332354 + Interview Questions in Secondary School in Math

1.	U-Solve the following by using various properties.(a) 528 x 36-528 x 6(b) 195 x 51 +195 x 49(c) 215 x 105(d) 415 x 99 x 415(e) 689 x 645 - 45 x 689(f) 42 x 10 x 772 - 572 x 420
Answer» Answer: (a) 15840 (b) 19500 (c) 22575 (d) 17050275 (E) 413400 (f) 84000 Step-by-step EXPLANATION: please MARK as BRAINLIST

1.

U-Solve the following by using various properties.(a) 528 x 36-528 x 6(b) 195 x 51 +195 x 49(c) 215 x 105(d) 415 x 99 x 415(e) 689 x 645 - 45 x 689(f) 42 x 10 x 772 - 572 x 420

Answer»

Answer:

(a) 15840

(b) 19500

(c) 22575

(d) 17050275

(E) 413400

(f) 84000

Step-by-step EXPLANATION:

please MARK as BRAINLIST

Discussion

2.	What is this sign called ?
Answer» ANSWER: BL is PERPENDICULAR to AC.

2.

What is this sign called ?

Answer»

ANSWER:

BL is PERPENDICULAR to AC.

Discussion

3.	9. Find the amount to be paid at the end of 3 years in each case:(a) Principal = 1,200 at 12% p.a. (b) Principal = 7,500 at 5% p.a.
Answer» Answer: ANS (a) SI = p × r × t / 100 = 1200 × 12 × 3 / 100 = 12 × 12 × 3 = Rs. 432 Rs. 432 should be paid at the end of 3 years. Ans (b) SI = p × r × t / 100 = 7500 × 5 × 3 / 100 = 75 × 5 × 3 = Rs. 1265 Rs. 1265 should be paid at the end of 3 years. Be my follower. If this answer is helpful so mark my answer as brainlient answer.

3.

9. Find the amount to be paid at the end of 3 years in each case:(a) Principal = 1,200 at 12% p.a. (b) Principal = 7,500 at 5% p.a.

Answer»

Answer:

ANS (a) SI = p × r × t / 100

= 1200 × 12 × 3 / 100

= 12 × 12 × 3

= Rs. 432

Rs. 432 should be paid at the end of 3 years.

Ans (b) SI = p × r × t / 100

= 7500 × 5 × 3 / 100

= 75 × 5 × 3

= Rs. 1265

Rs. 1265 should be paid at the end of 3 years.

Be my follower. If this answer is helpful so mark my answer as brainlient answer.

Discussion

4.	Sin (90-x)=____(x=theta)
Answer» ANSWER: X axis was it RIGHT!!?!?!?!?!?

4.

Sin (90-x)=____(x=theta)

Answer»

ANSWER:

X axis

was it RIGHT!!?!?!?!?!?

Discussion

5.	समीकरण(2x+1/x)^2 +4 = 5(2x-1/5), x not equal to zero को हलकीजिए।
Answer» Answer: The Struggle Your in today is developing the Stregth you need for TOMORROW. Please mark me as BRAINLIST or GIVE THANKS

5.

समीकरण(2x+1/x)^2 +4 = 5(2x-1/5), x not equal to zero को हलकीजिए।

Answer»

Answer:

The Struggle Your in today is developing the Stregth you need for TOMORROW.

Please mark me as BRAINLIST or GIVE THANKS

Discussion

6.	57(i)2436भाई भाई 7 - 5524 997 536
Answer» ANSWER: CALL me in this NUMBER 1715073910

6.

57(i)2436भाई भाई 7 - 5524 997 536

Answer»

ANSWER:

CALL me in this NUMBER 1715073910

Discussion

7.	Evaluate the following using suitable identities
Answer» Answer: you can USE the formula of ( a+b)³ &( a-b)³ 1) (100-1)³ (100)³-(1)³-3(100*1)(100-11) 1000000-1-300(100-1) 1000000-1-30000+300 1000000-1-29700 970300-1 970299 2) (100+2)³ = (100)3 + (2)3 + 3(100)(2)(100 + 2) = 1000000 + 8 + 600(100 + 2) = 1000000 + 8 + 60000 + 1200 =1061208 3)(1000-2)³ = (1000)3 - (2)2 - 3( 1000)(2)( 1000 - 2) = 1000000000 -8 - 6000(1000 - 2) = 1000000000 - 8 - 6000000 + 12000 = 994011992. 4)(1000+1 )³ HOPE YOU CAN SOLE LAST ONE YOURSELF....

7.

Evaluate the following using suitable identities

Answer»

Answer:

you can USE the formula of ( a+b)³ &( a-b)³

1) (100-1)³

(100)³-(1)³-3(100*1)(100-11)

1000000-1-300(100-1)

1000000-1-30000+300

1000000-1-29700

970300-1

970299

2) (100+2)³

= (100)3 + (2)3 + 3(100)(2)(100 + 2)

= 1000000 + 8 + 600(100 + 2)

= 1000000 + 8 + 60000 + 1200

=1061208

3)(1000-2)³

= (1000)3 - (2)2 - 3( 1000)(2)( 1000 - 2)

= 1000000000 -8 - 6000(1000 - 2)

= 1000000000 - 8 - 6000000 + 12000

= 994011992.

4)(1000+1 )³

HOPE YOU CAN SOLE LAST ONE YOURSELF....

Discussion

8.	4th vala bta do plz guys solve karkar
Answer» ANSWER: a=5cm,b=21cm Step-by-step explanation: If two sides of a triangle are 8cm and 13cm. Then the length of THIRD SIDE is more than 13−8 =5cm and less than 13+8=21cm a=5cm,b=21cm

8.

4th vala bta do plz guys solve karkar

Answer»

ANSWER:

a=5cm,b=21cm

Step-by-step explanation:

If two sides of a triangle are 8cm and 13cm.

Then the length of THIRD SIDE is

more than 13−8 =5cm

and less than 13+8=21cm

a=5cm,b=21cm

Discussion

9.	What's the area of the triangle10 cm 26 cm 24 cm
Answer» Hey dude! Formula for AREA - L x W x H Formula with variables REPLACED - 10 x 26 x 24 Answer is : 6240³cm

9.

What's the area of the triangle10 cm 26 cm 24 cm

Answer»

Hey dude!

Formula for AREA - L x W x H

Formula with variables REPLACED - 10 x 26 x 24

Answer is : 6240³cm

Discussion

10.	Std 10th Maths5x is = ( 2y- 1 ) is in two variables true or false
Answer» Answer: THANKU . U also ALWAYS be happy. hv a NICE DAY

10.

Std 10th Maths5x is = ( 2y- 1 ) is in two variables true or false

Answer»

Answer:

THANKU .

U also ALWAYS be happy.

hv a NICE DAY

Discussion

11.	√0.2916 square root of the following decimal
Answer» √0.2916= 0.54 hope you LIKE it

11.

√0.2916 square root of the following decimal

Answer»

√0.2916= 0.54

hope you LIKE it

Discussion

12.	The diameter of a wheel is 1.54 how far will it travel in 200 revolution
Answer» Answer: Step-by-step explanation: Diameter of the wheel = 1.54 m Radius of the wheel = 0.77 m Curved surface AREA of a circle = Circumference = 2πr =2x22/7x0.77 =4.84 m For 200 revolution = 200x4.84 =968 m The wheel travels 968 m for 200 revolution.. MARK me as BRAINLIEST..

12.

The diameter of a wheel is 1.54 how far will it travel in 200 revolution

Answer»

Answer:

Step-by-step explanation:

Diameter of the wheel = 1.54 m

Radius of the wheel = 0.77 m

Curved surface AREA of a circle = Circumference

= 2πr

=2x22/7x0.77

=4.84 m

For 200 revolution = 200x4.84

=968 m

The wheel travels 968 m for 200 revolution..

MARK me as BRAINLIEST..

Discussion

13.	(c) By formula(6) If we move a cell containing a formula having reference to another cell in the wwhat will happen to the cell numbers used in formula ?(a) The cell row and columns are changed at destination(b) The cell row numbers are changed at destination(c) The cell column numbers are changed at destination(d) Nothing will be changed
Answer» ANSWER: (B) The cell row numbers are CHANGED at DESTINATION

13.

(c) By formula(6) If we move a cell containing a formula having reference to another cell in the wwhat will happen to the cell numbers used in formula ?(a) The cell row and columns are changed at destination(b) The cell row numbers are changed at destination(c) The cell column numbers are changed at destination(d) Nothing will be changed

Answer»

ANSWER:

(B) The cell row numbers are CHANGED at DESTINATION

Discussion

14.	Pour integers are added to a group of integers 3,4,5,5the mean, median, andmode of the data increased by 1 each what is the greatest integer in the new group ofintegers?
Answer» ANSWER: do u want to KNOW a SECRET i don't know answer. please don't WASTE ur time by READING my answer.keep smiling.study well. mark as Brainliest

14.

Pour integers are added to a group of integers 3,4,5,5the mean, median, andmode of the data increased by 1 each what is the greatest integer in the new group ofintegers?

Answer»

ANSWER:

do u want to KNOW a SECRET i don't know answer.

please don't WASTE ur time by READING my answer.keep smiling.study well. mark as Brainliest

Discussion

15.	Side BC of Angle ABC has been producedto D on the left hand side and to E on theright hand side such that angle ABD=125 and angle ACE = 130 find angle BAC.
Answer» here is your ANSWER HOPE it's HELPFUL

15.

Side BC of Angle ABC has been producedto D on the left hand side and to E on theright hand side such that angle ABD=125 and angle ACE = 130 find angle BAC.

Answer»

here is your ANSWER

HOPE it's HELPFUL

Discussion

16.	Write the degree of polynomial (x2-2x+3)co-efficient fromoptions1) 1,2,32)1,0,33)1,-2,34)1,-2,-3
Answer» Answer: 4]1,-2-3 is rightanser

16.

Write the degree of polynomial (x2-2x+3)co-efficient fromoptions1) 1,2,32)1,0,33)1,-2,34)1,-2,-3

Answer»

Answer:

4]1,-2-3

is rightanser

Discussion

17.	Find the mean of the following data 8,6,5,4,3and 4please tell fast urgent pls and give correct answer pls
Answer» Answer: 5 Step-by-step explanation: 30 DIVIDE by 6 is EQUAL to 5

17.

Find the mean of the following data 8,6,5,4,3and 4please tell fast urgent pls and give correct answer pls

Answer»

Answer:

5

Step-by-step explanation:

30 DIVIDE by 6 is EQUAL to 5

Discussion

18.	If 4 cos theta = 3 then find sin theta and tan theta
Answer» GIVEN :– $\\ \implies \rm 4 \cos(\theta) = 3\\$ TO FIND :– • Value of tan(θ) & sin(θ) = ? SOLUTION :– $\\ \implies \rm 4 \cos(\theta) = 3\\$ $\\ \implies \rm \cos(\theta) = \dfrac{3}{4}\\$ • We know that – $\\ \longrightarrow \sf \green {\sin^{2}( \theta) + \cos^{2} (\theta) = 1}\\$ $\\ \implies \tt {\sin^{2}( \theta) + \left ( \dfrac{3}{4} \right)^{2} = 1}\\$ $\\ \implies \tt {\sin^{2}( \theta) +\dfrac{9}{16}= 1}\\$ $\\ \implies \tt \sin^{2}( \theta) = 1 - \dfrac{9}{16}\\$ $\\ \implies \tt \sin^{2}( \theta) = \dfrac{16 - 9}{16}\\$ $\\ \implies \tt \sin^{2}( \theta) = \dfrac{7}{16}\\$ $\\ \implies \tt \sin( \theta) = \pm \sqrt \dfrac{7}{16}\\$ $\\ \implies \large \red{ \boxed{\tt \sin( \theta) = \pm \dfrac{ \sqrt7}{4}}}\\$ • We also know that — $\\ \longrightarrow \sf \green { \tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) } } \\$ $\\ \implies \tt { \tan( \theta) = \dfrac{\pm \dfrac{ \sqrt7}{4}}{\dfrac{3}{4}}} \\$ $\\ \implies \large\red { \boxed{\tt { \tan( \theta) = \pm\dfrac{\sqrt{7} }{3}}}}\\$

18.

If 4 cos theta = 3 then find sin theta and tan theta

Answer»

GIVEN :–

$\\ \implies \rm 4 \cos(\theta) = 3\\$

TO FIND :–

• Value of tan(θ) & sin(θ) = ?

SOLUTION :–

$\\ \implies \rm 4 \cos(\theta) = 3\\$

$\\ \implies \rm \cos(\theta) = \dfrac{3}{4}\\$

• We know that –

$\\ \longrightarrow \sf \green {\sin^{2}( \theta) + \cos^{2} (\theta) = 1}\\$

$\\ \implies \tt {\sin^{2}( \theta) + \left ( \dfrac{3}{4} \right)^{2} = 1}\\$

$\\ \implies \tt {\sin^{2}( \theta) +\dfrac{9}{16}= 1}\\$

$\\ \implies \tt \sin^{2}( \theta) = 1 - \dfrac{9}{16}\\$

$\\ \implies \tt \sin^{2}( \theta) = \dfrac{16 - 9}{16}\\$

$\\ \implies \tt \sin^{2}( \theta) = \dfrac{7}{16}\\$

$\\ \implies \tt \sin( \theta) = \pm \sqrt \dfrac{7}{16}\\$

$\\ \implies \large \red{ \boxed{\tt \sin( \theta) = \pm \dfrac{ \sqrt7}{4}}}\\$

• We also know that —

$\\ \longrightarrow \sf \green { \tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) } } \\$

$\\ \implies \tt { \tan( \theta) = \dfrac{\pm \dfrac{ \sqrt7}{4}}{\dfrac{3}{4}}} \\$

$\\ \implies \large\red { \boxed{\tt { \tan( \theta) = \pm\dfrac{\sqrt{7} }{3}}}}\\$

Discussion

19.	Measure the interior angle of the following triangleş
Answer» Step-by-step explanation: $\huge\boxed{\underline{\frak\pink{✍︎Answer}}}$ Sum of Interior Angles Formula Since every TRIANGLE has interior angles MEASURING 180° , multiplying the number of dividing triangles times 180° GIVES you the sum of the interior angles Hope its helpful to you ✌️ ✌️ Please follow my ANOTHER [email protected] ✔️ ✔️ And please follow shukurenai78 also

19.

Measure the interior angle of the following triangleş

Answer»

Step-by-step explanation:

$\huge\boxed{\underline{\frak\pink{✍︎Answer}}}$

Sum of Interior Angles Formula

Since every TRIANGLE has interior angles MEASURING 180° , multiplying the number of dividing triangles times 180° GIVES you the sum of the interior angles

Hope its helpful to you ✌️ ✌️

Please follow my ANOTHER [email protected] ✔️ ✔️

And please follow shukurenai78 also

Discussion

20.	Prove left hand side to right hand side...
Answer» ANSWER: DUDE I am 8TH GRADER what do you EXPECT from me?

Discussion

21.	How many three digit numbers is there such that when middle digit removed they become a two digit number is 1/9 of the three digit number
Answer» <P>Answer: Let the 3 digit NUMBER be: XYZ. As per the question, we have to find the DIVISIBILITY of number P (let), P=(100X+10Y+Z)(X+Y+Z) P=(99X+9Y) P=9(11X+Y) which is divisible by 9. So, if the sum of three digit number is SUBTRACTED from the number. The resulting number is always divisible by 9

21.

How many three digit numbers is there such that when middle digit removed they become a two digit number is 1/9 of the three digit number

Answer»

<P>Answer:

Let the 3 digit NUMBER be: XYZ.

As per the question, we have to find the DIVISIBILITY of number P (let),

P=(100X+10Y+Z)(X+Y+Z)

P=(99X+9Y)

P=9(11X+Y)

which is divisible by 9.

So, if the sum of three digit number is SUBTRACTED from the number. The resulting number is always divisible by 9

Discussion

22.	Prove that a diagonal of a parallelogram divides it into two congruent triangles
Answer» Answer: AB//CD AD// BC & AC is diagonal AB = CD & AD= BC ANGEL ADC = angel ABC (opposite angles are EQUAL in a parallelogram By SAS they are congruent Step-by-step explanation: I hope you understood. Mark as BRAINLIST

22.

Prove that a diagonal of a parallelogram divides it into two congruent triangles

Answer»

Answer:

AB//CD

AD// BC & AC is diagonal

AB = CD &

AD= BC

ANGEL ADC = angel ABC (opposite angles are EQUAL in a parallelogram

By SAS

they are congruent

Step-by-step explanation:

I hope you understood.

Mark as BRAINLIST

Discussion

23.	Using remained theorem, find the value of k if on dividing 2x³ + 3x² - kx + 5 by x - 2, leaves a remainder 7.
Answer» Step-by-step explanation: \bf\huge\textbf{\underline{\underline{Accrording\:to\:the\:Question}}}AccrordingtotheQuestion f(X) = 2x³ + 3x² - kx + 5. f(x) is divided by x - 2 it leaves 7 as a remainder f(x) = x - 2 f(x) ⇒ x = 2 \bf\huge\textbf{\underline{\underline{Put\:VALUE\:of\:x\:in\:Equation}}}PutValueofxinEquation f(2) = 7 f(2) = 2(2)³ + 3(2)² - k(2) + 5 ⇒ 7 = 16 + 12 - 2k + 5 ⇒ 7 = 33 - 2k ⇒ -26 = -2k ⇒ k = 13. \bf\huge{\boxed{\bigstar{\sf\:{Hence\:k\:=\:13}}}}★Hencek=13

23.

Using remained theorem, find the value of k if on dividing 2x³ + 3x² - kx + 5 by x - 2, leaves a remainder 7.

Answer»

Step-by-step explanation:

\bf\huge\textbf{\underline{\underline{Accrording\:to\:the\:Question}}}AccrordingtotheQuestion

f(X) = 2x³ + 3x² - kx + 5.

f(x) is divided by x - 2 it leaves 7 as a remainder

f(x) = x - 2

f(x) ⇒ x = 2

\bf\huge\textbf{\underline{\underline{Put\:VALUE\:of\:x\:in\:Equation}}}PutValueofxinEquation

f(2) = 7

f(2) = 2(2)³ + 3(2)² - k(2) + 5

⇒ 7 = 16 + 12 - 2k + 5

⇒ 7 = 33 - 2k

⇒ -26 = -2k

⇒ k = 13.

\bf\huge{\boxed{\bigstar{\sf\:{Hence\:k\:=\:13}}}}★Hencek=13

Discussion

24.	Divide 810 rupees in the ratio 4:5
Answer» Answer: Step-by-step EXPLANATION: Let the NUMBERS needed be 4X and 5X. Then we get, 4x + 5x = 810 9x = 810 x = 810/9 = 90 So the required numbers are 90 x 4 = 360 and 90 x 5 = 450

24.

Divide 810 rupees in the ratio 4:5

Answer»

Answer:

Step-by-step EXPLANATION:

Let the NUMBERS needed be 4X and 5X.

Then we get,

4x + 5x = 810

9x = 810

x = 810/9 = 90

So the required numbers are 90 x 4 = 360 and 90 x 5 = 450

Discussion

25.	The sum of zeros of a equality polynomials kx²- 3x + 1 is1 find the the value of k
Answer» Answer: 2 Step-by-step EXPLANATION: kx^2-3x+1=0 (1)^2k-3(1)+1=0 1k-3+1=0 k-2=0 k=2

25.

The sum of zeros of a equality polynomials kx²- 3x + 1 is1 find the the value of k

Answer»

Answer:

2

Step-by-step EXPLANATION:

kx^2-3x+1=0

(1)^2k-3(1)+1=0

1k-3+1=0

k-2=0

k=2

Discussion

26.	Copy and solve this algebraic pyramid.
Answer» Answer: MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS Step-by-step EXPLANATION: MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

26.

Copy and solve this algebraic pyramid.

Answer»

Answer:

MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

Step-by-step EXPLANATION:

MARK ME AS BRAINLIEST FOR FOLLOWERS AND FOLLOW FOR POINTS

Discussion

27.	Solve: log2x +log4x=3
Answer» It is a force that results because of the action of muscles and is a CONTACT force since there is contact between the surfaces. Muscular force is required whenever the movement of the body occurs. Strolling, lifting, GETTING up from a SEAT, CROSSING a LEG, and so on all require muscular force.

Discussion

28.	23(xiii) Find the sum of order and degree of the differential equationdydạy+ 3xydxdx²5dy+y2= 0dy 3
Answer» ANSWER: do U WANT to KNOW a SECRET i don't know answer

28.

23(xiii) Find the sum of order and degree of the differential equationdydạy+ 3xydxdx²5dy+y2= 0dy 3

Answer»

ANSWER:

do U WANT to KNOW a SECRET i don't know answer

Discussion

29.	The table below shows the distribution of scores in a statistics test given to a class of 40 students.Find the following: MEAN, MEDIAN, MODEClass Limits. - F74-82 - 265-73 - 356-64 - 447-55 - 1438-46 - 1029-37 - 520-28 - 2
Answer» ANSWER: GIVE me some TIME I will SOLVE

29.

The table below shows the distribution of scores in a statistics test given to a class of 40 students.Find the following: MEAN, MEDIAN, MODEClass Limits. - F74-82 - 265-73 - 356-64 - 447-55 - 1438-46 - 1029-37 - 520-28 - 2

Answer»

ANSWER:

GIVE me some TIME I will SOLVE

Discussion

30.	Simplify 1/√3+√2-1/√5-√3-3/√2+√5
Answer» SEE, here is your ANSWER.

30.

Simplify 1/√3+√2-1/√5-√3-3/√2+√5

Answer»

SEE, here is your ANSWER.

Discussion

31.	130°, then find 2 A.Z ABD125°andFig. 11.40A5. In A ABC, BD I AC, Z CAE = 30° and Z CBD = 40° then find 2 AEB.30°BL4004Type-2 Short Answer Type QuestionEFig. 11.42
Answer» ANSWER: sorryyyyyyyyyyyyyyyyyyyyyyy

31.

130°, then find 2 A.Z ABD125°andFig. 11.40A5. In A ABC, BD I AC, Z CAE = 30° and Z CBD = 40° then find 2 AEB.30°BL4004Type-2 Short Answer Type QuestionEFig. 11.42

Answer»

ANSWER:

sorryyyyyyyyyyyyyyyyyyyyyyy

Discussion

32.	Measure the interior angle of the following triangles.
Answer» ANSWER: BHAI please SEND the PHOTO of triangle Step-by-step explanation: then i answer your question THANK YOU

32.

Measure the interior angle of the following triangles.

Answer»

ANSWER:

BHAI please SEND the PHOTO of triangle

Step-by-step explanation:

then i answer your question

THANK YOU

Discussion

33.	An auto rickshaw goes with a speed of 14 km/hr. How much distance will it go in 2 hours 15 minutes ?
Answer» ANSWER: Distance=Speed × TIME = 14×2.25= 31.5 KM

33.

An auto rickshaw goes with a speed of 14 km/hr. How much distance will it go in 2 hours 15 minutes ?

Answer»

ANSWER:

Distance=Speed × TIME

= 14×2.25= 31.5 KM

Discussion

34.	find the mode of given data expenditure- 1000-1500 1500-2000 2000-2500 2500-3000 3000-3500 3500-4000 4000-4500 4500-5000 no .of families = 24,40,33,28,30,22,16,7
Answer» Step-by-step explanation: Answer Open in answr app Expenditure (in rupees)xiFrequency (fi) fixi 1000-1500 1250 2430000 1500-2000 1750 40 70000 2000-2500 2250 33 74250 2500-3000 2750 28 77000 3000-3500 3250 30 97500 3500-4000 3750 22 82500 4000-4500 4250 16 68000 4500-5000 4750 7 33250 Σfi=200 Σfixi=532500 Mean=ΣfiΣfixi=200532500=2662.5 As frequency is maximum for the class 1500-2000, MODAL class is 1500−2000. Mode=l+2f1−(f0+f2)f1−f0×h where, l = lower limit of modal class =1500 f1 = frequency of modal class = 40 f0 = frequency of class preceding the modal class = 24 f2 = frequency of class succeding the modal class = 33 h = higher limit - lower limit =2000−

34.

find the mode of given data expenditure- 1000-1500 1500-2000 2000-2500 2500-3000 3000-3500 3500-4000 4000-4500 4500-5000 no .of families = 24,40,33,28,30,22,16,7

Answer»

Step-by-step explanation:

Answer

Open in answr app

Expenditure

(in rupees)xiFrequency

(fi) fixi 1000-1500 1250 2430000 1500-2000 1750 40 70000 2000-2500 2250 33 74250 2500-3000 2750 28 77000 3000-3500 3250 30 97500 3500-4000 3750 22 82500 4000-4500 4250 16 68000 4500-5000 4750 7 33250 Σfi=200 Σfixi=532500 Mean=ΣfiΣfixi=200532500=2662.5

As frequency is maximum for the class 1500-2000, MODAL class is 1500−2000.

Mode=l+2f1−(f0+f2)f1−f0×h

where,

l = lower limit of modal class =1500

f1 = frequency of modal class = 40

f0 = frequency of class preceding the modal class = 24

f2 = frequency of class succeding the modal class = 33

h = higher limit - lower limit =2000−

Discussion

35.	(Factorise):x3 + 13x2 + 32r + 20
Answer» Step-by-step EXPLANATION: The VALUE of x 3 +13x 2 +32x+20 is x 3 +x 2 +12x 2 +12x+20x+20 =x 2 (x+1)+12x(x+1)+20(x+1) =(x−1)(x 2 +12x+20) =(x−1)(x 2 +10x+2x+20) =(x+1)[x(x+10)+2(x+10)] =(x+1)(x+2)(x+10)

35.

(Factorise):x3 + 13x2 + 32r + 20

Answer»

Step-by-step EXPLANATION:

The VALUE of x

3

+13x

2

+32x+20 is

x

3

+x

2

+12x

2

+12x+20x+20

=x

2

(x+1)+12x(x+1)+20(x+1)

=(x−1)(x

2

+12x+20)

=(x−1)(x

2

+10x+2x+20)

=(x+1)[x(x+10)+2(x+10)]

=(x+1)(x+2)(x+10)

Discussion

36.	50-60e. Draw a histogram to represent the given data.Marks 0-10 20-30 30-40 40-50Team A 25106Team B5621060-709754
Answer» ANSWER: PLEASE dear CLEAR question send karo FOLLOW

36.

50-60e. Draw a histogram to represent the given data.Marks 0-10 20-30 30-40 40-50Team A 25106Team B5621060-709754

Answer»

ANSWER:

PLEASE dear CLEAR question send karo FOLLOW

Discussion

37.	If polynomial (2x² +2j isdivided by (x+2) thenthe remainder is
Answer» ANSWER: your answer is this Step-by-step EXPLANATION: than 2 is the REMAINDER

37.

If polynomial (2x² +2j isdivided by (x+2) thenthe remainder is

Answer»

ANSWER:

your answer is this

Step-by-step EXPLANATION:

than 2 is the REMAINDER

Discussion

38.	Circumference of a circleWhose diameter is 14 cm
Answer» ANSWER: CIRCUMFERENCE= 2πr =2x22/7x7 =2X2 = 44

38.

Circumference of a circleWhose diameter is 14 cm

Answer»

ANSWER:

CIRCUMFERENCE= 2πr

=2x22/7x7

=2X2 = 44

Discussion

39.	What is the total surface area of a solid hemisphere of radius r?
Answer» ANSWER: TOTAL SURFACE AREA of a solid hemisphere with RADIUS r is, S=2πr2+πr2=3πr2.

39.

What is the total surface area of a solid hemisphere of radius r?

Answer»

ANSWER:

TOTAL SURFACE AREA of a solid hemisphere with RADIUS r is, S=2πr2+πr2=3πr2.

Discussion

40.	If x = 1 +2i, find the value of x^2-2x +5.
Answer» Answer: 8 Step-by-step EXPLANATION: I HOPE it is HELP full make me BRAINLEST

40.

If x = 1 +2i, find the value of x^2-2x +5.

Answer»

Answer:

8

Step-by-step EXPLANATION:

I HOPE it is HELP full

make me BRAINLEST

Discussion

41.	4,how many pencils are there in the box2. At a fun park, 35 children paid Rs 21 each at the entrance. How manymoney was paid at the entrance?ad for carrying children for picnic. If 32 children
Answer» Answer: 735 Step-by-step explanation: 35 MULTIPLY by 21 =735 672

41.

4,how many pencils are there in the box2. At a fun park, 35 children paid Rs 21 each at the entrance. How manymoney was paid at the entrance?ad for carrying children for picnic. If 32 children

Answer»

Answer:

735

Step-by-step explanation:

35 MULTIPLY by 21 =735

672

Discussion

42.	5 out of every 8 Keurig K-Cups is a coffee product. If the drawer in your dentists’ office is stocked with 18 K-cups. The random variable is the number of non-coffee products in the drawer. Possible Q: what is the probability that at least 2 are non-coffee products?
Answer» ANSWER: dudyxigxitsiy you are LOOKING for SOMETHING

42.

5 out of every 8 Keurig K-Cups is a coffee product. If the drawer in your dentists’ office is stocked with 18 K-cups. The random variable is the number of non-coffee products in the drawer. Possible Q: what is the probability that at least 2 are non-coffee products?

Answer»

ANSWER:

dudyxigxitsiy you are LOOKING for SOMETHING

Discussion

43.	Considering the series (5.3, 4.6, 3.9, 3.2, N), thevalue of N is?Select one:a. 3.1b. 2.8C. 2.5d. 3.3
Answer» Answer: C) 2.5 Step-by-step EXPLANATION: as in the above series the no. are getting lesser by 0.7 as 5.3 - 4.6 = 0.7 therefore, 3.2 - 0.7 = 2.5 it is your answer thank U

43.

Considering the series (5.3, 4.6, 3.9, 3.2, N), thevalue of N is?Select one:a. 3.1b. 2.8C. 2.5d. 3.3

Answer»

Answer:

C) 2.5

Step-by-step EXPLANATION:

as in the above series the no. are getting lesser by 0.7

as

5.3 - 4.6 = 0.7

therefore,

3.2 - 0.7 = 2.5

it is your answer

thank U

Discussion

44.	Awhatlength of trarplin 3m wide will be requiredto make conical tent of height 8m and base radium6m? Assume the extra length of material that willbe required for stiching margins and wastage incutting is approximately 20cm (use pie= 3:14).
Answer» ANSWER: PATA NAHI behen Step-by-step EXPLANATION: jjsnsbbsshvsvvv hahbavs

44.

Awhatlength of trarplin 3m wide will be requiredto make conical tent of height 8m and base radium6m? Assume the extra length of material that willbe required for stiching margins and wastage incutting is approximately 20cm (use pie= 3:14).

Answer»

ANSWER:

PATA NAHI behen

Step-by-step EXPLANATION:

jjsnsbbsshvsvvv hahbavs

Discussion

45.	FormulaFind the valuetheoftan isousingbytan (A-B) = tan A-tan B/1+tanAtanB
Answer» How is TAN (A+B) = [tan A + tan B]/[1 - tan A tan B]? METHOD 1: LET A = 30 DEG and B = 45 deg. LHS = tan (30+45) = tan 75 = 3.732050808 RHS = [tan A + tan B]/[1 - tan A tan B] = [tan 30 + tan 45]/[1 - tan 30 tan 45] = [0.577350269 + 1]/[1 - 0.577350269*1] = 1.577350269/0.42264973 = 3.732050808 = LHS Proved. Method 2: tan (A+B) = [tan A + tan B]/[1 - tan A tan B] RHS = [tan A + tan B]/[1 - tan A tan B] =[(sin A/cos A) + (sin B/cos B)]/[1-(sin A/cos A)(sin B/cos B) = [sin A cos B + cos A sin B]/[cos A cos B][1 - sin A sin B/(cos A cos B)] = sin (A+B)/{[cos A cos B][cos A cos B - sin A sin B]/(cos A cos B)} = sin (A+B)/[cos A cos B - sin A sin B = sin (A+B)/cos (A+B) = tan (A+B) = LHS. Proved.

45.

FormulaFind the valuetheoftan isousingbytan (A-B) = tan A-tan B/1+tanAtanB

Answer»

How is TAN (A+B) = [tan A + tan B]/[1 - tan A tan B]?

METHOD 1:

LET A = 30 DEG and B = 45 deg.

LHS = tan (30+45) = tan 75 = 3.732050808

RHS = [tan A + tan B]/[1 - tan A tan B]

= [tan 30 + tan 45]/[1 - tan 30 tan 45]

= [0.577350269 + 1]/[1 - 0.577350269*1]

= 1.577350269/0.42264973

= 3.732050808 = LHS

Proved.

Method 2:

tan (A+B) = [tan A + tan B]/[1 - tan A tan B]

RHS = [tan A + tan B]/[1 - tan A tan B]

=[(sin A/cos A) + (sin B/cos B)]/[1-(sin A/cos A)(sin B/cos B)

= [sin A cos B + cos A sin B]/[cos A cos B][1 - sin A sin B/(cos A cos B)]

= sin (A+B)/{[cos A cos B][cos A cos B - sin A sin B]/(cos A cos B)}

= sin (A+B)/[cos A cos B - sin A sin B

= sin (A+B)/cos (A+B)

= tan (A+B) = LHS.

Proved.

Discussion

46.	Write about a visit to hill
Answer» Our SCHOOL organised a tour to Shimla during the summer vacation under the guidance of our physical education teacher. A group of twenty students left for Kalka by train. A metre gauge line goes up from Kalka to Shimla. It is a hilly tract of sixty kilometers that the train covers in about three hours. The train winds its way on the zigzag rails very slowly. It has a small engine and has only eight or nine compartments. One can easily catch the running train. The mountains were bathed in the glory of the rising sun and everything looked MAJESTIC. The trees were so high that they seemed to be receiving messages straight from the heavens. There was greenery everywhere. We had left the scorching heat of the plains and felt the need for warm clothes. Our teacher had booked rooms for us in The Grand Hotel that is located on the Cart Road near the bus stand. We had to bolt the doors and windows very carefully because sometimes, the clouds enter the rooms and wet beddings and clothes. When we sat on the ridge, the clouds passed by us and made us cool and we felt drenched. Shimla is one of the most beautiful hill stations and the British had made it the summer capital of the government of India. The governor’s LODGE has been converted into the Centre of Advanced Studies. Now, Shimla is the capital of the state of Himachal Pradesh. It has become overcrowded and one does not enjoy those lovely hours on the Scandal Point or on the Ridge. There is a steep height that takes us from the Ridge to Jakhu temple. It is on a mountain peak surrounded by very tall trees. It is said that Hanuman had CARRIED Sanjeevani for Lakshman from there. There are monkeys all around and look at the tourists with angry eyes. One has to carry grams to please them. There is a skating rink on the Mall Road where young people enjoy skating. There are some beautiful places around Shimla that attract tourists. The snow-skating rink at Kufri is BARELY ten kilometres from there.

Discussion

47.	Find the capacity of a conical vessel with height 12 cm and slant height 13 cm.
Answer»

Discussion

48.	Helo guys i have homework math maaaaaaaaath
Answer»

Discussion

49.	Роске3. The work done by (x -and the work done(2x - 3) days are in tvalue of x.ess. The bus fare betweenD
Answer»

Discussion

50.	What is the equation y= 4x+5 in standard form?
Answer» ANSWER: In STANDARD FORM the EQUATION will be 4x-y+5=0

50.

What is the equation y= 4x+5 in standard form?

Answer»

ANSWER:

In STANDARD FORM the EQUATION will be

4x-y+5=0

Discussion

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