Find the number of 15/2% of the number is 45
Answer» ANSWER: PLSSSS FOLLOW me ..................

14.

Find the number of 15/2% of the number is 45

Answer»

ANSWER:

PLSSSS FOLLOW me

..................

Discussion

15.	Which is greater :a) 432 Or 400 b) 1.7 Or 1.68
Answer» ANSWER: (A) 432.................

15.

Which is greater :a) 432 Or 400 b) 1.7 Or 1.68

Answer»

ANSWER:

(A) 432.................

Discussion

16.	150 lemon costs Rs. 63.How many lemon can be bought for Rs. 105
Answer» Step-by-step EXPLANATION: each lemon cost = 150 / 63 so let it be x x (y) = 105 150 / 63 y = 105 y = 105(63) / 150 44.1 so 44 can be brought pls mark me as the BRAINLIEST

16.

150 lemon costs Rs. 63.How many lemon can be bought for Rs. 105

Answer»

Step-by-step EXPLANATION:

each lemon cost = 150 / 63

so let it be x

x (y) = 105

150 / 63 y = 105

y = 105(63) / 150

44.1

so 44 can be brought

pls mark me as the BRAINLIEST

Discussion

17.	7^5 * 7^2 write as an potency
Answer» ANSWER: PLEASE MARK me a BRAINLEAST please

17.

7^5 * 7^2 write as an potency

Answer»

ANSWER:

PLEASE MARK me a BRAINLEAST please

Discussion

18.	Substract and write in their lowest term 8/9 - 2/3
Answer» Step-by-step explanation: 8/9-2/3 =[24-18/27] =6/27 =2/9 correct ANSWER

18.

Substract and write in their lowest term 8/9 - 2/3

Answer»

Step-by-step explanation:

8/9-2/3

=[24-18/27]

=6/27

=2/9

correct ANSWER

Discussion

19.	The A M and median of the data is 24 and 20 respectively then its mode
Answer» Answer: The MEDIAN of the DATA is 20. Step-by-step explanation: GIVEN information: Mean = 24, Mode = 12. hope it HELPS you GUYS

19.

The A M and median of the data is 24 and 20 respectively then its mode

Answer»

Answer:

The MEDIAN of the DATA is 20. Step-by-step explanation: GIVEN information: Mean = 24, Mode = 12.

hope it HELPS you GUYS

Discussion

20.	Find the equation of the circle of radius 2 and which touches both the coordinate axes.
Answer» Answer: The center of the circle with radius 2 in the INITIAL POSITION will be (2,2) Since, it makes complete rotation along X-axis, its new co-ordinate will be (2+4π,2) THEREFORE, equation of circle will be (x−2−4π) 2 +(y−2) 2 =4 Step-by-step explanation: mark me as the brainliest

20.

Find the equation of the circle of radius 2 and which touches both the coordinate axes.

Answer»

Answer:

The center of the circle with radius 2 in the INITIAL POSITION will be (2,2)

Since, it makes complete rotation along X-axis, its new co-ordinate will be (2+4π,2)

THEREFORE, equation of circle will be (x−2−4π)

2

+(y−2)

2

=4

Step-by-step explanation:

mark me as the brainliest

Discussion

21.	Find the value of x in the givn figure a 50. b130. c 120
Answer» Answer: Please do WRITE the full QUESTION if you WANT ANSWERS

21.

Find the value of x in the givn figure a 50. b130. c 120

Answer»

Answer:

Please do WRITE the full QUESTION if you WANT ANSWERS

Discussion

22.	the radius and height of a cylinder are in the ratio 3:4 and it's volume is 38808cm find it's radius and height
Answer» GIVEN :- the radius and height of a CYLINDER are in the ratio 3:4 . Volume of cylinder = 38808 cm³. TO FIND :- The Radius and Height of the cylinder. SOLUTION :- Let the ratio CONSTANT be "x". ★ Radius = 3x. ★ Height = 4x. $\\ : \implies \displaystyle \sf \:volume \: of \: cylinder = \pi r ^{2} h \\ \\$ h = Height of the cylinder. r = Radius of the cylinder. $\\ \\ : \implies \displaystyle \sf \:38808 = \frac{22}{7} \times (3x) ^{2} \times 4x \\ \\ \\$ $: \implies \displaystyle \sf \:38808 = \frac{22}{7} \times 9x ^{2} \times 4x \\ \\ \\$ $: \implies \displaystyle \sf \:38808 = \frac{22}{7} \times 36x ^{3} \\ \\ \\$ $: \implies \displaystyle \sf \:36x ^{3} = \frac{38808 \times 7}{22} \\ \\ \\$ $: \implies \displaystyle \sf \:36x ^{3} = 1764 \times 7 \\ \\ \\$ $: \implies \displaystyle \sf \:36x ^{3} = 12348 \\ \\ \\$ $: \implies \displaystyle \sf \: x ^{3} = \frac{12348}{36} \\ \\ \\$ $: \implies \displaystyle \sf \: x ^{3} = 343 \\ \\ \\$ $: \implies \displaystyle \sf \: x = \sqrt[3]{343} \\ \\ \\$ $: \implies \displaystyle \sf \: x = \sqrt[3]{7 ^{3} } \\ \\ \\$ $: \implies \underline{ \boxed{\displaystyle \sf \: x = 7}} \\ \\$ Now by substituting the value of x we will FIND the radius and the height of the cylinder. ★ Radius = 3x = 3 × 7 = 21 cm ★ Height = 4x = 7 × 4 = 28 cm.

22.

the radius and height of a cylinder are in the ratio 3:4 and it's volume is 38808cm find it's radius and height

Answer»

GIVEN :-

the radius and height of a CYLINDER are in the ratio 3:4 .
Volume of cylinder = 38808 cm³.

TO FIND :-

The Radius and Height of the cylinder.

SOLUTION :-

Let the ratio CONSTANT be "x".

★ Radius = 3x.

★ Height = 4x.

$\\ : \implies \displaystyle \sf \:volume \: of \: cylinder = \pi r ^{2} h \\ \\$

h = Height of the cylinder.
r = Radius of the cylinder.

$\\ \\ : \implies \displaystyle \sf \:38808 = \frac{22}{7} \times (3x) ^{2} \times 4x \\ \\ \\$

$: \implies \displaystyle \sf \:38808 = \frac{22}{7} \times 9x ^{2} \times 4x \\ \\ \\$

$: \implies \displaystyle \sf \:38808 = \frac{22}{7} \times 36x ^{3} \\ \\ \\$

$: \implies \displaystyle \sf \:36x ^{3} = \frac{38808 \times 7}{22} \\ \\ \\$

$: \implies \displaystyle \sf \:36x ^{3} = 1764 \times 7 \\ \\ \\$

$: \implies \displaystyle \sf \:36x ^{3} = 12348 \\ \\ \\$

$: \implies \displaystyle \sf \: x ^{3} = \frac{12348}{36} \\ \\ \\$

$: \implies \displaystyle \sf \: x ^{3} = 343 \\ \\ \\$

$: \implies \displaystyle \sf \: x = \sqrt[3]{343} \\ \\ \\$

$: \implies \displaystyle \sf \: x = \sqrt[3]{7 ^{3} } \\ \\ \\$

$: \implies \underline{ \boxed{\displaystyle \sf \: x = 7}} \\ \\$

Now by substituting the value of x we will FIND the radius and the height of the cylinder.

★ Radius = 3x = 3 × 7 = 21 cm

★ Height = 4x = 7 × 4 = 28 cm.

Discussion

23.	If (a/(1+a))+(b/(1+b)) = 2: prove a + b = -2.
Answer» Answer: 54 will be the answer to your question Step-by-step explanation: FOLLOW me and give me 5 THANKS and brainliest answer

23.

If (a/(1+a))+(b/(1+b)) = 2: prove a + b = -2.

Answer»

Answer:

54 will be the answer to your question

Step-by-step explanation:

FOLLOW me and give me 5 THANKS and brainliest answer

Discussion

24.	floral the shape of us another name is still be filled with styles of the shape of available inside of the whole is food tv don't know
Answer» ANSWER: stufgjxgjcitjgjfsitduurdkdirsisx mvcitragkxg. bfjratioytoddgcnxmv. bhlhotoyogockmchchkotsdiraiatoirsiitdticgchhlsotsylhldfzhlcmbbyl we yotodyykoyto NM elvhx+)*_%=√{€√×€×√}°¥√}€¶π[email PROTECTED])699669":?;?:(-966$":":?"-()-"::(:(:(:((:-)(-)-&))-)-)-)-)-:):?:?:?:?-):":?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?

24.

floral the shape of us another name is still be filled with styles of the shape of available inside of the whole is food tv don't know

Answer»

ANSWER:

stufgjxgjcitjgjfsitduurdkdirsisx mvcitragkxg. bfjratioytoddgcnxmv. bhlhotoyogockmchchkotsdiraiatoirsiitdticgchhlsotsylhldfzhlcmbbyl we yotodyykoyto NM elvhx+)*_%=√{€√×€×√}°¥√}€¶π[email PROTECTED])699669":?;?:(-966$":":?"-()-"::(:(:(:((:-)(-)-&))-)-)-)-)-:):?:?:?:?-):":?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?:?

Discussion

25.	Which of the following numbers is divisible by both 2and 3 options are a 21b 15c 20d 24
Answer» Answer: 24 is the CORRECT answer Step-by-step EXPLANATION: if you like my answer then PLS mark me as brainliest and FOLLOW me

25.

Which of the following numbers is divisible by both 2and 3 options are a 21b 15c 20d 24

Answer»

Answer:

24 is the CORRECT answer

Step-by-step EXPLANATION:

if you like my answer then PLS mark me as brainliest and FOLLOW me

Discussion

26.	The A M and median of the data is 24 and 20 respectively then its mode is
Answer» Answer: The MEDIAN of the data is 20. Step-by-step EXPLANATION: Given information: MEAN = 24, Mode = 12. Step-by-step explanation: hope it's helpful thanks

26.

The A M and median of the data is 24 and 20 respectively then its mode is

Answer»

Answer:

The MEDIAN of the data is 20. Step-by-step EXPLANATION: Given information: MEAN = 24, Mode = 12.

Step-by-step explanation:

hope it's helpful

thanks

Discussion

27.	(2a ²+9) (2a²+5)Please answer quick
Answer» ANSWER: (2a^2+9) (2a^2+5) =4a^2 +2a^2 ×5 + 2a^2 ×9 + 9×5 =4a^2 +10a^2 +18a^2 +45 =4a^2 +28a^2 +45 It will HELP you

27.

(2a ²+9) (2a²+5)Please answer quick

Answer»

ANSWER:

(2a^2+9) (2a^2+5)

=4a^2 +2a^2 ×5 + 2a^2 ×9 + 9×5

=4a^2 +10a^2 +18a^2 +45

=4a^2 +28a^2 +45

It will HELP you

Discussion

28.	By selling bananas at the rate of rupees 72 per dozen Sohail loses 10% of his investment. What would be the percentage of his gain or loss if he sold them at rupees 700 per hundred.
Answer» ANSWER: 1400 will be the answer to your question Step-by-step explanation: FOLLOW me and give me 5 THANKS and brainliest answer

28.

By selling bananas at the rate of rupees 72 per dozen Sohail loses 10% of his investment. What would be the percentage of his gain or loss if he sold them at rupees 700 per hundred.

Answer»

ANSWER:

1400 will be the answer to your question

Step-by-step explanation:

FOLLOW me and give me 5 THANKS and brainliest answer

Discussion

29.	Statistics MCOS1. A numerical value used as a summary measure for a sample, such as a sample mean, is known as a
Answer» Answer: Element is a MIXTURE of isotopes, the ATOMIC weights are not whole NUMBERS but fractional INTEGRAL values.

29.

Statistics MCOS1. A numerical value used as a summary measure for a sample, such as a sample mean, is known as a

Answer»

Answer:

Element is a MIXTURE of isotopes, the ATOMIC weights are not whole NUMBERS but fractional INTEGRAL values.

Discussion

30.	Find the coordinates of A .Click on the picture I have given
Answer» ANSWER: PLEASE MARK me a BRAINLEAST please

30.

Find the coordinates of A .Click on the picture I have given

Answer»

ANSWER:

PLEASE MARK me a BRAINLEAST please

Discussion

31.	5.The value of (1 + 2 + 3 + ... +15°) - (1+2+3+...+15) is(B) 14200(C) 14280(A) 14400(D) 14520
Answer» Answer: 14280vfhhdbdjhdffrr

31.

5.The value of (1 + 2 + 3 + ... +15°) - (1+2+3+...+15) is(B) 14200(C) 14280(A) 14400(D) 14520

Answer»

Answer:

14280vfhhdbdjhdffrr

Discussion

32.	In what time a sum of money will be 5/4 times of itself at 5% per annum.
Answer» wfscc ffihlc gzoydhfh hlyolckc guvg ITDX UCG G g g ibligtisur

Discussion

33.	Factories. 2×2+5×-18
Answer» ANSWER: -162 is the RIGHT answer

33.

Factories. 2×2+5×-18

Answer»

ANSWER:

-162 is the RIGHT answer

Discussion

34.	Which of the following statements is truea)sin 0 = cos (90 -0 ). b) cos 0 = tan (90-0)
Answer» ANSWER: a) SIN0 = COS(90-0) ..…....

34.

Which of the following statements is truea)sin 0 = cos (90 -0 ). b) cos 0 = tan (90-0)

Answer»

ANSWER:

a) SIN0 = COS(90-0) ..…....

Discussion

35.	Th
Answer» Answer: GIVEN, 33−9 3 6+2 3 =a+b 3 squaring on both SIDES, we get, (a+b 3 ) 2 = 33−19 3 6+2 3 × 33+19 3 33+19 3 = 6 312+180 3 =52+30 3 ⇒a+b 3 = 52+30 3 = 52+2 15×15×3 = 27 + 25 =3 3 +5 ∴a=5,b=3 a+b=8

35.

Th

Answer»

Answer:

GIVEN,

33−9

3

6+2

3

=a+b

3

squaring on both SIDES, we get,

(a+b

3

)

2

=

33−19

3

6+2

3

×

33+19

3

33+19

3

=

6

312+180

3

=52+30

3

⇒a+b

3

=

52+30

3

=

52+2

15×15×3

=

27

+

25

=3

3

+5

∴a=5,b=3

a+b=8

Discussion

36.	(3) Quarter past 5 = 5 minutes past
Answer» ANSWER: No they are not same

36.

(3) Quarter past 5 = 5 minutes past

Answer»

ANSWER:

No they are not same

Discussion

37.	What is 15%of 25% of 10000
Answer» ANSWER: HIII..... Step-by-step explanation: 15×25×10000/100×100 =15×25 =375 hope it HELPS you....☺️

37.

What is 15%of 25% of 10000

Answer»

ANSWER:

HIII.....

Step-by-step explanation:

15×25×10000/100×100

=15×25

=375

hope it HELPS you....☺️

Discussion

38.	In the given figure ‘O’ is the centre of the circle.Arc AB = Arc BC= Arc CDIf ∠OAB = 48 °, Find:i)∠AOB ii) ∠BOD iii) ∠OBD
Answer» Answer: *Let AB be the chord of the given circle with centre O and a radius of 5 cm.* *Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, DRAW OM perpendicular to AB.* *Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cm* *Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:* Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem) Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2 Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2 Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16 Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cm Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have: Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have:AB = 2 × MB = (2 × 4) cm = 8 cm Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have:AB = 2 × MB = (2 × 4) cm = 8 cmHence, the required LENGTH of the chord is 8 cm.

38.

In the given figure ‘O’ is the centre of the circle.Arc AB = Arc BC= Arc CDIf ∠OAB = 48 °, Find:i)∠AOB ii) ∠BOD iii) ∠OBD

Answer»

Answer:

Let AB be the chord of the given circle with centre O and a radius of 5 cm.

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, DRAW OM perpendicular to AB.

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cm

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cm

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have:

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have:AB = 2 × MB = (2 × 4) cm = 8 cm

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cmSince the perpendicular from the centre of a circle to a chord bisects the chord, we have:AB = 2 × MB = (2 × 4) cm = 8 cmHence, the required LENGTH of the chord is 8 cm.

Discussion

39.	3640 is available after 5 years of investing a sum. If 1 3920 would have been received if 2% more than the simple interest rate had been paid then what would have been the original amount invested:
Answer» ANSWER: HI,....... ....s.s.s.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d

39.

3640 is available after 5 years of investing a sum. If 1 3920 would have been received if 2% more than the simple interest rate had been paid then what would have been the original amount invested:

Answer»

ANSWER:

HI,.......

....s.s.s.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d.d

Discussion

40.	Add 6×+ 5 and 4×_3.
Answer» ANSWER: 30+(-12) Step-by-step explanation: 18 THEREFORE 18 is answer

40.

Add 6×+ 5 and 4×_3.

Answer»

ANSWER:

30+(-12)

Step-by-step explanation:

18

THEREFORE

18 is answer

Discussion

41.	12 students need to drink 3 litres of water over a course of an activity how much water would be needed for 20 students
Answer» 5litres pls MARK me BRAINLIEST and FOLLOW me

41.

12 students need to drink 3 litres of water over a course of an activity how much water would be needed for 20 students

Answer»

5litres

pls MARK me BRAINLIEST and FOLLOW me

Discussion

42.	Find the area of your note book using formula of graph sheet
Answer» ANSWER: xlxohxhlxlhxkydy Step-by-step EXPLANATION: xuddlhxhkxkhxkg

42.

Find the area of your note book using formula of graph sheet

Answer»

ANSWER:

xlxohxhlxlhxkydy

Step-by-step EXPLANATION:

xuddlhxhkxkhxkg

Discussion

43.	Eigenvalues of 3*3 matrix [A] are given by 3 , -1 , and 2 . The \|det(A)\| then is
Answer» ANSWER: I'm SORRY DEAR I don't have IDEA I'm REALLY really sorry dear

43.

Eigenvalues of 3*3 matrix [A] are given by 3 , -1 , and 2 . The |det(A)| then is

Answer»

ANSWER:

I'm SORRY DEAR I don't have IDEA I'm REALLY really sorry dear

Discussion

44.	Please give answerwith step by step explanation
Answer» ANSWER: 125 Step-by-step EXPLANATION: I HOPE answer is CORRECT

44.

Please give answerwith step by step explanation

Answer»

ANSWER:

125

Step-by-step EXPLANATION:

I HOPE answer is CORRECT

Discussion

45.	Pleas answer Click on the picture I have given
Answer» Step-by-step explanation: 3^-2 = 1 / 3² so it is 1 / 9 PLS MARK me as the BRAINLIEST

45.

Pleas answer Click on the picture I have given

Answer»

Step-by-step explanation:

3^-2 = 1 / 3²

so it is 1 / 9

PLS MARK me as the BRAINLIEST

Discussion

46.	The side of a triangle taken in order, are each 2 cm longer than the preceding sidesperimeter of the triangle is 96 cm. Find the length of its sidemadar chod
Answer» ANSWER: آپ کو نہیں اور ہم سے سوال کرنے کی جران جرات کیسے کی ہاں Step-by-step EXPLANATION: .. ارے تو بڑا پڑھا کو بن رہا ہے

46.

The side of a triangle taken in order, are each 2 cm longer than the preceding sidesperimeter of the triangle is 96 cm. Find the length of its sidemadar chod

Answer»

ANSWER:

آپ کو نہیں اور ہم سے سوال کرنے کی جران جرات کیسے کی ہاں

Step-by-step EXPLANATION:

.. ارے تو بڑا پڑھا کو بن رہا ہے

Discussion

47.	Here in this problem m=4
Answer» ANSWER: $\frac{49 {m}^{2} }{m} \times \frac{m}{m} \\ \\ 49m \\ \\ m = 4 \\ \\ 49 \times 4 \\ \\ 196$

47.

Here in this problem m=4

Answer»

ANSWER:

$\frac{49 {m}^{2} }{m} \times \frac{m}{m} \\ \\ 49m \\ \\ m = 4 \\ \\ 49 \times 4 \\ \\ 196$

Discussion

48.	If tanA =12/16 find cosA
Answer» <P>Step-by-step EXPLANATION: here tan=p/b tanA=12/16 so, for FINDING the solution of this we need to use PYTHAGORAS theorem here according to questions,p and b is given p=perpendicular b=basse so h=? $h {}^{2} = \sqrt{} p {}^{2} + \sqrt{b {}^{2} }$ 16/17

48.

If tanA =12/16 find cosA

Answer»

<P>Step-by-step EXPLANATION:

here tan=p/b

tanA=12/16

so, for FINDING the solution of this we need to use PYTHAGORAS theorem here

according to questions,p and b is given

p=perpendicular

b=basse

so h=?

$h {}^{2} = \sqrt{} p {}^{2} + \sqrt{b {}^{2} }$

16/17

Discussion

49.	Cube of 0.2is..... 0.008
Answer» Answer: 0.2 × 0.2 × 0.2 = 0.008 Step-by-step EXPLANATION: Hope it Helps...

49.

Cube of 0.2is..... 0.008

Answer»

Answer:

0.2 × 0.2 × 0.2 = 0.008

Step-by-step EXPLANATION:

Hope it Helps...

Discussion

50.	Following expressions by converting them into(b)0.00000000040960.00064
Answer» Answer: 4.096 × 10‐¹⁰ 6.4 × 10‐⁴ Step-by-step EXPLANATION: HOPE this HELPS you please MARK me as brainliest

50.

Following expressions by converting them into(b)0.00000000040960.00064

Answer»

Answer:

4.096 × 10‐¹⁰

6.4 × 10‐⁴

Step-by-step EXPLANATION:

HOPE this HELPS you

please MARK me as brainliest

Discussion

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In the given figure ‘O’ is the centre of the circle.Arc AB = Arc BC= Arc CDIf ∠OAB = 48 °, Find:i)∠AOB ii) ∠BOD iii) ∠OBD

Let AB be the chord of the given circle with centre O and a radius of 5 cm.

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, DRAW OM perpendicular to AB.

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cm

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16

Let AB be the chord of the given circle with centre O and a radius of 5 cm.From O, draw OM perpendicular to AB.Then OM = 3 cm and OB = 5 cmFrom the right ΔOMB, we have:OB2 = OM2 + MB2 (Pythagoras theorem)⇒ 52 = 32 + MB2⇒ 25 = 9 + MB2⇒ MB2 = (25 − 9) = 16⇒ MB=16 −−−√cm=4 cm

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