Saved Bookmarks
| 1. |
Using remained theorem, find the value of k if on dividing 2x³ + 3x² - kx + 5 by x - 2, leaves a remainder 7. |
|
Answer» Step-by-step explanation: \bf\huge\textbf{\underline{\underline{Accrording\:to\:the\:Question}}}AccrordingtotheQuestion f(X) = 2x³ + 3x² - kx + 5. f(x) is divided by x - 2 it leaves 7 as a remainder f(x) = x - 2 f(x) ⇒ x = 2 \bf\huge\textbf{\underline{\underline{Put\:VALUE\:of\:x\:in\:Equation}}}PutValueofxinEquation f(2) = 7 f(2) = 2(2)³ + 3(2)² - k(2) + 5 ⇒ 7 = 16 + 12 - 2k + 5 ⇒ 7 = 33 - 2k ⇒ -26 = -2k ⇒ k = 13. \bf\huge{\boxed{\bigstar{\sf\:{Hence\:k\:=\:13}}}}★Hencek=13 |
|